ACT Math Practice Test

The correct answer is \(10\)
Write the numbers in order:
\(3, 5, 8, 10, 13, 15, 19\)
Since we have \(7\) numbers (\(7\) is odd), then the median is the number in the middle, which is \(10\).

The correct answer is \(50\) cm\(^2\)
The diagonal of the square is \(10\). 
Let \(x\) be the side. 
Use Pythagorean Theorem: \(a^2 \ + \ b^2 = c^2\)
\(x^2 \ + \ x^2 = 10^2 ⇒\)
\(2 \ x^2 = 10^2 ⇒\)
\(2 \ x^2 = 100⇒\)
\(x^2 = 50 ⇒x= \sqrt{50}\)
The area of the square is: \(\sqrt{50} \ × \ \sqrt{50} = 50\)

The correct answer is \(6\)
Let’s review the options provided.
A. \(4\). In \(4\) years, David will be \(46\) and Ava will be \(10\). \(46\) is not \(4\) times \(10\).
B. \(6\). In \(6\) years, David will be \(48\) and Ava will be \(12\). \(48\) is \(4\) times \(12\)!
C. \(8\). In \(8\) years, David will be \(80\) and Ava will be \(14\). \(50\) is not \(4\) times \(14\).
D. \(10\). In \(10\) years, David will be \(52\) and Ava will be \(16\). \(52\) is not \(4\) times \(16\).
E. \(14\). In \(14\) years, David will be \(56\) and Ava will be \(20\). \(56\) is not \(4\) times \(20\).

The correct answer is \(7\) hours and \(12\) minutes
Use distance formula:
Distance \(=\) Rate \(×\) time \(⇒ 360 = 50 \ ×\) T, divide both sides by \(50\).
\(\frac{360 }{50} =\) T \(⇒\) T \(= 7.2\) hours.
Change hours to minutes for the decimal part.
\(0.2\) hours \(= 0.2 \ ×\ 60 = 12\) minutes.

The correct answer is \(0.77\) D
To find the discount, multiply the number by (\(100\% \ –\) rate of discount).
Therefore, for the first discount we get: (D) \((100\% \ – \ 30\%) =\) (D) \((0.70) = 0.70\) D
For increase of \(10\%\): (\(0.70\) D) \((100\% \ + \ 10\%) = (0.70\) D\() (1.10) = 0.77\) D \(= 77\%\) of D

The correct answer is \(\frac{5}{6} \ > \ 0.8\)
Check each option.
A. \(\frac{3}{4} \ > \ 0.8\)      \(\frac{3}{4}=0.75\) and it is less than \(0.8\). Not true!
B. \(10\% = \frac{2}{5}\)      \(10\% = \frac{1}{10} \ < \ \frac{2}{5}\). Not True!
C. \(3 \ < \ \frac{5}{2}\)         \(\frac{5}{2}=2.5 \ < \ 3\). Not True!
D. \(\frac{5}{6} \ > \ 0.8\)      \(\frac{5}{6}=0.8333\)… and it is greater than \(0.8\). Bingo!
E. None of them above Not True!

The correct answer is \(8 \ ≤ \ x \ ≤ \ 16\)
\(|x \ - \ 12| \ ≤ \ 4→\)
\(- \ 4 \ ≤ \ x \ - \ 12 \ ≤ \ 4→\)
\(- \ 4 \ + \ 12 \ ≤ \ x \ - \ 12 \ + \ 12 \ ≤ \ 4 \ + \ 12 →\)
\(8 \ ≤ \ x \ ≤ \ 16\)

The correct answer is \(0.02125\)
\(2000\) times the number is \(42.5\).
Let \(x\) be the number, then:
\(2000 \ x=42.5, \ x=\frac{42.5}{2000}=0.02125\)

The correct answer is \(54\)
The area of the floor is: \(9\) cm \(× \ 36\) cm \(= 324\) cm
The number is tiles needed \(= 324 \ ÷ \ 6 = 54\)

The correct answer is cos \(A =\) sin \(B\)
By definition, the sine of any acute angle is equal to the cosine of its complement.
Since, angle \(A\) and \(B\) are complementary angles, therefore: cos \(A =\) sin \(B\)

The correct answer is \(12\%\)
The percent of girls playing tennis is: \(40\% \ × \ 30\% = 0.40 \ × \ 0.30= 0.12 = 12\%\)

The correct answer is \(5^{\frac{5}{2}}\)
\(5^{\frac{7}{4}} \ × \ 5^{\frac{3}{4}} = 5^{\frac{7}{4} \ + \ \frac{3}{4}} = 5^{\frac{10}{4}}=5^{\frac{5}{2}}\)

