Testinar Grade 7 math

Connecting Percents and Proportions

Students will build Grade 7 mastery of connecting percents and proportions using models, equations, and test-style reasoning.

CH02-02 Percents and Financial Literacy
Name
Date
Score
____ / 8
Directions Solve each problem. Show your reasoning on the page or on separate paper. Check the answer key only after finishing.

  1. In a class of \(25\) students, \(15\) play a sport. What percent of the students play a sport?

    1. \(25\%\)
    2. \(40\%\)
    3. \(50\%\)
    4. \(60\%\)

  2. A store sells \(120\) items in one day. If \(30\%\) of them were on sale, how many items were on sale?

    1. \(30\)
    2. \(90\)
    3. \(40\)
    4. \(36\)

  3. What is \(0.45\) as a percent?

    1. \(4.5\%\)
    2. \(450\%\)
    3. \(0.45\%\)
    4. \(45\%\)

  4. A school has \(280\) students. If \(35\%\) are in 7th grade, how many 7th graders are there?

    1. \(70\)
    2. \(78\)
    3. \(98\)
    4. \(105\)

  5. What percent is shown in the bar model above?

    Connecting Percents and Proportions visual for G7-C02-T02-Q005
    1. \(6\%\)
    2. \(40\%\)
    3. \(60\%\)
    4. \(100\%\)

  6. If \(18\%\) of a number is \(36\), what is the number?

    1. \(150\)
    2. \(180\)
    3. \(200\)
    4. \(250\)

  7. A bicycle costs \($80\). The price is marked up by \(25\%\). What is the new price?

    1. \($55\)
    2. \($20\)
    3. \($105\)
    4. \($100\)

  8. A recipe needs \(2\) cups of flour. If you want to make \(150\%\) of the recipe, how much flour do you need?

    1. \(1.5\) cups
    2. \(2.5\) cups
    3. \(3\) cups
    4. \(4\) cups
Teacher and parent reference

Answer key and explanations

  1. D. \(60\%\)

    Set up the proportion \(\frac{15}{25}=\frac{p}{100}\). Solving gives \(p=60\), so \(60\%\) play a sport.

  2. D. \(36\)

    Using the proportion \(\frac{30}{100}=\frac{x}{120}\), cross-multiply: \(30 \times 120 = 100x\), so \(x = 36\) items.

  3. D. \(45\%\)

    To convert a decimal to a percent, multiply by \(100\): \(0.45 \times 100 = 45\%\). Alternatively, \(0.45 = \frac{45}{100} = 45\%\).

  4. C. \(98\)

    Set up the proportion \(\frac{35}{100}=\frac{x}{280}\). Cross-multiply: \(35 \times 280 = 100x\), giving \(x = 98\).

  5. C. \(60\%\)

    The shaded portion represents \(60\) out of \(100\) units. Set up the proportion: \(\frac{60}{100}=\frac{p}{100}\), so \(p = 60\%\).

  6. C. \(200\)

    Set up \(\frac{18}{100}=\frac{36}{x}\). Cross-multiply: \(18x = 3600\), so \(x = 200\).

  7. D. \($100\)

    The markup is \(\frac{25}{100} \times 80 = 20\). Add to original: \(80 + 20 = $100\).

  8. C. \(3\) cups

    Multiply \(2\) by \(1.5\): \(2 \times 1.5 = 3\) cups. Alternatively, using a proportion: \(\frac{150}{100} = \frac{x}{2}\), so \(x = 3\).

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