## Full Length STAAR Grade 7 Practice Test

If you want to prepare for the STAAR Grade 7 Practice Test? It’s time to taking a Full-length STAAR Grade 7 Practice Test. It is the best way to simulate test day. To challenge your skills and simulate the full length STAAR Grade 7 Practice Test day experience, score your tests using the answer keys.

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## STAAR Practice Test 2

1- What is the slope of a line that is parallel to the line $$2 \ x \ - \ y=12$$?
(A) $$− \ 2$$
(B) $$2$$
(C) $$4$$
(D) $$12$$
2- What is the value of the expression $$5 \ (x \ - \ 2 \ y) \ + \ (2 \ - \ x)^2$$ when $$x=3$$ and $$y=- \ 2$$ ?
(A) $$− \ 4$$
(B) $$20$$
(C) $$36$$
(D) $$50$$
3- The mean of $$50$$ test scores was calculated as $$88$$. But, it turned out that one of the scores was misread as $$94$$ but it was $$69$$. What is the correct mean of the data?
(A) $$85$$
(B) $$87$$
(C) $$87.5$$
(D) $$88.5$$
4- The width of a box is one third of its length. The height of the box is one third of its width. If the length of the box is $$27$$ cm, what is the volume of the box?
(A) $$81$$ cm$$^3$$
(B) $$162$$ cm$$^3$$
(C) $$243$$ cm$$^3$$
(D) $$729$$ cm$$^3$$
5- In five successive hours, a car travels $$40$$ km, $$45$$ km, $$50$$ km, $$35$$ km and $$55$$ km. In the next five hours, it travels with an average speed of $$50$$ km per hour. Find the total distance the car traveled in $$10$$ hours.
(A) $$425$$ km
(B) $$450$$ km
(C) $$475$$ km
(D) $$500$$ km
6- The ratio of boys to girls in a school is $$2:3$$. If there are $$600$$ students in a school, how many boys are in the school.
(A) 240
(B) 240
(C) 240.0
7- The perimeter of the trapezoid below is $$54$$ cm. What is its area?
(A) 130
(B) 130
(C) 130.0
8- In $$1999$$, the average worker's income increased $$2,000$$ per year starting from $$24,000$$ annual salary.  Which equation represents income greater than average? (I $$=$$ income, $$x =$$ number of years after 1999)
(A) $$I > \ 2000 \ x \ + \ 24000$$
(B) $$I \ > \ - \ 2000 \ x \ + \ 24000$$
(C) $$I \ < \ - \ 2000 \ x \ + \ 24000$$
(D) $$I \ < \ 2000 \ x \ - \ 24000$$
9- Which of the following graphs represents the compound inequality?
(A)
(B)
(C)
(D)
10- A football team had $$20,000$$ to spend on supplies. The team spent $$14,000$$ on new balls. New sport shoes cost $$120$$ each. Which of the following inequalities represent how many new shoes the team can purchase?
(A) $$120 \ x \ + \ 14,000 \ ≤ \ 20,000$$
(B) $$120 \ x \ + \ 14,000 \ ≥ \ 20,000$$
(C) $$14,000 \ x \ + \ 12,0 \ ≤ \ 20,000$$
(D) $$14,000 \ x \ + \ 12,0 \ ≥ \ 20,000$$
11- Two dice are thrown simultaneously, what is the probability of getting a sum of $$6$$ or $$9$$?
(A) $$\frac{1}{3}$$
(B) $$\frac{1}{4}$$
(C) $$\frac{1}{6}$$
(D) $$\frac{1}{12}$$
12- A swimming pool holds $$2,000$$ cubic feet of water. The swimming pool is $$25$$ feet long and $$10$$ feet wide. How deep is the swimming pool?
(A) 8
(B) 8
(C) 8.0
13- Which graph corresponds to the following inequalities?
$$y \leq x \ + \ 4$$
$$2 \ x \ + \ y \leq - \ 4$$
(A)
(B)
(C)
(D)
14- A bank is offering $$4.5\%$$ simple interest on a savings account. If you deposit $$8,000$$, how much interest will you earn in five years?
