How to Solve Quadratic Equations?
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A quadratic equation can be written as \(ax^2 + bx + c = 0\), where \(a
e 0\). The solutions, or roots, are the values of \(x\) that make the equation true.
Main Solving Methods
Factoring: Move all terms to one side, factor the polynomial, and use the zero product property.
Square-root property: If \((x - h)^2 = k\), then \(x - h = \pm\sqrt{k}\).
Completing the square: Add the number that makes a perfect-square trinomial, then use square roots.
Quadratic formula: For \(ax^2 + bx + c = 0\), use \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). The discriminant \(b^2 - 4ac\) tells whether the roots are real or complex.
Example
Solve \(x^2 - 5x - 14 = 0\).
- Factor: \(x^2 - 5x - 14 = (x - 7)(x + 2)\).
- Set each factor equal to zero: \(x - 7 = 0\) or \(x + 2 = 0\).
- Solve: \(x = 7\) or \(x = -2\).
The solutions are \(x = -2\) and \(x = 7\).
Quadratic Equations
Think of this lesson as more than a rule to memorize. Quadratic Equations is about undoing operations while keeping both sides balanced. A strong student does not rush to the first formula on the page; they pause, identify the structure of the problem, and then choose the tool that matches that structure. That pause is what prevents most mistakes.
A quadratic usually has the form \(ax^2+bx+c\). Factoring, graphing, square roots, and the quadratic formula are different tools for the same family of problems.
Here is the teacher way to approach the topic. First, read the problem slowly and underline the information that is actually given. Next, name the target: are you finding a value, simplifying an expression, comparing two quantities, solving for a variable, or interpreting a graph? Once the target is clear, the calculation becomes much less mysterious because every step has a job.
- Clear clutter such as parentheses or fractions.
- Collect like terms.
- Undo operations in reverse order.
- Substitute the answer back or test a point.
A helpful habit is to say what each number represents before using it. For example, if a number is a denominator, a radius, a slope, a common difference, or a coefficient, it should not be treated like an ordinary loose number. Its role tells you where it belongs in the formula. This is especially important on ACT-style questions because many wrong answer choices come from using the right numbers in the wrong places.
Another good habit is to keep the work organized vertically. Write one clean line for substitution, one line for simplifying, and one line for the final answer. If the problem has units, keep the units attached. If the problem has signs, exponents, or parentheses, copy them carefully from one line to the next. Most errors in this topic are not caused by a hard idea; they are caused by dropping a negative sign, combining unlike terms, using the wrong denominator, or skipping a check.
When you finish, ask a quick reasonableness question. Should the answer be positive or negative? Should it be larger or smaller than the original number? Does it fit the graph, table, shape, or equation? Can you plug it back into the original problem? This final check turns the lesson from a procedure into understanding.
On a test, the goal is not to write the longest solution. The goal is to write enough clear work that you can see the structure, avoid traps, and recover quickly if one line goes wrong. Practice the examples below with that mindset: identify the type of problem, choose the matching rule, show the substitution, simplify carefully, and check the answer before moving on.
Free printable Worksheets
Exercises for Quadratic Equations
1) Solve: \(x^2 - 9 = 0\)
2) Solve: \(x^2 + 5x + 6 = 0\)
3) Solve: \(x^2 - 7x + 12 = 0\)
4) Solve: \(x^2 + 2x - 15 = 0\)
5) Solve: \(2x^2 - 8x = 0\)
6) Solve: \(3x^2 + 12x + 12 = 0\)
7) Solve: \(x^2 = 49\)
8) Solve: \((x - 5)^2 = 16\)
9) Solve: \(x^2 - 6x + 5 = 0\)
10) Solve: \(2x^2 + 7x + 3 = 0\)
11) Solve: \(3x^2 - 5x - 2 = 0\)
12) Solve: \(4x^2 - 25 = 0\)
13) Solve: \(x^2 + 8x + 7 = 0\)
14) Solve: \(x^2 - 4x - 12 = 0\)
15) Solve: \(5x^2 + 6x + 1 = 0\)
16) Solve: \(x^2 + 6x + 1 = 0\)
17) Solve: \(2x^2 - 4x - 7 = 0\)
18) Solve: \(3x^2 + 2x + 5 = 0\)
19) Solve: \(x^2 - 10x + 21 = 0\)
20) Solve: \(4x^2 - 12x + 9 = 0\)
1)Factor \(x^2 - 9 = 0\).
