A graph of a proportional relationship passes through the origin and \((5, 15)\). What is the slope (unit rate)?
- \(2\)
- \(15\)
- \(5\)
- \(3\)
Learn to reason about and solve Grade 8 problems involving Graphing Proportional Relationships.
A graph of a proportional relationship passes through the origin and \((5, 15)\). What is the slope (unit rate)?
What is the slope of the line shown in the graph?
What is the constant of proportionality for this graph?
Using the graph, find the equation of the proportional relationship.
What is the slope of the line?
Does the table show values from the equation \(y = 5x\)?
What is the unit rate shown in the graph?
The graph shows a proportional relationship. Find the equation.
Slope \(=\frac{\Delta y}{\Delta x}=\frac{15-0}{5-0}=3\). For a proportional line through the origin, the slope equals the unit rate.
Slope \(=\frac{\Delta y}{\Delta x}=\frac{6-0}{3-0}=\frac{6}{3}=2\). The line passes through \((0,0)\) and \((3,6)\).
Constant of proportionality \(k=\frac{y}{x}=\frac{2}{4}=\frac{1}{2}\). The line passes through \((0,0)\) and \((4,2)\).
Slope \(k=\frac{2}{5}\). Equation: \(y=\frac{2}{5}x\).
Slope \(=\frac{8}{2}=4\). The line passes through \((0,0)\) and \((2,8)\).
Each value: \(y=5(1)=5\), \(y=5(2)=10\), \(y=5(3)=15\). All match the equation \(y=5x\).
Unit rate is slope: \(\frac{3}{6}=\frac{1}{2}\). For every 1 unit of \(x\), \(y\) increases by \(\frac{1}{2}\).
Slope \(k=\frac{3}{9}=\frac{1}{3}\). Equation: \(y=\frac{1}{3}x\).