A trapezoid’s area is the region encompassed inside the perimeter and calculated by this formula:
\(A \ = \ \frac{1}{2} \ h(b_1 \ + \ b_2)\)
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A trapezoid’s area is the region encompassed inside the perimeter and calculated by this formula:
\(A \ = \ \frac{1}{2} \ h(b_1 \ + \ b_2)\)
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- Step 1: Study the data and determine the amount of figures. Classify these as \(2\) or \(3\)-digit numbers.
- Step 2: Put in a stem and leaf plot key. For example, \(2 \ | \ 4 \ = \ 24\), along wtih \(3 \ | \ 1\) is \(31\).
- Step 3: Establish the first figures as stems, then make the last numbers leaves.
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- Mean:\(\frac{\ sum\ \ of\ \ the data\ }{\ of \ data\ \ entires\ }\)
- Mode: value in the list that appears most often
- Range: largest value – the smallest value
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To factor trinomials, follow these steps:
- Step one: Determine values for \(b\) and \(c\). (trinomial: \(x^2 \ + \ bx \ + c\))
- Step two: Locate 2 two numbers which ADD to \(b\) and MULTIPLY to \(c\). This second step may involve a small amount of trial and error.
- Step three: Utilize the numbers you chose for writing out the factors and check.
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An angle is a type of geometric shape that is made by joining the ends of two rays together. The angle can also be shown by the three letters of the shape that makes the angle. The angle is in the middle letter (i.e.its vertex). Most of the time, Greek letters like \(β \ , \ α \ , \ φ\), etc. are used to show angles.
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Geometric sequences are those in which the following number is obtained by multiplying the previous term by a constant known as the common ratio. The letter \(r\) is used to show the common ratio.
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\(a_n \ = \ a_1 \ + \ d \ (n \ – \ 1)\)
- \(a_1 =\) The first term
- \(d =\) The common difference between terms
- \(n =\) The term poistion
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In math, logarithm problems are solved using the properties of the functions that make up logarithms. In basic math, we learned a lot of properties, like commutative, associative, and distributive, that can be used in algebra. When it comes to logarithmic functions, there are five main things to know.
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Consider: \(log_b \ x \ = \ y\):
- Rewrite the exponential expression "\(x\)" as a power of "\(b\)": \(b^y \ = \ x\)
- Use what you know about powers to figure out what \(y\) is by asking, "To what exponent should \(y\) be raised to get \(x\)?"
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If you realize that logarithms are just another way to write out exponential equations, it becomes much easier to solve a logarithm. Once you change the logarithm into a form that is easier to understand, you should be able to solve it the same way you would solve an ordinary exponential equation.
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