Which inequality has the solution graphed below?
- \(x<2\)
- \(x>2\)
- \(x\leq2\)
- \(x\geq2\)
Learn to reason about and solve Grade 8 problems involving Solving Linear Inequalities.
Which inequality has the solution graphed below?
Graph the solution to \(x+4<7\) on a number line. The inequality is:
Which graph represents \(x\geq-1\)?
Solve: \(x+7<10\). Which number line shows the solution?
Which shows the solution to \(x-3>-7\) on a number line?
Which number line shows the solution to \(3-2x>-5\)?
Solve and graph: \(-2x+3<-1\). Which describes the graph?
Solve: \(-2x+5\geq11\)
The open circle at \(2\) means \(2\) is not included. The ray points left to smaller values, so \(x<2\).
Subtract \(4\): \(x<3\). The open circle and left-pointing ray show all numbers less than \(3\).
The inequality \(x\geq-1\) includes \(-1\) (closed circle) and all values greater (ray points right).
Subtract \(7\): \(x<3\). The open circle and left ray match this solution.
Add \(3\): \(x>-4\). Open circle at \(-4\) with right ray confirms this.
Subtract \(3\): \(-2x>-8\). Divide by \(-2\) (FLIP): \(x<4\). Open circle and left ray.
Subtract \(3\): \(-2x<-4\). Divide by \(-2\) (FLIP): \(x>2\). Open circle and right ray.
Subtract \(5\): \(-2x\geq6\). Divide by \(-2\) (and FLIP the inequality): \(x\leq-3\).