Testinar Grade 6 math

Solving Percent Problems

Students will build Grade 6 mastery of solving percent problems using models, equations, and test-style reasoning.

CH01-08 Ratios, Rates, and Percents
Name
Date
Score
____ / 8
Directions Solve each problem. Show your reasoning on the page or on separate paper. Check the answer key only after finishing.

  1. A sweater originally costs \($40\). It is on sale for \(25\%\) off. What is the sale price?

    1. \($10\)
    2. \($15\)
    3. \($30\)
    4. \($50\)

  2. Sarah scored \(45\) correct answers out of \(60\) questions on a math test. What percent of the questions did she answer correctly?

    1. \(55\%\)
    2. \(65\%\)
    3. \(75\%\)
    4. \(85\%\)

  3. In the bar model above, the shaded region represents \(75\) students. How many students are there in total?

    Solving Percent Problems visual for G6-C01-T08-Q003
    1. \(100\)
    2. \(150\)
    3. \(200\)
    4. \(300\)

  4. A jacket costs \($80\) after a \(20\%\) discount. What was the original price?

    1. \($96\)
    2. \($160\)
    3. \($120\)
    4. \($100\)

  5. What is \(15\%\) of \($200\)?

    1. \($20\)
    2. \($25\)
    3. \($30\)
    4. \($35\)

  6. A restaurant bill comes to \($45\). The customer wants to leave a \(20\%\) tip. How much is the tip?

    1. \($4.50\)
    2. \($9.00\)
    3. \($18.00\)
    4. \($27.00\)

  7. Out of \(250\) students at a school, \(30\%\) participate in sports. How many students participate in sports?

    1. \(50\)
    2. \(70\)
    3. \(75\)
    4. \(100\)

  8. If a book's price increases from \($20\) to \($24\), what is the percent increase?

    1. \(20\%\)
    2. \(25\%\)
    3. \(30\%\)
    4. \(40\%\)
Teacher and parent reference

Answer key and explanations

  1. C. \($30\)

    \(25\%\) of \($40\) is \(0.25\times40=$10\). Sale price is \($40-$10=$30\).

  2. C. \(75\%\)

    To find the percent: \(\frac{45}{60}=\frac{3}{4}=0.75=75\%\).

  3. A. \(100\)

    Shaded portion is \(75\%\) of the total. If \(75\%\) equals \(75\) students, then \(100\%=\frac{75}{0.75}=100\) students.

  4. D. \($100\)

    If the discount is \(20\%\), the customer pays \(80\%\) of the original price. So \(0.80 \times \text{original} = $80\). Original \(= $80 \div 0.80 = $100\).

  5. C. \($30\)

    \(15\% \times $200 = 0.15 \times 200 = $30\).

  6. B. \($9.00\)

    \(20\%\) of \($45 = 0.20 \times 45 = $9.00\).

  7. C. \(75\)

    \(30\%\) of \(250 = 0.30 \times 250 = 75\) students.

  8. A. \(20\%\)

    Increase is \($24 - $20 = $4\). Percent increase is \(\frac{4}{20} = 0.20 = 20\%\).

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