(A) $$360$$
(B) $$720$$
(C) $$1800$$
(D) $$3600$$
15- A card is drawn at random from a standard $$52–$$card deck, what is the probability that the card is of Hearts? (The deck includes $$13$$ of each suit clubs, diamonds, hearts, and spades)
(A) $$\frac{1}{3}$$
(B) $$\frac{1}{4}$$
(C) $$\frac{1}{6}$$
(D) $$\frac{1}{52}$$
16- How long does a $$420–$$miles trip take moving at $$50$$ miles per hour (mph)?
(A) $$4$$ hours
(B) $$6$$ hours and $$24$$ minutes
(C) $$8$$ hours and $$24$$ minutes
(D) $$8$$ hours and $$30$$ minutes
17- $$11$$ yards $$6$$ feet and $$4$$ inches equals to how many inches?
(A) $$388$$
(B) $$468$$
(C) $$472$$
(D) $$476$$
18- A shirt costing $$200$$ is discounted $$15\%$$. After a month, the shirt is discounted another $$15\%$$. Which of the following expressions can be used to find the selling price of the shirt?
(A) $$(200) \ (0.70)$$
(B) $$(200) \ – \ 200 \ (0.30)$$
(C) $$(200) \ (0.15) \ – \ (200) \ (0.15)$$
(D) $$(200) \ (0.85) \ (0.85)$$
19- Which of the following points lies on the line $$2 \ x \ + \ 4 \ y = 10$$
(A) $$(2, \ 1)$$
(B) $$(– \ 1, \ 3)$$
(C) $$(– \ 2, \ 2)$$
(D) $$(2, \ 2)$$
20- $$5 \ + \ 8 \ × \ (– \ 2) \ – \ \left[ \ 4 \ + \ 22 \ × \ 5 \ \right] \ ÷ \ 6 =$$ ?
(A) -30
(B) - 30
(C) -30
(D) - 30
21- The price of a car was $$20,000$$ in $$2014, \ 16,000$$ in $$2015$$ and $$12,800$$ in $$2016$$. What is the rate of depreciation of the price of car per year?
(A) $$15\%$$
(B) $$20\%$$
(C) $$25\%$$
(D) $$30\%$$
22- What is the equivalent temperature of $$104^°$$F in Celsius?
C $$= \frac{5}{9}$$ (F $$– \ 32$$)
(A) $$32$$
(B) $$40$$
(C) $$48$$
(D) $$68$$
23- The square of a number is $$\frac{25}{64}$$. What is the cube of that number?
(A) $$\frac{5}{8}$$
(B) $$\frac{25}{254}$$
(C) $$\frac{125}{512}$$
(D) $$\frac{125}{64}$$

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24- What is the surface area of the cylinder below?
(A) $$48 \ π$$
(B) $$57 \ π$$
(C) $$66 \ π$$
(D) $$288 \ π$$
25- What is the value of $$x$$ in the following equation?
$$\frac{2}{3} \ x \ + \ \frac{1}{6}= \frac{1}{3}$$
(A) $$6$$
(B) $$\frac{1}{2}$$
(C) $$\frac{1}{3}$$
(D) $$\frac{1}{4}$$
26- The average of five numbers is $$24$$. If a sixth number $$42$$ is added, then, what is the new average?
(A) $$25$$
(B) $$26$$
(C) $$27$$
(D) $$28$$
27- Anita’s trick–or–treat bag contains $$12$$ pieces of chocolate, $$18$$ suckers, $$18$$ pieces of gum, $$24$$ pieces of licorice. If she randomly pulls a piece of candy from her bag, what is the probability of her pulling out a piece of sucker?
