Testinar Grade 3 math

Area by Multiplying Side Lengths

Students will find the area of a rectangle by multiplying whole-number side lengths.

CH06-07 Geometry and Measurement

Directions Solve each problem. Show your reasoning on the page or on separate paper. Check the answer key only after finishing.

A garden is \(7\) feet long and \(5\) feet wide. What is its area?
1. \(12\) sq ft
2. \(35\) sq ft
3. \(24\) sq ft
4. \(70\) sq ft
A rectangular rug is \(6\) meters long and \(4\) meters wide. What is the area of the rug?
1. \(10\) sq m
2. \(24\) sq m
3. \(20\) sq m
4. \(12\) sq m
A classroom floor is shaped like a rectangle with a length of \(9\) feet and a width of \(8\) feet. What is the area of the classroom floor?
1. \(17\) sq ft
2. \(72\) sq ft
3. \(64\) sq ft
4. \(63\) sq ft
What is the area of this rectangle?
1. \(8\) sq in
2. \(15\) sq in
3. \(10\) sq in
4. \(12\) sq in
Sam needs to paint a poster that is \(10\) inches wide and \(8\) inches tall. What is the total area Sam needs to paint?
1. \(36\) sq in
2. \(80\) sq in
3. \(18\) sq in
4. \(90\) sq in
Find the area of the rectangle shown above.
1. \(6\) sq cm
2. \(8\) sq cm
3. \(4\) sq cm
4. \(12\) sq cm
A rectangular tile is \(7\) inches long and \(3\) inches wide. How much area does one tile cover?
1. \(20\) sq in
2. \(28\) sq in
3. \(21\) sq in
4. \(10\) sq in
A rectangular parking spot measures \(6\) meters by \(4\) meters. What is its area?
1. \(10\) sq m
2. \(20\) sq m
3. \(12\) sq m
4. \(24\) sq m

Teacher and parent reference

Answer key and explanations

B. \(35\) sq ft
Area \(=\) length \(\times\) width \(=7\times5=35\) square feet. Choice A (12) is the sum \(7+5\); Choice C (24) is common product error; Choice D (70) is double the area.
B. \(24\) sq m
Area \(=\) length \(\times\) width \(=6\times4=24\) square meters. Choice A (10) is the sum; C (20) is 4×5 miscomputation; D (12) is 6×2.
B. \(72\) sq ft
Area \(=\) length \(\times\) width \(=9\times8=72\) square feet. Choice A (17) is the sum; C (64) is \(8\times8\); D (63) is \(9\times7\).
B. \(15\) sq in
Area \(=\) length \(\times\) width \(=5\times3=15\) square inches. Choice A (8) is the sum; C (10) is \(5\times2\); D (12) is \(4\times3\).
B. \(80\) sq in
Area \(=\) width \(\times\) height \(=10\times8=80\) square inches.
B. \(8\) sq cm
Area \(=\) length \(\times\) width \(=4\times2=8\) square centimeters. Choice A (6) is the sum; C (4) is one dimension; D (12) is \(4\times3\).
C. \(21\) sq in
Area \(=\) length \(\times\) width \(=7\times3=21\) square inches.
D. \(24\) sq m
Area \(=\) length \(\times\) width \(=6\times4=24\) square meters.