The correct answer is \(0.04 \ x \ + \ 6500\)
Employer’s revenue: \(0.04 \ x \ + \ 6500\)

The correct answer is \(60\) cm
One liter \(=1,000\) cm\(^3→ 6\) liters \(=6000\) cm\(^3\)
\(6000=20 \ × \ 5 \ × \ h→h=\frac{6000}{100}=60\) cm

The correct answer is \(33\)
Five years ago, Amy was three times as old as Mike.
Mike is \(12\) years now.
Therefore, \(5\) years ago Mike was \(7\) years. 
Five years ago, Amy was: \(A=4 \ × \ 7=28\) 
Now Amy is \(33\) years old: \(28 \ + \ 5 = 33\)

The correct answer is \(152^\circ\)
\(x=25 \ + \ 127=152\)

The correct answer is I and III only
I. \(|a| \ < \ 1→ \ - \ 1 \ < \ a\ < \ 1\)
Multiply all sides by \(b\).
Since, \(b \ > \ 0→ \ - \ b \ < \ b \ a \ < \ b\) (it is true!)
II. Since, \(- \ 1 \ < \ a \ < \ 1\), and \(a \ < \ 0→ \ - \ a \ > \ a^2 \ > \ a\) (plug in \(\frac{- \ 1}{2}\), and check!) (It’s false)
III. \(- \ 1 \ < \ a \ < \ 1\), multiply all sides by \(2\), then: \(- \ 2 \ < \ 2 \ a \ < \ 2\) 
Subtract \(3\) from all sides. Then:
\(- \ 2 \ - \ 3 \ < \ 2 \ a \ - \ 3 \ < \ 2 \ - \ 3→ \ - \ 5 \ < \ 2 \ a \ - \ 3 \ < \ - \ 1\) (It is true!)

The correct answer is \(4\) and \(5\)
Solve for \(x\).
\(x^3 \ + \ 18=130, \ x^3=112\)
Let’s review the choices. 
A. \(1\) and \(2\).    \(13 = 1\) and       \(23 = 8, \ 112\) is not between these two numbers.
B. \(2\) and \(3\).    \(23 = 8\) and       \(33 = 27, \ 112\) is not between these two numbers.
C. \(3\) and \(4\).    \(33 = 27\) and     \(43 = 64, \ 112\) is not between these two numbers.
D. \(4\) and \(5\).    \(43 = 64\) and     \(53 = 125, \ 112\) is between these two numbers.
E. \(5\) and \(6\).    \(53 = 125\) and   \(63 = 216, \ 112\) is not between these two numbers.

The correct answer is \(y \ + \ 2 \ x=𝑧\) 
\(x\) and \(z\) are colinear.
\(y\) and \(5 \ x\) are colinear.
Therefore:
\(x \ + \ z=y \ + \ 3 \ x\),subtract \(x\) from both sides,then,\(z=y \ + \ 2 \ x\)

The correct answer is \(- \ 8\)
Solving Systems of Equations by Elimination m8ethod.
\(\cfrac{\begin{align} 2 \ x \ -  \ y \ = \ - \ 48 \\ - \ x \ + \ 2 \ y \ = \ 12 \end{align}}{} \)
Multiply the second equation by \(2\), then add it to the first equation.
\(\cfrac{\begin{align} 2 \ x \ -  \ y \ = \ - \ 48 \\ 2 \ ( \ - \ x \ + \ 2 \ y \ = \ 12) \end{align}}{}\) 
\(\cfrac{ \begin{align} 2 \ x \ -  \ y \ = \ - \ 48 \\ - \ 2 \ x \ + \ 4\ y \ = \ 24 \end{align} } ⇒\) add the equations
\({\begin{align} 3\ y \ = - \ 24 \\ ⇒ y \ = -\ 8 \end{align}} \)

The correct answer is \(81\)
\(30\%\) of \(60\) equals to: \(0.30 \ × \ 60=18\)
\(15\%\) of \(430\) equals to: \(0.15 \ × \ 420=63\)
\(30\%\) of \(60\) is added to \(15\%\) of \(420: \ 18 \ + \ 63=81\)

The correct answer is \(150\)
\(\frac{5}{3} \ × \ 90=150\)

The correct answer is \(- \ 49 \ - \ 18 \ i\)
We know that: \(i=\sqrt{- \ 1}⇒i^2= \ - \ 1\) 
\((- \ 4 \ + \ 5 \ i) \ (2 \ + \ 7 \ i)= \ - \ 14 \ - \ 28 \ i \ + \ 10 \ i \ + \ 35 \ i^2= \ - \ 14 \ - \ 18 \ i \ + \ 35 \ i^2=- \ 49 \ - \ 18 \ i\)

The correct answer is \(y=2 \ + 2\) cos \( x\)
The amplitude in the graph of the equation \(y=a\) cos \(b \ x\) is \(a\). (\(a\) and \(b\) are constant)
In the equation \(y=\) cos \(x\), the amplitude is \(2\) and the period of the graph is \(2 \ π\).
The only option that has two times the amplitude of graph \(y =\) cos \(x\) is \(y=2 \ + \ 2\) cos \(x\)
They both have the amplitude of \(2\) and period of \(2 \ π\).

