Testinar Grade 6 math

Mean and Median

Students will build Grade 6 mastery of mean and median using models, equations, and test-style reasoning.

CH05-03 Statistics and Probability
Name
Date
Score
____ / 8
Directions Solve each problem. Show your reasoning on the page or on separate paper. Check the answer key only after finishing.
  1. Find the mean of the data set: \(4, 6, 8, 10, 12\).

    1. \(6\)
    2. \(8\)
    3. \(10\)
    4. \(40\)
  2. What is the mean of the numbers \(2, 4, 6, 8, 10\)?

    1. \(4\)
    2. \(6\)
    3. \(5\)
    4. \(7\)
  3. Find the mean of \(5, 15, 20, 30\).

    1. \(15\)
    2. \(25\)
    3. \(20\)
    4. \(17.5\)
  4. What is the median of the data set: \(3, 7, 9, 12, 15\)?

    1. \(9\)
    2. \(7\)
    3. \(12\)
    4. \(10.2\)
  5. Find the median of \(2, 5, 8, 11, 14, 17\).

    1. \(9.5\)
    2. \(8\)
    3. \(11\)
    4. \(10\)
  6. The mean of \(5, 8, 12, x\) is \(10\). What is the value of \(x\)?

    1. \(15\)
    2. \(18\)
    3. \(25\)
    4. \(30\)
  7. The data set is: \(2, 4, 6, 8, 30\). Which statement is true?

    1. Mean equals Median
    2. Mean is less than Median
    3. Mean is greater than Median
    4. Mean is half the Median
  8. A dot plot shows the number of goals scored by 9 players: What is the median number of goals?

    Mean and Median visual for G6-C05-T03-Q009
    1. \(2\)
    2. \(3\)
    3. \(4\)
    4. \(5\)
Teacher and parent reference

Answer key and explanations

  1. B. \(8\)

    Mean \(=\frac{4+6+8+10+12}{5}=\frac{40}{5}=8\).

  2. B. \(6\)

    Mean \(=\frac{2+4+6+8+10}{5}=\frac{30}{5}=6\).

  3. D. \(17.5\)

    Mean \(=\frac{5+15+20+30}{4}=\frac{70}{4}=17.5\).

  4. A. \(9\)

    The data is already ordered. The median is the middle value: \(9\).

  5. A. \(9.5\)

    Median is the average of the two middle values (positions 3 and 4): \(\frac{8+11}{2}=9.5\).

  6. A. \(15\)

    Mean \(= \frac{5+8+12+x}{4}=10 \Rightarrow 5+8+12+x=40 \Rightarrow x=15\).

  7. C. Mean is greater than Median

    Mean \(=\frac{2+4+6+8+30}{5}=10\). Median \(=6\) (middle value). Since \(10>6\), the mean is greater than the median. The outlier \(30\) pulls the mean up.

  8. B. \(3\)

    Data: \(1, 2, 2, 3, 3, 3, 4, 4, 5\). The median (middle of 9 values) is the 5th value: \(3\).

Free Testinar sample Reviewed November 6, 2026 testinar.com
Page UP