(A) $$\frac{1}{3}$$
(B) $$\frac{1}{4}$$
(C) $$\frac{1}{6}$$
(D) $$\frac{1}{12}$$
28- Which of the following shows the numbers in descending order?
$$\frac{2}{3} , \ 0.68 , \ 67\% , \ \frac{4}{5}$$
(A) $$67\%, \ 0.68, \frac{2}{3}, \ \frac{4}{5}$$
(B) $$67\%, \ 0.68, \frac{4}{5}, \ \frac{2}{3}$$
(C) $$0.68, \ 67\%, \ \frac{2}{3}, \ \frac{4}{5}$$
(D) $$\frac{2}{3}, \ 67\%, \ 0.68, \ \frac{4}{5}$$
29- Mr. Carlos family are choosing a menu for their reception. They have $$3$$ choices of appetizers, $$5$$ choices of entrees, $$4$$ choices of cake. How many different menu combinations are possible for them to choose?
(A) $$12$$
(B) $$32$$
(C) $$60$$
(D) $$120$$
30- Four one – foot rulers can be split among how many users to leave each with $$\frac{1}{6}$$ of a ruler?
(A) $$4$$
(B) $$6$$
(C) $$12$$
(D) $$24$$
31- What is the area of a square whose diagonal is $$8$$?
(A) $$16$$
(B) $$32$$
(C) $$36$$
(D) $$64$$
32- The ratio of boys and girls in a class is $$4:7$$. If there are $$44$$ students in the class, how many more boys should be enrolled to make the ratio $$1:1$$?
(A) $$8$$
(B) $$10$$
(C) $$12$$
(D) $$14$$
33- What is the area of the shaded region?
(A) $$31$$ ft.$$^2$$
(B) $$40$$ ft.$$^2$$
(C) $$64$$ ft.$$^2$$
(D) $$80$$ ft.$$^2$$
34- Mr. Jones saves $$2,500$$ out of his monthly family income of $$55,000$$. What fractional part of his income does he save?
(A) $$\frac{1}{22}$$
(B) $$\frac{1}{12}$$
(C) $$\frac{3}{25}$$
(D) $$\frac{2}{15}$$
35- When a number is subtracted from $$24$$ and the difference is divided by that number, the result is $$3$$. What is the value of the number?
(A) $$2$$
(B) $$4$$
(C) $$6$$
(D) $$12$$
36- What is the volume of a box with the following dimensions?
Hight $$= 4$$ cm       Width $$= 5$$ cm       Length $$= 6$$ cm
(A) $$15$$ cm$$^3$$
(B) $$60$$ cm$$^3$$
(C) $$90$$ cm$$^3$$
(D) $$120$$ cm$$^3$$
37- In two successive years, the population of a town is increased by $$15\%$$ and $$20\%$$. What percent of its population is increased after two years?
(A) $$32$$
(B) $$35$$
(C) $$38$$
(D) $$68$$
38- In a school, the ratio of number of boys to girls is $$4:5$$. If the number of boys is $$180$$, what is the total number of students in the school?
(A) 405
(B) 405
(C) 405.0
39- How many tiles of $$8$$ cm$$^2$$ is needed to cover a floor of dimension $$6$$ cm by $$24$$ cm?
(A) $$6$$
(B) $$12$$
(C) $$18$$
(D) $$24$$
40- The radius of the following cylinder is $$8$$ inches and its height is $$12$$ inches. What is the surface area of the cylinder?
