Solving Systems of Equations by Substitution Course

Solving Systems of Equations by Substitution

Consider the system of equations
$x\  – \ y\ = \ 1\ –\ 2\ x\  +\  y \ = \ 6$
Substitute $\ x\  = \ 1\  –\ y\ $ in the second equation
$-2(\ 1\ -\ y\ ) + y = 5 y = 2$ 
Substitute$\ y\  = \ 2\  in \ x\  = \ 1\  +\  y$
$\ x\  = \ 1\  + \ 2\  = \ 3$

Example:

$–\  2\ x\  –\  2\ y\  = -\ 13$
$–\  4\ x\  +\  2\ y\  = \ 10$

$(\ 0\ .\ 5\ ,\ 6\ )$