Testinar Grade 5 math

Subtracting Fractions with Unlike Denominators

Students will subtract fractions with unlike denominators using equivalent fractions and visual models.

CH04-03 Adding and Subtracting Fractions

Directions Solve each problem. Show your reasoning on the page or on separate paper. Check the answer key only after finishing.

Subtract: \(\frac{7}{9} - \frac{2}{3}\)
1. \(\frac{1}{3}\)
2. \(\frac{5}{9}\)
3. \(\frac{1}{9}\)
4. \(\frac{4}{7}\)
Subtract: \(\frac{5}{6} - \frac{1}{4}\)
1. \(\frac{7}{12}\)
2. \(\frac{4}{2}\)
3. \(\frac{4}{6}\)
4. \(\frac{4}{10}\)
Bar shows 8 parts, 5 shaded. Remove 2 parts. \(\frac{5}{8} - \frac{2}{8} = ?\)
1. \(\frac{3}{8}\)
2. \(\frac{7}{8}\)
3. \(\frac{2}{8}\)
4. \(\frac{5}{16}\)
Subtract: \(\frac{7}{8} - \frac{1}{3}\)
1. \(\frac{6}{5}\)
2. \(\frac{13}{24}\)
3. \(\frac{6}{11}\)
4. \(\frac{5}{24}\)
Recipe needs \(\frac{3}{4}\) cup flour. Maria used \(\frac{1}{6}\) cup. How much more needed?
1. \(\frac{2}{6}\) cups
2. \(\frac{3}{10}\) cups
3. \(\frac{2}{10}\) cups
4. \(\frac{7}{12}\) cups
Number line: Start at \(\frac{9}{10}\). Back by \(\frac{3}{10}\). Where do you land?
1. \(\frac{5}{10}\)
2. \(\frac{6}{10}\)
3. \(\frac{7}{10}\)
4. \(\frac{8}{10}\)
Simplify: \(\frac{9}{12} - \frac{3}{12}\)
1. \(\frac{5}{12}\)
2. \(\frac{2}{3}\)
3. \(\frac{3}{4}\)
4. \(\frac{1}{2}\)
Pizza has 8 slices. Ben eats \(\frac{3}{8}\), sister eats \(\frac{1}{4}\). How much remains?
1. \(\frac{3}{8}\)
2. \(\frac{1}{4}\)
3. \(\frac{5}{8}\)
4. \(\frac{1}{8}\)

Teacher and parent reference

Answer key and explanations

C. \(\frac{1}{9}\)
Use ninths: \(\frac{2}{3}=\frac{6}{9}\). Then \(\frac{7}{9}-\frac{6}{9}=\frac{1}{9}\).
A. \(\frac{7}{12}\)
LCD = 12. \(\frac{5}{6} = \frac{10}{12}\); \(\frac{1}{4} = \frac{3}{12}\). \(\frac{10}{12} - \frac{3}{12} = \frac{7}{12}\).
A. \(\frac{3}{8}\)
Same denominator: \(5 - 2 = 3\) parts remaining. Answer: \(\frac{3}{8}\).
B. \(\frac{13}{24}\)
LCD = 24. \(\frac{7}{8} = \frac{21}{24}\); \(\frac{1}{3} = \frac{8}{24}\). \(\frac{21}{24} - \frac{8}{24} = \frac{13}{24}\).
D. \(\frac{7}{12}\) cups
LCD = 12. \(\frac{3}{4} = \frac{9}{12}\); \(\frac{1}{6} = \frac{2}{12}\). \(\frac{9}{12} - \frac{2}{12} = \frac{7}{12}\).
B. \(\frac{6}{10}\)
\(\frac{9}{10} - \frac{3}{10} = \frac{6}{10}\).
D. \(\frac{1}{2}\)
\(\frac{9}{12} - \frac{3}{12} = \frac{6}{12}\), which simplifies to \(\frac{1}{2}\).
A. \(\frac{3}{8}\)
Together eaten: \(\frac{3}{8} + \frac{2}{8} = \frac{5}{8}\). Remaining: \(1 - \frac{5}{8} = \frac{3}{8}\).