(A) $$96 \ π$$ cm$$^2$$
(B) $$192 \ π$$ cm$$^2$$
(C) $$320 \ π$$ cm$$^2$$
(D) $$1004.8 \ π$$ cm$$^2$$
 1- Choice B is correct The correct answer is $$2$$The equation of a line in slope intercept form is: $$y=m \ x \ + \ b$$Solve for $$y$$.$$2 \ x \ - \ y=12 ⇒$$$$- \ y=12 \ - \ 2 \ x ⇒$$$$y=(12 \ - \ 2 \ x) \ ÷ \ (- \ 1) ⇒$$$$y=2 \ x \ - \ 6$$The slope of this line is $$2$$.Parallel lines have same slopes. 2- Choice C is correct The correct answer is $$36$$Simplify:$$5 \ (x\ - \ 2 \ y) \ + \ (2 \ - \ x)^2 =$$$$(5 \ x \ - \ 10 \ y) \ + \ (4 \ - \ 4 \ x \ + \ x^2) =$$$$x \ - \ 10 \ y \ + \ 4 \ + \ x^2$$When $$x=3$$ and $$y=- \ 2$$ ,therefore:$$x \ - \ 10 \ y \ + \ 4 \ + \ x^2 =3 \ + \ 20 \ + \ 4 \ + \ 9 =36$$ 3- Choice C is correct The correct answer is $$87.5$$average (mean) $$=\frac{sum \ of \ terms}{number \ of \ terms}⇒$$$$88 = \frac{sum \ of \ terms}{50} ⇒$$sum $$= 88 \ × \ 50 = 4400$$The difference of $$94$$ and $$69$$ is $$25$$.Therefore, $$25$$ should be subtracted from the sum.$$4400 \ – \ 25 = 4375$$mean $$=\frac{sum \ of \ terms}{number \ of \ terms}⇒$$mean $$=\frac{4375}{50 }= 87.5$$ 4- Choice D is correct The correct answer is $$729$$If the length of the box is $$27$$, then the width of the box is one third of it, $$9$$, and the height of the box is $$3$$ (one third of the width).The volume of the box is:$$V = lwh = (27) \ (9) \ (3) = 729$$ 5- Choice C is correct The correct answer is $$475$$Add the first $$5$$ numbers.$$40 \ + \ 45 \ + \ 50 \ + \ 35 \ + \ 55 = 225$$To find the distance traveled in the next $$5$$ hours, multiply the average by number of hours.Distance $$=$$ Average $$×$$ Rate $$= 50 \ × \ 5 = 250$$Add both numbers. $$250 \ + \ 225 = 475$$ 6- Choice C is correct The correct answer is $$240$$The ratio of boy to girls is $$2:3$$. Therefore, there are $$2$$ boys out of $$5$$ students.To find the answer, first divide the total number of students by $$5$$, then multiply the result by $$2$$. $$600 \ ÷ \ 5 = 120 ⇒$$$$120 \ × \ 2 = 240$$ 7- Choice C is correct The correct answer is $$130$$The perimeter of the trapezoid is $$54$$ cm.Therefore, the missing side (high) is $$= 54 \ – \ 18 \ – \ 12 \ – \ 14 = 10$$Area of a trapezoid: A $$= \frac{1}{2} \ h \ (b1 \ + \ b2) = \frac{1}{2} \ (10) \ (12 \ + \ 14) = 130$$ 8- Choice A is correct The correct answer is $$I \ > \ 2000 \ x \ + \ 24000$$Let $$x$$ be the number of years.Therefore, $$2,000$$ per year equals $$2000 \ x$$. starting from $$24,000$$ annual salary means you should add that amount to $$2000 \ x$$. Income more than that is:$$I \ > \ 2000 \ x \ + \ 24000$$ 9- Choice D is correct Solve for $$x$$.$$- \ 2 \ ≤ \ 2 \ x \ - \ 4 \ < \ 8 ⇒$$(add $$4$$ all sides) $$-\ 2 \ + \ 4 \ ≤ \ 2 \ x \ - \ 4 \ + \ 4 \ < \ 8 \ + \ 4 ⇒$$ $$2 \ ≤ \ 2 \ x \ < \ 12 ⇒$$(divide all sides by $$2$$) $$1 \ ≤ \ x \ < \ 6$$$$x$$ is between $$1$$ and $$6$$. 