Testinar Grade 7 math

Solving Two-Step Equations

Students will build Grade 7 mastery of solving two-step equations using models, equations, and test-style reasoning.

CH05-02 Equations and Inequalities

Directions Solve each problem. Show your reasoning on the page or on separate paper. Check the answer key only after finishing.

Solve for \(x\): \(2x+7=19\)
1. \(x=4\)
2. \(x=5\)
3. \(x=6\)
4. \(x=13\)
Solve: \(2(x+3)=14\)
1. \(x=2\)
2. \(x=3\)
3. \(x=4\)
4. \(x=7\)
Which value of \(x\) satisfies \(4x+2=18\)?
1. \(x=2\)
2. \(x=4\)
3. \(x=5\)
4. \(x=8\)
Solve for \(y\): \(5y-3=22\)
1. \(y=3\)
2. \(y=5\)
3. \(y=19\)
4. \(y=25\)
What is \(x\) if \(3(x-2)=9\)?
1. \(x=2\)
2. \(x=3\)
3. \(x=5\)
4. \(x=6\)
Find \(x\): \(\frac{x}{2}+3=7\)
1. \(x=4\)
2. \(x=6\)
3. \(x=8\)
4. \(x=10\)
Which value makes \(2(x+5)=18\) true?
1. \(x=2\)
2. \(x=4\)
3. \(x=5\)
4. \(x=9\)
Find the solution: \(\frac{x}{3}-2=4\)
1. \(x=4\)
2. \(x=12\)
3. \(x=18\)
4. \(x=24\)

Teacher and parent reference

Answer key and explanations

C. \(x=6\)
Subtract \(7\): \(2x=12\). Divide by \(2\): \(x=6\).
C. \(x=4\)
Divide by \(2\): \(x+3=7\). Subtract \(3\): \(x=4\).
B. \(x=4\)
Subtract \(2\): \(4x=16\). Divide by \(4\): \(x=4\).
B. \(y=5\)
Add \(3\): \(5y=25\). Divide by \(5\): \(y=5\).
C. \(x=5\)
Divide by \(3\): \(x-2=3\). Add \(2\): \(x=5\).
C. \(x=8\)
Subtract \(3\): \(\frac{x}{2}=4\). Multiply by \(2\): \(x=8\).
B. \(x=4\)
Divide by \(2\): \(x+5=9\). Subtract \(5\): \(x=4\).
C. \(x=18\)
Add \(2\): \(\frac{x}{3}=6\). Multiply by \(3\): \(x=18\).