Evaluate: \(-\frac{3}{4}+\frac{1}{2}\)
- A \(-\frac{5}{4}\)
- B \(-\frac{1}{4}\)
- C \(\frac{1}{4}\)
- D \(\frac{5}{4}\)
Check answer and explanation
Answer B: \(-\frac{1}{4}\)
Find a common denominator: \(-\frac{3}{4}+\frac{2}{4}=-\frac{1}{4}\).
A focused Grade 7 learning session for Adding and Subtracting Rational Numbers using visual models, worked examples, strategy guidance, and a short mastery check.
Student goal: I can solve problems involving adding and subtracting rational numbers.
Adding and Subtracting Rational Numbers is part of Grade 7 The Number System. This activity focuses on the central idea students need before they move into independent practice.
Students will build Grade 7 mastery of adding and subtracting rational numbers using models, equations, and test-style reasoning.
| What to notice | How to use it |
|---|---|
| Numbers, units, labels, diagrams, or graphs | Identify what each part represents before calculating. |
| The relationship in the problem | Connect the model to an equation, comparison, or explanation. |
Use the figures and worked questions in the practice set below as the visual model for this skill.
Read the first practice question slowly. Decide what the question is asking, choose a strategy, solve, and then compare your reasoning with the answer explanation.
For Adding and Subtracting Rational Numbers, a strong worked example should show the setup, the calculation or model, and a final answer that matches the context.
Many Grade 7 test questions use real situations. Look for quantities, units, rates, measures, expressions, or data values that connect the math to the story.
After solving, explain what the answer means in the situation, not just the number you calculated.
I can solve problems involving adding and subtracting rational numbers.
Use the warmup, guided question, practice set, and exit questions below to check whether this skill is ready or needs more practice.
Use scratch paper. The explanation matters more than simply seeing whether the choice is correct.
Evaluate: \(-\frac{3}{4}+\frac{1}{2}\)
Answer B: \(-\frac{1}{4}\)
Find a common denominator: \(-\frac{3}{4}+\frac{2}{4}=-\frac{1}{4}\).
What is \(-\frac{3}{5}+\frac{4}{5}\)?
Answer B: \(\frac{1}{5}\)
When denominators are the same, add the numerators: \(-\frac{3}{5}+\frac{4}{5}=\frac{1}{5}\).
Evaluate: \(5.2 - 7.1\)
Answer A: \(-1.9\)
Since \(5.2 < 7.1\), the difference is negative: \(5.2 - 7.1 = -1.9\).
Add: \(1\frac{1}{3} + 2\frac{1}{6}\)
Answer D: \(3\frac{1}{2}\)
Convert to common denominator 6: \(1\frac{2}{6} + 2\frac{1}{6} = 3\frac{3}{6} = 3\frac{1}{2}\).
Which expression is equivalent to \(8 - 3\)?
Answer B: \(8 + (-3)\)
Subtraction can be rewritten as adding the opposite: \(8 - 3 = 8 + (-3) = 5\).
Evaluate: \(-\frac{5}{6} - \frac{1}{3}\)
Answer D: \(-1\frac{1}{6}\)
Common denominator is 6: \(-\frac{5}{6} - \frac{2}{6} = -\frac{7}{6} = -1\frac{1}{6}\).
Use the number line below. Start at \(-2\) and add \(3\). Where do you end?
Answer B: \(1\)
Starting at \(-2\) and moving right 3 units: \(-2 + 3 = 1\).
Use the number line to find \(-2.5 + 4.7\).
Answer C: \(2.2\)
Starting at \(-2.5\) and moving right \(4.7\) units: \(-2.5 + 4.7 = 2.2\).
Subtract: \(\frac{7}{8} - \frac{1}{4}\)
Answer D: \(\frac{5}{8}\)
Common denominator is 8: \(\frac{7}{8} - \frac{2}{8} = \frac{5}{8}\).
Evaluate: \(-3.6 + (-2.4)\)
Answer A: \(-6.0\)
Adding two negatives: \(-3.6 + (-2.4) = -(3.6 + 2.4) = -6.0\).
What is \(\frac{3}{10} + \frac{4}{10}\)?
Answer D: \(\frac{7}{10}\)
Same denominator: \(\frac{3}{10} + \frac{4}{10} = \frac{7}{10}\).