10- Choice A is correct The correct answer is $$120 \ x \ + \ 14,000 \ ≤ \ 20,000$$Let $$x$$ be the number of new shoes the team can purchase. Therefore, the team can purchase $$120 \ x$$.The team had $$20,000$$ and spent $$14000$$.Now the team can spend on new shoes $$6000$$ at most. Now, write the inequality:$$120 \ x \ + \ 14,000 \ ≤ \ 20,000$$ 11- Choice B is correct The correct answer is $$\frac{1}{4}$$The options to get sum of $$6: \ (1$$ & $$5)$$ and $$(5$$ & $$1), \ (2$$ & $$4)$$ and $$(4$$ & $$2), \ (3$$ & $$3)$$, so we have $$5$$ optionsThe options to get sum of $$9: \ (3$$ & $$6)$$ and $$(6$$ & $$3), \ (4$$ & $$5)$$ and $$(5$$ & $$4)$$, we have $$4$$ options.To get the sum of $$6$$ or $$9$$ for two dice, we have $$9$$ options: $$5 \ + \ 4 = 9$$Since, we have $$6 \ × \ 6 = 36$$ total options, the probability of getting a sum of $$6$$ and $$9$$ is $$9$$ out of $$36$$ or $$\frac{9}{36}=\frac{1}{4}$$. 12- Choice C is correct The correct answer is $$8$$Use formula of rectangle prism volume.V $$=$$ (length) (width) (height) $$⇒ 2000 = (25) \ (10)$$ (height) $$⇒$$ height $$= 2000 \ ÷ \ 250 = 8$$ 13- Choice A is correct For each option, choose a point in the solution part and check it on both inequalities. A. Point $$(– \ 4, \ – \ 4)$$ is in the solution section. Let’s check the point in both inequalities. $$– \ 4 \ ≤ \ – \ 4 \ + \ 4$$, It works$$2 \ (– \ 4) \ + \ (– \ 4) \ ≤ \ – \ 4 ⇒ – \ 12 \ ≤ \ – \ 4$$, it works (this point works in both)B. Let’s choose this point $$(0, \ 0)$$ $$0 \ ≤ \ 0 \ + \ 4$$, It works$$2 \ (0) \ + \ (0) \ ≤ \ – \ 4$$, That’s not true!C. Let’s choose this point $$(– \ 5, \ 0)$$ $$0 \ ≤ \ – \ 5 \ + \ 4$$, That’s not true!D. Let’s choose this point $$(0, \ 5)$$ $$5 \ ≤ \ 0 \ + \ 4$$, That’s not true! 14- Choice C is correct The correct answer is $$1800$$Use simple interest formula:$$I=prt$$($$I =$$ interest, $$p =$$ principal, $$r =$$ rate, $$t =$$ time)$$I=(8000) \ (0.045) \ (5)=1800$$ 15- Choice B is correct The correct answer is $$\frac{1}{4}$$The probability of choosing a Hearts is $$\frac{13}{52} =\frac{1}{4}$$ 16- Choice C is correct The correct answer is $$8$$ hours and $$24$$ minutesUse distance formula:Distance $$=$$ Rate $$×$$ time $$⇒ 420 = 50 \ ×$$ T, divide both sides by $$50$$.$$\frac{420}{50} =$$ T $$⇒$$ T $$= 8.4$$ hours.Change hours to minutes for the decimal part. $$0.4$$ hours $$= 0.4 \ × \ 60 = 24$$ minutes. 