Free Full Length STAAR Grade 7 Practice Test

The correct answer is $2$
The equation of a line in slope intercept form is: $y=m \ x \ + \ b$
Solve for $y$.
$2 \ x \ - \ y=12 ⇒$
$- \ y=12 \ - \ 2 \ x ⇒$
$y=(12 \ - \ 2 \ x) \ ÷ \ (- \ 1) ⇒$
$y=2 \ x \ - \ 6$
The slope of this line is $2$.
Parallel lines have same slopes.

The correct answer is $36$
Simplify:
$5 \ (x\ - \ 2 \ y) \ + \ (2 \ - \ x)^2 =$
$(5 \ x \ - \ 10 \ y) \ + \ (4 \ - \ 4 \ x \ + \ x^2) =$
$x \ - \ 10 \ y \ + \ 4 \ + \ x^2$
When $x=3$ and $y=- \ 2$ ,therefore:
$x \ - \ 10 \ y \ + \ 4 \ + \ x^2 =3 \ + \ 20 \ + \ 4 \ + \ 9 =36$

The correct answer is $87.5$
average (mean) $=\frac{sum \ of \ terms}{number \ of \ terms}⇒$
$88 = \frac{sum \ of \ terms}{50} ⇒$
sum $= 88 \ × \ 50 = 4400$
The difference of $94$ and $69$ is $25$.
Therefore, $25$ should be subtracted from the sum.
$4400 \ – \ 25 = 4375$
mean $=\frac{sum \ of \ terms}{number \ of \ terms}⇒$
mean $=\frac{4375}{50 }= 87.5$

The correct answer is $729$
If the length of the box is $27$, then the width of the box is one third of it, $9$, and the height of the box is $3$ (one third of the width).
The volume of the box is:
$V = lwh = (27) \ (9) \ (3) = 729$

The correct answer is $475$
Add the first $5$ numbers.
$40 \ + \ 45 \ + \ 50 \ + \ 35 \ + \ 55 = 225$
To find the distance traveled in the next $5$ hours, multiply the average by number of hours.
Distance $=$ Average $×$ Rate $= 50 \ × \ 5 = 250$
Add both numbers.
$250 \ + \ 225 = 475$

The correct answer is $240$
The ratio of boy to girls is $2:3$.
Therefore, there are $2$ boys out of $5$ students.
To find the answer, first divide the total number of students by $5$, then multiply the result by $2$.
$600 \ ÷ \ 5 = 120 ⇒$
$120 \ × \ 2 = 240$

The correct answer is $130$
The perimeter of the trapezoid is $54$ cm.
Therefore, the missing side (high) is $= 54 \ – \ 18 \ – \ 12 \ – \ 14 = 10$
Area of a trapezoid: A $= \frac{1}{2} \ h \ (b1 \ + \ b2) = \frac{1}{2} \ (10) \ (12 \ + \ 14) = 130$

The correct answer is $I \ > \ 2000 \ x \ + \ 24000$
Let $x$ be the number of years.
Therefore, $$2,000$ per year equals $2000 \ x$.
starting from $$24,000$ annual salary means you should add that amount to $2000 \ x$.
Income more than that is:
$I \ > \ 2000 \ x \ + \ 24000$

Solve for $x$.
$- \ 2 \ ≤ \ 2 \ x \ - \ 4 \ < \ 8 ⇒$
(add $4$ all sides) $-\ 2 \ + \ 4 \ ≤ \ 2 \ x \ - \ 4 \ + \ 4 \ < \ 8 \ + \ 4 ⇒$
$2 \ ≤ \ 2 \ x \ < \ 12 ⇒$
(divide all sides by $2$) $1 \ ≤ \ x \ < \ 6$
$x$ is between $1$ and $6$.

The correct answer is $120 \ x \ + \ 14,000 \ ≤ \ 20,000$
Let $x$ be the number of new shoes the team can purchase. Therefore, the team can purchase $120 \ x$.
The team had $$20,000$ and spent $$14000$.
Now the team can spend on new shoes $$6000$ at most.
Now, write the inequality:
$120 \ x \ + \ 14,000 \ ≤ \ 20,000$

The correct answer is $\frac{1}{4}$
The options to get sum of $6: \ (1$ & $5)$ and $(5$ & $1), \ (2$ & $4)$ and $(4$ & $2), \ (3$ & $3)$, so we have $5$ options
The options to get sum of $9: \ (3$ & $6)$ and $(6$ & $3), \ (4$ & $5)$ and $(5$ & $4)$, we have $4$ options.
To get the sum of $6$ or $9$ for two dice, we have $9$ options: $5 \ + \ 4 = 9$
Since, we have $6 \ × \ 6 = 36$ total options, the probability of getting a sum of $6$ and $9$ is $9$ out of $36$ or $\frac{9}{36}=\frac{1}{4}$.

