Derivatives and Rates of Change

The derivative gives an instantaneous rate of change. Polynomial power rules, sums, and the chain rule provide a starting point, but a complete calculus course also needs derivative meaning, graphs, and applications.

2 worked examples and 3 practice questions, with explained answers. No sign-in required.

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A reliable method

  1. Identify how the function is built.
  2. Apply the appropriate derivative rule to each part.
  3. For a nested function multiply by the inner derivative.
  4. Simplify and distinguish the derivative from a numerical derivative value at one input.

Example 1

Differentiate \(f(x)=3 x^{4} - 2 x + 7\) with respect to x.

  1. Identify sums, products, and nested functions before choosing a derivative rule.
  2. Differentiate each additive term, using the power rule and chain rule where needed: \(\frac{d}{d x} 7\) = \(0\), \(\frac{d}{d x} \left(- 2 x\right)\) = \(-2\), \(\frac{d}{d x} 3 x^{4}\) = \(12 x^{3}\).
  3. Add the derivatives and simplify: \(12 x^{3} - 2\). The derivative is a rate function, not the original function value.

Answer: \(12 x^{3} - 2\)

Example 2

Differentiate \(f(x)=\left(2 x + 1\right)^{3}\) with respect to x.

  1. Identify sums, products, and nested functions before choosing a derivative rule.
  2. Differentiate each additive term, using the power rule and chain rule where needed: \(\frac{d}{d x} 1\) = \(0\), \(\frac{d}{d x} 6 x\) = \(6\), \(\frac{d}{d x} 8 x^{3}\) = \(24 x^{2}\), \(\frac{d}{d x} 12 x^{2}\) = \(24 x\).
  3. Add the derivatives and simplify: \(6 \left(2 x + 1\right)^{2}\). The derivative is a rate function, not the original function value.

Answer: \(6 \left(2 x + 1\right)^{2}\)

Common mistakes

  • The power rule lowers the exponent by 1 and multiplies by the old exponent.
  • A chain rule calculation is incomplete without the inner derivative.

Practice without the answer first

  1. Differentiate \(f(x)=5 x^{2} + 4 x - 9\) with respect to x.
  2. Differentiate \(f(x)=x^{5} - 3 x^{3}\) with respect to x.
  3. Differentiate \(f(x)=\left(x^{2} + 1\right)^{2}\) with respect to x.
Answers and step-by-step explanations

Practice 1

  1. Identify sums, products, and nested functions before choosing a derivative rule.
  2. Differentiate each additive term, using the power rule and chain rule where needed: \(\frac{d}{d x} \left(-9\right)\) = \(0\), \(\frac{d}{d x} 4 x\) = \(4\), \(\frac{d}{d x} 5 x^{2}\) = \(10 x\).
  3. Add the derivatives and simplify: \(10 x + 4\). The derivative is a rate function, not the original function value.

Answer: \(10 x + 4\)

Practice 2

  1. Identify sums, products, and nested functions before choosing a derivative rule.
  2. Differentiate each additive term, using the power rule and chain rule where needed: \(\frac{d}{d x} x^{5}\) = \(5 x^{4}\), \(\frac{d}{d x} \left(- 3 x^{3}\right)\) = \(- 9 x^{2}\).
  3. Add the derivatives and simplify: \(x^{2} \left(5 x^{2} - 9\right)\). The derivative is a rate function, not the original function value.

Answer: \(x^{2} \left(5 x^{2} - 9\right)\)

Practice 3

  1. Identify sums, products, and nested functions before choosing a derivative rule.
  2. Differentiate each additive term, using the power rule and chain rule where needed: \(\frac{d}{d x} 1\) = \(0\), \(\frac{d}{d x} x^{4}\) = \(4 x^{3}\), \(\frac{d}{d x} 2 x^{2}\) = \(4 x\).
  3. Add the derivatives and simplify: \(4 x \left(x^{2} + 1\right)\). The derivative is a rate function, not the original function value.

Answer: \(4 x \left(x^{2} + 1\right)\)

These original skill exercises are not official exam questions or a score prediction. Use the coverage notes on your exam hub to choose relevant practice.

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Original Testinar instructional content. Updated November 11, 2026. Editorial standards ยท Report a correction

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