Greatest Common Factor of 248 and 4715
GCF(248, 4715) = 1, Greatest common factor of 248 and 4715 is 1. Greatest Common Factor or Greatest Common Divisor of two numbers is the largest integer by which both the numbers can be divided. There are two different methods to calculate Greatest Common Factor of 248 and 4715. Greatest Common Factor by prime factorization method and Greatest Common Factor by matching factors method.
Greatest Common Factor of 248 and 4715 by prime factorization method
We will first find the prime factorization of 248 and 4715.
Prime Factorization of 248 is 1, 2, 2, 2, 31 and Prime Factorization of 4715 is 1, 5, 23, 41.
- Factorize\( (248) = \) \(1\times 2\times 2\times 2\times 31\)
- Factorize\( (4715) = \) \(1\times 5\times 23\times 41\)
Now we need to find any which are common for each number (1, 1) and multiply these numbers together.
\(GCF(248, 4715) = 1\times 1 = 1\).
Greatest Common Factor of 248 and 4715 by matching factors method
List of positive integers factors of 248 leaving a remainder zero is 1, 2, 4, 8, 31, 62, 124, 248
List of positive integers factors of 4715 leaving a remainder zero is 1, 5, 23, 41, 115, 205, 943, 4715
As you can see, 1 is the greatest and common number that 248 and 4715 divides into.
So the greatest common factor 248 and 4715 is 1.
\(GCF(248, 4715) = 1\).
If you want to learn more about greatest common divisor, take a look at the Wikipedia page.