17- Choice C is correct The correct answer is $$472$$$$11 \ × \ 36 \ + \ 6 \ × \ 12 \ + \ 4 = 472$$ 18- Choice D is correct The correct answer is $$(200) \ (0.85) \ (0.85)$$To find the discount, multiply the number by ($$100\% \ –$$ rate of discount).Therefore, for the first discount we get: $$(200) (100\% \ – \ 15\%) = (200) \ (0.85) = 170$$For the next $$15\%$$ discount: $$(200) \ (0.85) \ (0.85)$$ 19- Choice B is correct The correct answer is $$(- \ 1, \ 3)$$Input $$(- \ 1, \ 3)$$ in the $$2 \ x \ + \ 4 \ y = 10$$ formula instead of $$x$$ and $$y$$. So we have:$$2(- \ 1) \ + \ 4 \ (3) = 10$$$$- \ 2 \ + \ 12 = 10$$ 20- Choice D is correct The correct answer is $$- \ 30$$Use PEMDAS (order of operation):$$5 \ + \ 8 \ × \ (– \ 2) \ – \ [ \ 4 \ + \ 22 \ × \ 5 \ ] \ ÷ \ 6 =$$$$5 \ + \ 8 \ × \ (– \ 2) \ – \ [ \ 4 \ + \ 110 \ ] \ ÷ \ 6 =$$$$5 \ + \ 8 \ × \ (– \ 2) \ – \ [ \ 114 \ ] \ ÷ \ 6 =$$$$5 \ + \ (– \ 16) \ – \ 19 =$$$$5 \ + \ (– \ 16) \ – \ 19 =$$$$– \ 11 \ – \ 19 = \ – \ 30$$ 21- Choice B is correct The correct answer is $$20\%$$Use this formula: Percent of Change$$\frac{New \ Value-Old \ Value}{Old \ Value} \ × \ 100\%$$$$\frac{16000 \ - \ 20000}{20000} \ × \ 100\% = 20\%$$ and $$\frac{12800 \ - \ 16000}{16000} \ × \ 100\% = 20\%$$ 22- Choice B is correct The correct answer is $$40$$Plug in $$104$$ for F and then solve for C.C $$= \frac{5}{9}$$ (F $$– \ 32) ⇒$$C $$= \frac{5}{9} \ (104 \ – \ 32) ⇒$$C $$= \frac{5}{9} \ (72) = 40$$ 23- Choice C is correct The correct answer is $$\frac{125}{512}$$The square of a number is $$\frac{25}{64}$$, then the number is the square root of $$\frac{25}{64}$$$$\sqrt{\frac{25}{64}}= \frac{5}{8}$$The cube of the number is:$$(\frac{5}{8})^3 = \frac{125}{512}$$ 24- Choice C is correct The correct answer is $$66 \ π$$Surface Area of a cylinder $$= 2 \ π \ r \ (r \ + \ h)$$,The radius of the cylinder is $$3 \ (6 \ ÷ \ 2)$$ inches and its height is $$8$$ inches.Therefore, Surface Area of a cylinder $$= 2 \ π \ (3) \ (3 \ + \ 8) = 66 \ π$$ 25- Choice D is correct The correct answer is $$\frac{1}{4}$$$$\frac{2}{3} \ x \ + \ \frac{1}{6}=\frac{1}{3}⇒$$$$\frac{2}{3} \ x= \frac{1}{6} ⇒$$$$x= \frac{1}{6} \ × \ \frac{3}{2} ⇒ x= \frac{1}{4}$$ 26- Choice C is correct The correct answer is $$27$$Solve for the sum of five numbers. average $$=\frac{sum \ of \ terms}{number \ of \ terms} ⇒$$$$24 = \frac{sum \ of \ 5 \ numbers}{5} ⇒$$sum of $$5$$ numbers $$= 24 \ × \ 5 = 120$$The sum of $$5$$ numbers is $$120$$.If a sixth number $$42$$ is added, then the sum of $$6$$ numbers is $$120 \ + \ 42 = 162$$average $$= \frac{sum \ of \ terms}{number \ of \ terms}= \frac{162}{6} = 27$$ 27- Choice B is correct The correct answer is $$\frac{1}{4}$$Probability $$= \frac{number \ of \ desired \ outcomes}{number \ of \ total \ outcomes}= \frac{18}{12 \ + \ 18 \ + \ 18 \ + \ 24} = \frac{18}{72} = \frac{1}{4}$$ 28- Choice D is correct The correct answer is $$\frac{2}{3}, \ 67\%, \ 0.68, \ \frac{4}{5}$$Change the numbers to decimal and then compare.