Using the simple interest formula \(I=Prt\), how much interest does \($800\) earn at an annual rate of \(5\%\) over \(3\) years?
- \($40\)
- \($240\)
- \($125\)
- \($120\)
Students will build Grade 7 mastery of simple interest: earning and paying interest using models, equations, and test-style reasoning.
Using the simple interest formula \(I=Prt\), how much interest does \($800\) earn at an annual rate of \(5\%\) over \(3\) years?
Maya deposits \($1200\) into a savings account with a simple interest rate of \(4\%\) per year. How much interest will she earn after \(2\) years?
A loan of \($5000\) has a simple interest rate of \(6\%\) per year. What will be the total amount owed after \(4\) years?
Jordan invests \($2000\) at a simple interest rate of \(3.5\%\) per year for \(5\) years. How much interest will he earn?
A savings account earns \($75\) in interest from a principal of \($500\) at an annual rate of \(5\%\). How many years has the money been in the account?
An investment of \($3000\) earns \($270\) in simple interest over \(2\) years. What is the annual interest rate?
A car loan of \($15000\) is taken at a simple interest rate of \(7\%\) per year. How much total interest will be paid over \(6\) years?
A principal amount earns \($200\) in interest at \(8\%\) annual rate over \(5\) years. What was the original principal?
\(I=Prt=800\times0.05\times3=$120\).
STEP 1: Convert percentage to decimal: \(4\% = 4 \div 100 = 0.04\). STEP 2: \(I=1200\times0.04\times2=$96\).
First find interest: \(I=5000\times0.06\times4=$1200\). Then \(A=P+I=5000+1200=$6200\).
\(I=2000\times0.035\times5=$350\). Convert \(3.5\%\) to \(0.035\).
Using \(I=Prt\): \(75=500\times0.05\times t \Rightarrow 75=25t \Rightarrow t=3\).
\(270=3000\times r\times2 \Rightarrow 270=6000r \Rightarrow r=0.045=4.5\%\).
\(I=15000\times0.07\times6=$6300\).
\(200=P\times0.08\times5 \Rightarrow 200=0.4P \Rightarrow P=$500\).