What is \(8{,}432-3{,}657\)?
- \(4{,}225\)
- \(5{,}775\)
- \(5{,}225\)
- \(4{,}775\)
Students will fluently add and subtract multi-digit whole numbers and explain how place value supports the algorithm.
What is \(8{,}432-3{,}657\)?
Add: \(5{,}234 + 2{,}145 =\)?
What is \(9{,}000 - 4{,}256\)?
Subtract: \(6{,}320 - 1{,}485 =\)?
Add: \(3{,}456 + 4{,}567 =\)?
What is \(10{,}000 - 5{,}678\)?
Add: \(7{,}285 + 1{,}514 =\)?
Add: \(12{,}345 + 23{,}456 =\)?
Subtract column by column, regrouping as needed. Starting from the ones: we need to regroup the tens and higher places to complete the subtraction. The answer is \(\mathbf{4{,}775}\).
Add from right to left: ones \(4+5=9\), tens \(3+4=7\), hundreds \(2+1=3\), thousands \(5+2=7\). The sum is \(\mathbf{7{,}379}\).
Since we're subtracting from \(9{,}000\), we must regroup across the zeros to subtract in each place. The answer is \(\mathbf{4{,}744}\).
Start in the ones place: \(0 < 5\), so regroup one ten as \(10\) ones. Then subtract from right to left carefully. The answer is \(\mathbf{4{,}835}\).
Add from right to left: ones give \(13\) (write \(3\), carry \(1\)), tens give \(12\) (write \(2\), carry \(1\)), hundreds give \(10\) (write \(0\), carry \(1\)), thousands give \(8\). The sum is \(\mathbf{8{,}023}\).
Subtracting from \(10{,}000\) requires careful regrouping across all the zeros. The answer is \(\mathbf{4{,}322}\).
Add by place value: ones \(5+4=9\), tens \(8+1=9\), hundreds \(2+5=7\), thousands \(7+1=8\). The sum is \(\mathbf{8{,}799}\).
Add from ones: \(5+6=11\) (write \(1\), carry \(1\)), \(4+5+1=10\) (write \(0\), carry \(1\)), \(3+4+1=8\), \(2+3=5\), \(1+2=3\). The sum is \(\mathbf{35{,}801}\).