Rewrite it as \((x - 3)(x + 3) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -3, 3\).
2)Factor \(x^2 + 5x + 6 = 0\).
Rewrite it as \((x + 2)(x + 3) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -3, -2\).
3)Factor \(x^2 - 7x + 12 = 0\).
Rewrite it as \((x - 3)(x - 4) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = 3, 4\).
4)Factor \(x^2 + 2x - 15 = 0\).
Rewrite it as \((x + 5)(x - 3) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -5, 3\).
5)Factor \(2x^2 - 8x = 0\).
Rewrite it as \(2x(x - 4) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = 0, 4\).
6)Factor \(3x^2 + 12x + 12 = 0\).
Rewrite it as \(3(x + 2)^2 = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -2\).
7)Use the square-root property on \(x^2 = 49\).
Take both square roots: \(x = \pm 7\).
Solve the resulting linear equations.
Answer: \(x = -7, 7\).
8)Use the square-root property on \((x - 5)^2 = 16\).
Take both square roots: \(x - 5 = \pm 4\).
Solve the resulting linear equations.
Answer: \(x = 1, 9\).
9)Factor \(x^2 - 6x + 5 = 0\).
Rewrite it as \((x - 1)(x - 5) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = 1, 5\).
10)Factor \(2x^2 + 7x + 3 = 0\).
Rewrite it as \((2x + 1)(x + 3) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -3, -\frac{1}{2}\).
11)Factor \(3x^2 - 5x - 2 = 0\).
Rewrite it as \((3x + 1)(x - 2) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -\frac{1}{3}, 2\).
12)Factor \(4x^2 - 25 = 0\).
Rewrite it as \((2x - 5)(2x + 5) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -\frac{5}{2}, \frac{5}{2}\).
13)Factor \(x^2 + 8x + 7 = 0\).
Rewrite it as \((x + 1)(x + 7) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -7, -1\).
14)Factor \(x^2 - 4x - 12 = 0\).
Rewrite it as \((x - 6)(x + 2) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -2, 6\).
15)Factor \(5x^2 + 6x + 1 = 0\).
Rewrite it as \((5x + 1)(x + 1) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = -1, -\frac{1}{5}\).
16)Complete the square for \(x^2 + 6x + 1 = 0\).
Move the constant: \(x^2 + 6x = -1\). Add \(9\): \((x + 3)^2 = 8\).
Take square roots: \(x + 3 = \pm 2\sqrt{2}\).
Answer: \(x = -3 \pm 2\sqrt{2}\).
17)Use the quadratic formula on \(2x^2 - 4x - 7 = 0\): \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
Substitute \(a\), \(b\), and \(c\), then simplify: \(x = \frac{4 \pm \sqrt{72}}{4}\).
Answer: \(x = 1 \pm \frac{3\sqrt{2}}{2}\).
18)Use the quadratic formula on \(3x^2 + 2x + 5 = 0\): \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
Substitute \(a\), \(b\), and \(c\), then simplify: \(x = \frac{-2 \pm \sqrt{-56}}{6}\).
Answer: \(x = \frac{-1 \pm i\sqrt{14}}{3}\).
19)Factor \(x^2 - 10x + 21 = 0\).
Rewrite it as \((x - 3)(x - 7) = 0\).
Set each factor equal to zero and solve.
Answer: \(x = 3, 7\).
20)Factor \(4x^2 - 12x + 9 = 0\).
Rewrite it as \((2x - 3)^2 = 0\).
Set each factor equal to zero and solve.
Answer: \(x = \frac{3}{2}\).
Quadratic Equations Practice Quiz