A fair coin is flipped twice. What is the probability of getting heads BOTH times?
- \(\frac{1}{8}\)
- \(\frac{1}{4}\)
- \(\frac{1}{2}\)
- \(\frac{3}{4}\)
Students will build Grade 7 mastery of finding probabilities of compound events using models, equations, and test-style reasoning.
A fair coin is flipped twice. What is the probability of getting heads BOTH times?
A fair six-sided die is rolled twice. What is the probability of rolling a 3 on the first roll AND a 5 on the second roll?
A bag contains 6 white marbles and 4 black marbles. One marble is drawn at random. What is the probability it is white?
Two cards are drawn from a standard 52-card deck WITH replacement. What is the probability of drawing a heart on the first draw AND a spade on the second draw?
A bag contains 3 red marbles and 5 blue marbles. What is the probability of drawing a red marble first, WITHOUT replacing it, then drawing a blue marble?
Which of the following describes mutually exclusive events?
A card is drawn from a standard deck. What is the probability of drawing a king OR a queen?
A number from 1 to 20 is selected at random. What is the probability of selecting a multiple of 3 OR a multiple of 5?
\(P(H)\cdot P(H)=\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}\).
\(P(3)\cdot P(5)=\frac{1}{6}\cdot\frac{1}{6}=\frac{1}{36}\) for independent events.
Total marbles: 10. White marbles: 6. Probability: \(\frac{6}{10}=\frac{3}{5}\).
With replacement: \(P(\text{heart})\cdot P(\text{spade})=\frac{1}{4}\cdot\frac{1}{4}=\frac{1}{16}\).
Without replacement: \(P(\text{red first})=\frac{3}{8}\), then \(P(\text{blue second})=\frac{5}{7}\) (only 7 left). Product: \(\frac{3}{8}\cdot\frac{5}{7}=\frac{15}{56}\).
Mutually exclusive events cannot happen at the same time. A coin cannot show both heads and tails on one flip.
King OR Queen: \(P(\text{King})+P(\text{Queen})=\frac{4}{52}+\frac{4}{52}=\frac{8}{52}=\frac{2}{13}\) (mutually exclusive).
Multiples of 3: {3, 6, 9, 12, 15, 18} and multiples of 5: {5, 10, 15, 20}. Total: {3, 5, 6, 9, 10, 12, 15, 18, 20} = 9 numbers. So \(\frac{9}{20}\).