Quantitative Comparisons: Prove the Relationship

A comparison question asks which relationship must hold for every allowed input. One convenient example can disprove a claim of always, but it usually cannot prove that claim.

2 worked examples and 3 practice questions, with explained answers. No sign-in required.

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A reliable method

  1. List the allowed inputs.
  2. Simplify the difference or use a reversible transformation.
  3. Look for counterexamples at negative values, fractions, zero, or boundaries when allowed.
  4. Choose a definite relationship only when it holds throughout the domain.

Example 1

Compare Quantity A = \(x^{2}\) with Quantity B = \(x\). The real input x is positive. Decide: left greater, right greater, equal, or not determined.

  1. Use only the stated input restriction; do not silently assume x is an integer.
  2. Subtract B from A: \(x \left(x - 1\right)\). A positive difference means A is greater; a negative one means B is greater.
  3. Within the allowed domain, possible outcomes are: left is greater, right is greater, equal. Therefore the comparison is not determined by the given information.

Answer: not determined by the given information

Example 2

Compare Quantity A = \(2 x + 3\) with Quantity B = \(2 x + 1\). The real input x is unrestricted. Decide: left greater, right greater, equal, or not determined.

  1. Use only the stated input restriction; do not silently assume x is an integer.
  2. Subtract B from A: \(2\). A positive difference means A is greater; a negative one means B is greater.
  3. Within the allowed domain, possible outcomes are: left is greater. Therefore the comparison is left is greater.

Answer: left is greater

Common mistakes

  • Do not assume a variable is a positive integer.
  • Two different valid outcomes mean the relationship is not determined.

Practice without the answer first

  1. Compare Quantity A = \(x^{2}\) with Quantity B = \(0\). The real input x is nonzero. Decide: left greater, right greater, equal, or not determined.
  2. Compare Quantity A = \(\sqrt{x^{2}}\) with Quantity B = \(x\). The real input x is negative. Decide: left greater, right greater, equal, or not determined.
  3. Compare Quantity A = \(\left(x + 1\right)^{2}\) with Quantity B = \(x^{2} + 2 x + 1\). The real input x is unrestricted. Decide: left greater, right greater, equal, or not determined.
Answers and step-by-step explanations

Practice 1

  1. Use only the stated input restriction; do not silently assume x is an integer.
  2. Subtract B from A: \(x^{2}\). A positive difference means A is greater; a negative one means B is greater.
  3. Within the allowed domain, possible outcomes are: left is greater. Therefore the comparison is left is greater.

Answer: left is greater

Practice 2

  1. Use only the stated input restriction; do not silently assume x is an integer.
  2. Subtract B from A: \(- 2 x\). A positive difference means A is greater; a negative one means B is greater.
  3. Within the allowed domain, possible outcomes are: left is greater. Therefore the comparison is left is greater.

Answer: left is greater

Practice 3

  1. Use only the stated input restriction; do not silently assume x is an integer.
  2. Subtract B from A: \(0\). A positive difference means A is greater; a negative one means B is greater.
  3. Within the allowed domain, possible outcomes are: equal. Therefore the comparison is equal.

Answer: equal

These original skill exercises are not official exam questions or a score prediction. Use the coverage notes on your exam hub to choose relevant practice.

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This is shared skill instruction, not an official question set or a prediction of your exam score. Choose your exam for its coverage notes and provider requirements.

Original Testinar instructional content. Updated November 11, 2026. Editorial standards ยท Report a correction

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