A fair coin is flipped twice. What is the probability of getting heads BOTH times?
- A \(\frac{1}{8}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{2}\)
- D \(\frac{3}{4}\)
Check answer and explanation
Answer B: \(\frac{1}{4}\)
\(P(H)\cdot P(H)=\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}\).

