A rectangle has a length of \(8\) ft and a width of \(5\) ft. What is its area?
- \(13\) sq ft
- \(26\) sq ft
- \(40\) sq ft
- \(45\) sq ft
Students will apply area and perimeter formulas to rectangles in real-world and mathematical problems.
A rectangle has a length of \(8\) ft and a width of \(5\) ft. What is its area?
A rectangle has a length of \(12\) m and a width of \(7\) m. What is its perimeter?
Diego draws a rectangle with a length of \(6\) cm and a width of \(4\) cm. What is the area of his rectangle?
A garden is shaped like a rectangle. It is \(9\) feet long and \(5\) feet wide. How many feet of fencing are needed to go around the garden?
What is the area of a rectangle that is \(10\) inches long and \(3\) inches wide?
A poster is a rectangle with a length of \(11\) inches and a width of \(8\) inches. What is its perimeter?
What is the area of the rectangle shown above?
A room is \(15\) feet long and \(12\) feet wide. What is the area of the floor?
To find area, we multiply length times width: \(8 \times 5 = 40\) sq ft.
Perimeter is the distance around the rectangle. Use the formula \(P = 2\ell + 2w = 2(12) + 2(7) = 24 + 14 = 38\) m.
Multiply length by width: \(6 \times 4 = 24\) sq cm.
To find how much fencing goes around the garden, we calculate perimeter: \(P = 2(9) + 2(5) = 18 + 10 = 28\) ft.
Area \(= \text{length} \times \text{width} = 10 \times 3 = 30\) sq in.
The perimeter of the poster is \(P = 2(11) + 2(8) = 22 + 16 = 38\) in.
From the diagram, length is \(7\) cm and width is \(3\) cm. Area \(= 7 \times 3 = 21\) sq cm.
The floor area is \(15 \times 12 = 180\) sq ft.