Students will solve problems using operations and information from line plots.
The line plot below shows lengths of ribbon pieces, in inches, collected by an art club: The club uses only the pieces longer than \(1\frac{1}{2}\) inches. What is the total length of those pieces?
The line plot shows the lengths (in inches) of ribbons collected by the art club: If the total ribbon length is shared equally among 4 posters, how much ribbon goes on each poster?
The line plot shows lengths of ribbon pieces, in yards: What is the total length of all the ribbon pieces?
The line plot shows the heights (in half-inches) of plant seedlings in a garden: What is the total height of all seedlings in inches?
The line plot shows lengths of ribbon pieces, in inches: What is the total length of the pieces longer than \(1\) inch?
The line plot shows the lengths, in feet, of boards used for a project: What is the total length of all the boards?
The line plot shows distances (in meters) students jumped: What is the range of the data?
Two line plots show ribbon lengths, in yards, used by two teams: How much more ribbon did Team 2 use than Team 1?
The pieces longer than \(1\frac{1}{2}\) inches are one piece of \(1\frac{3}{4}\) inches and one piece of \(2\) inches. Their total length is \(1\frac{3}{4}+2=3\frac{3}{4}\) inches.
Add the ribbon lengths shown by the marks: \((1 \times 3) + (3 \times 2) + (5 \times 3) + (7 \times 1) = 31\) inches. Sharing 31 inches equally among 4 posters gives \(31 \div 4 = 7\frac{3}{4}\) inches per poster.
Add the ribbon lengths shown: \(2(\frac{1}{4})+3(\frac{1}{2})+2(\frac{3}{4})+1+1\frac{1}{4}=5\frac{3}{4}\) yards.
The labels are in half-inches. The total is \((2 \times 4) + (4 \times 2) + (6 \times 2) + (8 \times 1) + (10 \times 1) = 46\) half-inches. Since 2 half-inches make 1 inch, \(46 \div 2 = 23\) inches.
The pieces longer than \(1\) inch are two pieces of \(1\frac{1}{4}\) inches and one piece of \(1\frac{1}{2}\) inches. Their total is \(1\frac{1}{4}+1\frac{1}{4}+1\frac{1}{2}=4\) inches.
Add the board lengths: \(1 + 2(1\frac{1}{4}) + 2(1\frac{1}{2}) + 1\frac{3}{4} + 2 = 9\frac{1}{4}\) feet.
Lowest: 2 m (2 marks), Highest: 5 m (1 mark). Range = \(5 - 2 = 3\) meters.
Team 1 used \(\frac{1}{2}+\frac{1}{2}+\frac{3}{4}+1+1\frac{1}{4}=4\) yards. Team 2 used \(\frac{1}{2}+\frac{3}{4}+\frac{3}{4}+1+1\frac{1}{4}=4\frac{1}{4}\) yards. The difference is \(\frac{1}{4}\) yard.