$$\frac{2}{3} = 0.666…$$$$0.68$$ $$67\% = 0.67$$$$\frac{4}{5} = 0.80$$Therefore: $$\frac{4}{5} \ > \ 68\% \ > \ 0.67 \ > \frac{2}{3}$$ 29- Choice C is correct The correct answer is $$60$$To find the number of possible outfit combinations, multiply number of options for each factor:$$3 \ × \ 5 \ × \ 4 = 60$$ 30- Choice D is correct The correct answer is $$24$$$$4 \ ÷ \ \frac{1}{6} = 24$$ 31- Choice B is correct The correct answer is $$32$$The diagonal of the square is $$8$$.Let $$x$$ be the side. Use Pythagorean Theorem: $$a^2 \ + \ b^2 = c^2$$$$x^2 \ + \ x^2 = 82 ⇒$$$$2 \ x^2 = 82 ⇒$$$$2 \ x^2 = 64 ⇒$$$$x^2 = 32 ⇒$$$$x= \sqrt{32}$$The area of the square is:$$\sqrt{32} \ × \ \sqrt{32} = 32$$ 32- Choice C is correct The correct answer is $$12$$The ratio of boy to girls is $$4:7$$.Therefore, there are $$4$$ boys out of $$11$$ students.To find the answer, first divide the total number of students by $$11$$, then multiply the result by $$4$$. $$44 \ ÷ \ 11 = 4 ⇒$$$$4 \ × \ 4 = 16$$There are $$16$$ boys and $$28 \ (44 \ – \ 16)$$ girls. So, $$12$$ more boys should be enrolled to make the ratio $$1:1$$ 33- Choice B is correct The correct answer is $$40$$ ft.$$^2$$Use the area of rectangle formula $$(s=a \ × \ b)$$.To find area of the shaded region subtract the smaller rectangle from bigger rectangle.S$$_{1} \ –$$ S$$_{2} = (10$$ ft $$× \ 8$$ ft) $$– \ (5$$ ft $$× \ 8$$ ft) $$⇒$$ S$$_{1} \ –$$ S$$_{2} = 40$$ ft.$$^2$$ 34- Choice A is correct The correct answer is $$\frac{1}{22}$$$$2,500$$ out of $$55,000$$ equals to $$\frac{2500}{55000} = \frac{25}{550} = \frac{1}{22}$$ 35- Choice C is correct The correct answer is $$6$$Let the number be $$x$$. Then:$$\frac{24 \ - \ x}{x} = 3→$$$$3 \ x=24 \ - \ x→$$$$4 \ x=24→$$$$x = 6$$ 36- Choice D is correct The correct answer is $$120$$ cm$$^3$$Volume of a box $$=$$ length $$×$$ width $$×$$ height $$= 4 \ × \ 5 \ × \ 6 = 120$$ cm$$^3$$ 37- Choice C is correct The correct answer is $$38$$The population is increased by $$15\%$$ and $$20\%$$.$$15\%$$ increase changes the population to $$115\%$$ of original population. For the second increase, multiply the result by $$120\%$$.$$(1.15) \ ×\ (1.20) = 1.38 = 138\%$$$$38$$ percent of the population is increased after two years. 38- Choice C is correct The correct answer is $$405$$The ratio of boy to girls is $$4:5$$.Therefore, there are $$4$$ boys out of $$9$$ students.To find the answer, first divide the number of boys by $$4$$, then multiply the result by $$9$$. $$180 \ ÷ \ 4 = 45 ⇒$$$$45 \ × \ 9 = 405$$ 39- Choice C is correct The correct answer is $$18$$The area of the floor is: $$6$$ cm $$× \ 24$$ cm $$= 144$$ cm$$^2$$The number of tiles needed $$= 144 \ ÷ \ 8 = 18$$ 40- Choice D is correct The correct answer is $$1004.8$$Surface Area of a cylinder $$= 2 \ π \ r \ (r \ + \ h)$$,The radius of the cylinder is $$8$$ inches and its height is $$12$$ inches.$$π$$ is about $$3.14$$. Then: Surface Area of a cylinder $$= 2 \ (π) \ (8) \ (8 \ + \ 12) =$$$$320 \ π = 1004.8$$

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