The correct answer is \(50\) feet
The relationship among all sides of special right triangle 
\(30^\circ \ - \ 60^\circ \ - \ 90^\circ\) is provided in this triangle: 
In this triangle, the opposite side of \(30^\circ\) angle is half of the hypotenuse. 
Draw the shape of this question: 
The latter is the hypotenuse. Therefore, the latter is \(50\) ft.

The correct answer is \(66 \ π\) in\(^2\)
Surface Area of a cylinder \(= 2 \ π \ r \ (r \ + \ h)\),
The radius of the cylinder is \(3 \ (6 \ ÷ \ 2)\) inches and its height is \(8\) inches. Therefore, 
Surface Area of a cylinder \(= 2 \ π \ (3) \ (3 \ + \ 8) = 66 \ π\) in\(^2\)

The correct answer is \(4 \ x^2 \ + \ 4 \ x^3 \ + \ 3 \ y^2 \ - \ 5 \ y^5 \ + \ 2 \ z^3\)
\(5 \ x^2 \ + \ 2 \ y^5 \ - \ x^2 \ - \ 6 \ z^3 \ + \ 3 \ y^2 \ + \ 4 \ x^3 \ - \ 7 \ y^5 \ + \ 8 \ z^3\)
\(5 \ x^2 \ - \ x^2 \ + \ 4 \ x^3 \ + \ 3 \ y^2 \ + \ 2 \ y^5 \ - \ 7 \ y^5 \ + \ 8 \ z^3 \ - \ 6 \ z^3=\)
\(4 \ x^2 \ + \ 4 \ x^3 \ + \ 3 \ y^2 \ - \ 5 \ y^5 \ + \ 2 \ z^3\)

The correct answer is \(\frac{17}{18}\)
If \(17\) balls are removed from the bag at random, there will be one ball in the bag.
The probability of choosing a brown ball is \(1\) out of \(18\).
Therefore, the probability of not choosing a brown ball is \(17\) out of \(18\) and the probability of having not a brown ball after removing \(17\) balls is the same.

The correct answer is \(\frac{2}{5}, \frac{5}{7}, \frac{8}{13}, \frac{3}{4}\)
\(\frac{2}{5}=0.4 \ \ \ \  \frac{5}{7}≅0.71 \ \ \ \  \frac{8}{13}≅0.61 \  \ \ \ \frac{3}{4}=0.75\)

The correct answer is \(48\) ft.
Write a proportion and solve for \(x\).
\(\frac{6}{3}=\frac{x}{24} ⇒ 3 \ x=6 \ ×\ 24 ⇒ x=48\) ft.

The correct answer is \(150\%\)
The question is this: \(1.80\) is what percent of \(1.20\)?
Use percent formula: part \(= \frac{percent}{100} \ ×\) whole 
\(1.80 =\frac{ percent}{100} \ × \ 1.20 ⇒\)
\(1.80 = \frac{percent \ × \ 1.20}{100} ⇒\)
\(180 =\) percent \(× \ 1.20⇒\)
percent \(=\frac{ 180}{1.20} = 150\)

The correct answer is \(180\)
\((x \ - \ 25)^3=125→x \ - \ 25=5→x=30\)
\(→(x \ - \ 21)\ (x \ - \ 10)=(30 \ - \ 21) \ (30 \ - \ 10)=(9) \ (20)=180\)

The correct answer is Mode: \(1, \ 3\) Median: \(3\)
We write the numbers in the order: \(1, 1, 1, 2, 2, 3, 3, 3, 4, 4, 5\)
The mode of numbers is: \(1\) and \(3\) median is: \(3\)

The correct answer is \(48\)
Based on corresponding members from two matrices, we get: \(\begin{cases}2 \ x = x \ + \ 2 \ y \ - 4\\3 \ x =2 \ y \ + \ 12\end{cases}→\)
\(\begin{cases} x \ - \ 2 \ y = \ - \ 4\\3 \ x \ - \ 2 \ y = 12\end{cases}\) Multiply first equation by \(- \ 3\).
\(\begin{cases}- \ 3 \ x \ + \ 6 \ y = 12\\3 \ x \ - \ 2 \ y = 12\end{cases}→\) add two equations.
\(4 \ y=24→y=6→x=8→ x \ × \ y=48\)