The correct answer is $8$
Use formula of rectangle prism volume.
V $=$ (length) (width) (height) $⇒ 2000 = (25) \ (10)$ (height) $⇒$
height $= 2000 \ ÷ \ 250 = 8$

For each option, choose a point in the solution part and check it on both inequalities.
A. Point $(– \ 4, \ – \ 4)$ is in the solution section. Let’s check the point in both inequalities.
$– \ 4 \ ≤ \ – \ 4 \ + \ 4$, It works
$2 \ (– \ 4) \ + \ (– \ 4) \ ≤ \ – \ 4 ⇒ – \ 12 \ ≤ \ – \ 4$, it works (this point works in both)
B. Let’s choose this point $(0, \ 0)$
$0 \ ≤ \ 0 \ + \ 4$, It works
$2 \ (0) \ + \ (0) \ ≤ \ – \ 4$, That’s not true!
C. Let’s choose this point $(– \ 5, \ 0)$
$0 \ ≤ \ – \ 5 \ + \ 4$, That’s not true!
D. Let’s choose this point $(0, \ 5)$
$5 \ ≤ \ 0 \ + \ 4$, That’s not true!

The correct answer is $$1800$
Use simple interest formula:
$I=prt$
($I =$ interest, $p =$ principal, $r =$ rate, $t =$ time)
$I=(8000) \ (0.045) \ (5)=1800$

The correct answer is $\frac{1}{4}$
The probability of choosing a Hearts is $\frac{13}{52} =\frac{1}{4}$

The correct answer is $8$ hours and $24$ minutes
Use distance formula:
Distance $=$ Rate $×$ time $⇒ 420 = 50 \ ×$ T, divide both sides by $50$.
$\frac{420}{50} =$ T $⇒$ T $= 8.4$ hours.
Change hours to minutes for the decimal part.
$0.4$ hours $= 0.4 \ × \ 60 = 24$ minutes.

The correct answer is $472$
$11 \ × \ 36 \ + \ 6 \ × \ 12 \ + \ 4 = 472$

The correct answer is $(200) \ (0.85) \ (0.85)$
To find the discount, multiply the number by ($100\% \ –$ rate of discount).
Therefore, for the first discount we get: $(200) (100\% \ – \ 15\%) = (200) \ (0.85) = 170$
For the next $15\%$ discount: $(200) \ (0.85) \ (0.85)$

The correct answer is $(- \ 1, \ 3)$
Input $(- \ 1, \ 3)$ in the $2 \ x \ + \ 4 \ y = 10$ formula instead of $x$ and $y$. So we have:
$2(- \ 1) \ + \ 4 \ (3) = 10$
$- \ 2 \ + \ 12 = 10$

The correct answer is $- \ 30$
Use PEMDAS (order of operation):
$5 \ + \ 8 \ × \ (– \ 2) \ – \ [ \ 4 \ + \ 22 \ × \ 5 \ ] \ ÷ \ 6 =$
$5 \ + \ 8 \ × \ (– \ 2) \ – \ [ \ 4 \ + \ 110 \ ] \ ÷ \ 6 =$
$5 \ + \ 8 \ × \ (– \ 2) \ – \ [ \ 114 \ ] \ ÷ \ 6 =$
$5 \ + \ (– \ 16) \ – \ 19 =$
$5 \ + \ (– \ 16) \ – \ 19 =$
$– \ 11 \ – \ 19 = \ – \ 30$

The correct answer is $20\%$
Use this formula: Percent of Change
$\frac{New \ Value-Old \ Value}{Old \ Value} \ × \ 100\%$
$\frac{16000 \ - \ 20000}{20000} \ × \ 100\% = 20\%$ and $\frac{12800 \ - \ 16000}{16000} \ ×  \ 100\% = 20\%$

The correct answer is $40$
Plug in $104$ for F and then solve for C.
C $= \frac{5}{9}$ (F $– \ 32) ⇒$
C $= \frac{5}{9} \ (104 \ – \ 32) ⇒$
C $= \frac{5}{9} \ (72) = 40$

The correct answer is $\frac{125}{512}$
The square of a number is $\frac{25}{64}$, then the number is the square root of $\frac{25}{64}$
$\sqrt{\frac{25}{64}}= \frac{5}{8}$
The cube of the number is:
$(\frac{5}{8})^3 = \frac{125}{512}$

The correct answer is $66 \ π$
Surface Area of a cylinder $= 2 \ π \ r \ (r \ + \ h)$,
The radius of the cylinder is $3 \ (6 \ ÷ \ 2)$ inches and its height is $8$ inches.
Therefore, Surface Area of a cylinder $= 2 \ π \ (3) \ (3 \ + \ 8) = 66 \ π$

