Expand: \(4(2x-3)\)
- A \(6x-12\)
- B \(8x-12\)
- C \(8x-3\)
- D \(6x-7\)
Check answer and explanation
Answer B: \(8x-12\)
Distribute \(4\) to both terms: \(4(2x)-4(3)=8x-12\). (Positive times negative gives negative.)
A focused Grade 7 learning session for Expanding Expressions with the Distributive Property using visual models, worked examples, strategy guidance, and a short mastery check.
Student goal: I can solve problems involving expanding expressions with the distributive property.
Expanding Expressions with the Distributive Property is part of Grade 7 Expressions. This activity focuses on the central idea students need before they move into independent practice.
Students will build Grade 7 mastery of expanding expressions with the distributive property using models, equations, and test-style reasoning.
| What to notice | How to use it |
|---|---|
| Numbers, units, labels, diagrams, or graphs | Identify what each part represents before calculating. |
| The relationship in the problem | Connect the model to an equation, comparison, or explanation. |
Use the figures and worked questions in the practice set below as the visual model for this skill.
Read the first practice question slowly. Decide what the question is asking, choose a strategy, solve, and then compare your reasoning with the answer explanation.
For Expanding Expressions with the Distributive Property, a strong worked example should show the setup, the calculation or model, and a final answer that matches the context.
Many Grade 7 test questions use real situations. Look for quantities, units, rates, measures, expressions, or data values that connect the math to the story.
After solving, explain what the answer means in the situation, not just the number you calculated.
I can solve problems involving expanding expressions with the distributive property.
Use the warmup, guided question, practice set, and exit questions below to check whether this skill is ready or needs more practice.
Use scratch paper. The explanation matters more than simply seeing whether the choice is correct.
Expand: \(4(2x-3)\)
Answer B: \(8x-12\)
Distribute \(4\) to both terms: \(4(2x)-4(3)=8x-12\). (Positive times negative gives negative.)
Expand: \(3(x+5)\)
Answer C: \(3x+15\)
Distribute \(3\) to both terms: \(3(x)+3(5)=3x+15\).
Expand: \(-2(x+4)\)
Answer A: \(-2x-8\)
Distribute \(-2\): \(-2(x)-2(4)=-2x-8\). Negative times positive is negative.
Expand: \(5(3y-2)\)
Answer C: \(15y-10\)
Distribute \(5\): \(5(3y)-5(2)=15y-10\).
Expand: \(-3(2a-5)\)
Answer B: \(-6a+15\)
Distribute \(-3\) to both terms: \(-3(2a)=-6a\) and \(-3(-5)=+15\) (negative times negative is positive). Result: \(-6a+15\).
Expand: \(\frac{1}{2}(4x+6)\)
Answer A: \(2x+3\)
Distribute \(\frac{1}{2}\): \(\frac{1}{2}(4x)+\frac{1}{2}(6)=2x+3\).
Expand: \(6(m-1)\)
Answer A: \(6m-6\)
Distribute \(6\): \(6(m)-6(1)=6m-6\).
Expand: \(-4(3b+2)\)
Answer A: \(-12b-8\)
Distribute \(-4\): \(-4(3b)-4(2)=-12b-8\).
Expand: \(7(2p+3)\)
Answer C: \(14p+21\)
Distribute \(7\): \(7(2p)+7(3)=14p+21\).
Expand and simplify: \(2(3x+5)+4\)
Answer A: \(6x+14\)
Expand: \(2(3x)+2(5)+4=6x+10+4=6x+14\).
Expand: \(\frac{1}{3}(9y-12)\)
Answer A: \(3y-4\)
Distribute \(\frac{1}{3}\): \(\frac{1}{3}(9y)-\frac{1}{3}(12)=3y-4\).