The correct answer is \(12\)
Check each choice provided:
A. \(2 \ \ \ \ \frac{4 \ + \ 6 \ + \ 8 \ + \ 10 \ + \ 12}{5}=\frac{40}{5}=8\)
B. \(4 \ \ \ \ \frac{2 \ + \ 6 \ + \ 8 \ + \ 10 \ + \ 12}{5}=\frac{38}{5}=7.6\)
C. \(6 \ \ \ \ \frac{2 \ + \ 4 \ + \ 8 \ + \ 10 \ + \ 12}{5}=\frac{36}{5}=7.2\)
D. \(10 \ \ \frac{2 \ + \ 4 \ + \ 6 \ + \ 8 \ + \ 12}{5}=\frac{32}{5}=6.4\)
E. \(12 \ \ \frac{2 \ + \ 4 \ + \ 6 \ + \ 8 \ + \ 10}{5}=\frac{30}{5}=6\)

The correct answer is \(– \ x^2 \ – \ 3 \ x \ – \ 1\)
\((g \ – \ f)(x) = g(x) \ – \ f(x) = (– \ x^2 \ + \ 3 \ – \ 2 \ x) \ – \ (4 \ + \ x)\)
\(– \ x^2 \ + \ 3 \ – \ 2 \ x \ – \ 4 \ – \ x = \ – \ x^2 \ – \ 3 \ x \ – \ 1\)

The correct answer is \(289\)
\(0.5 \ x=(0.4) \ × \ 20→x=16→\)
\((16 \ + \ 1)^2=(17)^2=289\)

The correct answer is \(6\)
Solve for \(x\). 
\(\frac{2 \ x}{18}=\frac{x \ - \ 2}{6}\).
Multiply the second fraction by \(3\).
\(\frac{2 \ x}{18}=\frac{3 \ (x \ - \ 2)}{6 \ × \ 3}\)
Tow denominators are equal.
Therefore, the numerators must be equal.
\(2 \ x=3 \ x \ - \ 6\), 
\(0=x \ - \ 6\)
\(6=x\)

The correct answer is \(I \ > \ 2500 \ x \ + \ 25000\)
Let \(x\) be the number of years.
Therefore, \($2,500\) per year equals \(2500 \ x\). 
starting from \($25,000\) annual salary means you should add that amount to \(2500 \ x\). 
Income more than that is:
\(I \ > \ 2500 \ x \ + \ 25000\)

The correct answer is \(465\) km
Add the first \(5\) numbers.
\(32 \ + \ 40 \ + \ 51 \ + \ 39 \ + \ 53 = 215\)
To find the distance traveled in the next \(5\) hours, multiply the average by number of hours.
Distance \(=\) Average \(×\) Rate \(= 50 \ × \ 5 = 250\)
Add both numbers. \( 250 \ + \ 215 = 465\)

The correct answer is \(800\) ml
\(3\%\) of the volume of the solution is alcohol.
Let \(x\) be the volume of the solution. 
Then: \(3\%\) of \(x = 24\) ml \(⇒ 0.03 \ x = 24 ⇒ x = 24 \ ÷ \ 0.03 = 800\)

The correct answer is \( \frac{12}{13}\)
cot \(=\frac{adjacent}{opposite}\)
cot \(θ=\frac{12}{5}⇒\) we have the following right triangle.
Then:
\(c=\sqrt{5^2 \ + \ 12^2 }=\sqrt{25 \ + \ 144}=\sqrt{169}=13\)
cos \(θ=\frac{adjacent}{hypotenuse}=\frac{12}{13}\)

The correct answer is \(y=2 \ x\)
The slop of line A is: \(m=\frac{y_{2} \ - \ y_{1}}{x_{2} \ - \ x_{1}}=\frac{4 \ - \ 2}{6 \ - \ 5}=2\)
Parallel lines have the same slope and only choice C \((y=2 \ x)\) has slope of \(2\).

