Testinar Grade 8 math

Solving Real Problems with Systems

Learn to reason about and solve Grade 8 problems involving Solving Real Problems with Systems.

CH03-06 Equations, Inequalities, and Systems
Name
Date
Score
____ / 8
Directions Solve each problem. Show your reasoning on the page or on separate paper. Check the answer key only after finishing.
  1. A juice bar mixes two juices. Juice A is \(25\%\) apple. Juice B is \(75\%\) apple. The shop wants \(40\) liters of a \(55\%\) apple blend. The graph below shows the relationship between volumes of A and B. Which point represents the solution?

    Solving Real Problems with Systems visual for G8-C03-T06-Q032
    1. \((10, 30)\)
    2. \((20, 20)\)
    3. \((16, 24)\)
    4. \((30, 10)\)
  2. Two planes depart from the same airport at the same time, flying in opposite directions. Plane A flies at \(480\) mph; Plane B flies at \(520\) mph. The graph shows their positions over time. After how many hours are the planes \(3000\) miles apart?

    Solving Real Problems with Systems visual for G8-C03-T06-Q039
    1. \(2.5\) hours
    2. \(3.5\) hours
    3. \(3\) hours
    4. \(4\) hours
  3. Two boats depart from the same dock, traveling in opposite directions along a river. Boat A goes upstream at \(10\) mph in still water; Boat B goes downstream at \(14\) mph in still water. The river current is \(2\) mph. After how many hours are they \(36\) miles apart?

    Solving Real Problems with Systems visual for G8-C03-T06-Q044
    1. \(1\) hour
    2. \(2\) hours
    3. \(1.5\) hours
    4. \(2.5\) hours
  4. Tickets cost \($4\) for children and \($7\) for adults. The theater sold \(200\) tickets for a total of \($1{,}100\). How many children's tickets were sold?

    1. \(100\)
    2. \(150\)
    3. \(50\)
    4. \(120\)
  5. A chemist mixes a \(30\%\) acid solution with an \(80\%\) acid solution to make \(100\) mL of a \(50\%\) solution. Let \(x\) = volume of \(30\%\) solution (mL). Which equation represents the acid content?

    1. \(0.3x + 0.8(100-x) = 0.5(100)\)
    2. \(0.3(100-x) + 0.8x = 50\)
    3. \(30x + 80x = 50 \cdot 100\)
    4. \(0.3x + 0.8x = 50\)
  6. Train A travels at \(60\) mph. Train B travels at \(75\) mph. If Train B leaves \(1\) hour later but they meet after Train A has traveled for \(5\) hours, which equation is correct?

    1. \(60 \cdot 5 = 75 \cdot 4\)
    2. \(60 \cdot 5 + 75 \cdot 4 = \text{total distance}\)
    3. \(60 \cdot 4 = 75 \cdot 5\)
    4. \(60 \cdot 5 = 75 \cdot 5\)
  7. A piggy bank holds \(25\) coins consisting of nickels (5¢) and dimes (10¢). The total value is \($1.70\). How many nickels are in the bank?

    1. \(10\)
    2. \(16\)
    3. \(12\)
    4. \(8\)
  8. Maria is currently \(4\) years older than her sister Emma. In \(3\) years, Maria will be twice Emma's age. How old is Emma now?

    1. \(1\)
    2. \(2\)
    3. \(3\)
    4. \(5\)
Teacher and parent reference

Answer key and explanations

  1. C. \((16, 24)\)

    Let \(a =\) liters of Juice A and \(b =\) liters of Juice B. Then \(a+b=40\) and \(0.25a+0.75b=0.55(40)=22\). Substitute \(b=40-a\): \(0.25a+0.75(40-a)=22\), so \(30-0.50a=22\). Thus \(a=16\) and \(b=24\).

  2. C. \(3\) hours

    When flying in opposite directions, combined speed \(= 480 + 520 = 1000\) mph. Distance \(=\) speed \(\times\) time: \(3000 = 1000t\), so \(t = 3\) hours.

  3. C. \(1.5\) hours

    Boat A's effective upstream speed is \(10-2=8\) mph. Boat B's effective downstream speed is \(14+2=16\) mph. Their separation increases at \(8+16=24\) mph, so \(24t=36\) and \(t=1.5\) hours.

  4. A. \(100\)

    Let \(c=\) children, \(a=\) adults. Then \(c+a=200\) and \(4c+7a=1100\). Substitute \(a=200-c\): \(4c+7(200-c)=1100\), so \(-3c=-300\), \(c=100\).

  5. A. \(0.3x + 0.8(100-x) = 0.5(100)\)

    The \(30\%\) solution contributes \(0.3x\) mL of pure acid. The \(80\%\) solution contributes \(0.8(100-x)\) mL. Total pure acid must equal \(0.5(100) = 50\) mL. Only option A is correct.

  6. A. \(60 \cdot 5 = 75 \cdot 4\)

    Train A travels for \(5\) hours. Train B leaves \(1\) hour later, so it travels for \(4\) hours. Since they meet after covering the same distance, the equation is \(60 \cdot 5 = 75 \cdot 4\).

  7. C. \(12\)

    Let \(n =\) nickels, \(d =\) dimes. Then \(n + d = 25\) and \(0.05n + 0.10d = 1.70\). From the first equation, \(d = 25 - n\). Substituting: \(0.05n + 0.10(25-n) = 1.70\), so \(0.05n + 2.5 - 0.10n = 1.70\), giving \(-0.05n = -0.8\), so \(n = 12\).

  8. A. \(1\)

    Let \(e =\) Emma's current age. Then Maria's age is \(e + 4\). In \(3\) years: Emma is \(e + 3\), Maria is \(e + 7\). The condition gives \(e + 7 = 2(e + 3)\), so \(e + 7 = 2e + 6\), thus \(e = 1\).

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