The correct answer is $\frac{1}{4}$
$\frac{2}{3} \ x \ + \ \frac{1}{6}=\frac{1}{3}⇒$
$\frac{2}{3} \ x= \frac{1}{6} ⇒$
$x= \frac{1}{6} \ × \ \frac{3}{2} ⇒ x= \frac{1}{4}$

The correct answer is $27$
Solve for the sum of five numbers.
average $=\frac{sum \ of \ terms}{number \ of \ terms} ⇒$
$24 = \frac{sum \ of \ 5 \ numbers}{5} ⇒$
sum of $5$ numbers $= 24 \ × \ 5 = 120$
The sum of $5$ numbers is $120$.
If a sixth number $42$ is added, then the sum of $6$ numbers is
$120 \ + \ 42 = 162$
average $= \frac{sum \ of \ terms}{number \ of \ terms}= \frac{162}{6} = 27$

The correct answer is $\frac{1}{4}$
Probability $= \frac{number \ of \ desired \ outcomes}{number \ of \ total \ outcomes}= \frac{18}{12 \ + \ 18 \ + \ 18 \ + \ 24} = \frac{18}{72} = \frac{1}{4}$

The correct answer is $\frac{2}{3}, \ 67\%, \ 0.68, \ \frac{4}{5}$
Change the numbers to decimal and then compare.
$\frac{2}{3} = 0.666…$
$0.68$
$67\% = 0.67$
$\frac{4}{5} = 0.80$
Therefore: $\frac{4}{5} \ > \ 68\% \ > \ 0.67 \ > \frac{2}{3}$

The correct answer is $60$
To find the number of possible outfit combinations, multiply number of options for each factor:
$3 \ × \ 5 \ × \ 4 = 60$

The correct answer is $24$
$4 \ ÷ \ \frac{1}{6} = 24$

The correct answer is $32$
The diagonal of the square is $8$.
Let $x$ be the side.
Use Pythagorean Theorem: $a^2 \ + \ b^2 = c^2$
$x^2 \ + \ x^2 = 82 ⇒$
$2 \ x^2 = 82 ⇒$
$2 \ x^2 = 64 ⇒$
$x^2 = 32 ⇒$
$x= \sqrt{32}$
The area of the square is:
$\sqrt{32} \ × \ \sqrt{32} = 32$

The correct answer is $12$
The ratio of boy to girls is $4:7$.
Therefore, there are $4$ boys out of $11$ students.
To find the answer, first divide the total number of students by $11$, then multiply the result by $4$. 
$44 \ ÷ \ 11 = 4 ⇒$
$4 \ × \ 4 = 16$
There are $16$ boys and $28 \ (44 \ – \ 16)$ girls. So, $12$ more boys should be enrolled to make the ratio $1:1$

The correct answer is $40$ ft.$^2$
Use the area of rectangle formula $(s=a \ × \ b)$.
To find area of the shaded region subtract the smaller rectangle from bigger rectangle.
S$_{1} \ –$ S$_{2} = (10$ ft $× \ 8$ ft) $– \ (5$ ft $× \ 8$ ft) $⇒$ S$_{1} \ –$ S$_{2} = 40$ ft.$^2$

The correct answer is $\frac{1}{22}$
$2,500$ out of $55,000$ equals to $\frac{2500}{55000} = \frac{25}{550} = \frac{1}{22}$

The correct answer is $6$
Let the number be $x$. Then:
$\frac{24 \ - \ x}{x} = 3→$
$3 \ x=24 \ - \ x→$
$4 \ x=24→$
$x = 6$

The correct answer is $120$ cm$^3$
Volume of a box $=$ length $×$ width $×$ height $= 4 \ × \ 5 \ × \ 6 = 120$ cm$^3$

The correct answer is $38$
The population is increased by $15\%$ and $20\%$.
$15\%$ increase changes the population to $115\%$ of original population.
For the second increase, multiply the result by $120\%$.
$(1.15) \ ×\ (1.20) = 1.38 = 138\%$
$38$ percent of the population is increased after two years.

The correct answer is $405$
The ratio of boy to girls is $4:5$.
Therefore, there are $4$ boys out of $9$ students.
To find the answer, first divide the number of boys by $4$, then multiply the result by $9$.
$180 \ ÷ \ 4 = 45 ⇒$
$45 \ × \ 9 = 405$

The correct answer is $18$
The area of the floor is: $6$ cm $× \ 24$ cm $= 144$ cm$^2$
The number of tiles needed $= 144 \ ÷ \ 8 = 18$

The correct answer is $1004.8$
Surface Area of a cylinder $= 2 \ π \ r \ (r \ + \ h)$,
The radius of the cylinder is $8$ inches and its height is $12$ inches.
$π$ is about $3.14$. Then:
Surface Area of a cylinder $= 2 \ (π) \ (8) \ (8 \ + \ 12) =$
$320 \ π = 1004.8$