The correct answer is \(𝑃^{ \ 3}\)
To solve for \(f(3 \ g(P))\), first, find \(3 \ g(p)\)
\(g(x)=\log_{3}{x}\)
\(g(p)=\log_{3}{p}\)
\(3 \ g(p)=3 \ \log_{3}{p}=\log_{3}{p}^3\)
Now, find \(f(3 \ g(p))\):
\(f(x)=3^{ \ x}\)
\(f(\log_{3}{p}^{ \ 3} )=3^{\log_{3}{p}^{ \ 3}}\)
Logarithms and exponentials with the same base cancel each other.
This is true because logarithms and exponentials are inverse operations. Then:
\(f(\log_{3}{p}^{ \ 3})=3^{\log_{3}{p}^{ \ 3}}=p^{ \ 3}\)

The correct answer is \(0.97\)
ratio of A: \(\frac{570}{600}=0.95\) ratio of B: \(\frac{291}{300}=0.97\) ratio of C: \(\frac{665}{700}=0.95\) ratio of D: \(\frac{528}{550}=0.96\)

The correct answer is \(\frac{20}{19}\)
First find percentage of men in city A and percentage of women in city C.
Percentage of men in city A \(=\frac{600}{1170}\) and percentage of women in city C \(=\frac{665}{1365}\)
Find the ratio and simplify.
\(\frac{\frac{600}{1170}}{\frac{665}{1365}}=\frac{20}{19}\)

The correct answer is \(132\)
\(\frac{528 \ + \ x}{550}=1.2→528 \ + \ x=660→x=132\)

The correct answer is \(((\frac{30}{4} \ + \ \frac{13}{2}) \ × \ 7) \ − \ \frac{11}{2} \ + \ \frac{110}{4}\)
Simplify each choice provided. 
A. \(20 \ − \ (4 \ × \ 10) \ + \ (6 \ × \ 30)=20 \ - \ 40 \ + \ 180=160\)
B. \((\frac{11}{8} \ × \ 72) \ + \ (\frac{125}{5})=99 \ + \ 25=124\)
C. \(((\frac{30}{4} \ + \ \frac{13}{2}) \ × \ 7) \ − \ \frac{11}{2} \ + \ \frac{110}{4}=((\frac{30 \ + \ 26}{4}) \ × \ 7) \ - \ \frac{11}{2} \ + \ \frac{55}{2}=((\frac{56}{4}) \ × \ 7) \ + \ \frac{55 \ - \ 11}{2}=\)
\((14 \ × \ 7) \ + \ \frac{44}{2}=98 \ + \ 22=120\) (this is the answer)
D. \((2 \ × \ 10) \ + \ (50 \ × \ 1.5) \ + \ 15=20 \ + \ 75 \ + \ 15=110\)
E. \(\frac{481}{6} \ + \ \frac{121}{3}=\frac{481 \ + \ 242}{6}=120.5\)

The correct answer is \((2, 2)\)
Plug in each pair of number in the equation:
A. \((2, 2): \ \ \ \  \  \ 2 \ (2) \ + \ 4 \ (2) = 12\) Bingo!
B. \((– \ 1, 3): \ \ \ 2 \ (– \ 1) \ + \ 4 \ (3) = 10\) Nope!
C. \((– \ 2, 2): \ \ \ 2 \ (– \ 2) \ + \ 4 \ (2) = 4\) Nope!
D. \((2, 3): \ \ \ \ \  \  2 \ (2) \ + \ 4 \ (3) = 14\) Nope!
E. \((2, 8): \ \ \ \  \  \ 2 \ (2) \ + \ 4 \ (8) = 36\) Nope!

The correct answer is \(x\) is divided by \(2\)
Replace \(z\) by \(\frac{z}{2}\) and simplify.
\(x_{1}=\frac{5 \ y \ + \ \frac{r}{r \ + \ 2}}{\frac{4}{\frac{z}{2}}}= \frac{5 \ y \ + \ \frac{r}{r \ + \ 2}}{\frac{4 \ × \ 2}{z}}=\)
\(\frac{5 \ y \ + \ \frac{r}{r \ + \ 2}}{2 \ \times \frac{4}{z}} = \frac{1}{2} \ \times \ \frac{5 \ y \ + \ \frac{r}{r \ + \ 2}}{\frac{4}{z}} =\frac{x}{2}\)
When \(z\) is divided by \(2, \ x\) is also divided by \(2\).

The correct answer is \(108\)
\(y = 3 \ a \ b \ + \ 4 \ b^3\)
Plug in the values of a and b in the equation: \(a = 3\) and \(b = 3\)
\(y = 3 \ (3) \ (3) \ + \ 4 \ (3)^3 = 27 \ + \ 3 \ (27) = 27 \ + \ 81 = 108\)

The correct answer is \(\frac{1}{2}\)
cotangent \(β= \frac{1}{tangent \ β}=\frac{1}{2}\)

The correct answer is \((- \ 5, 3)\)
When points are reflected over \(y-\)axis, the value of \(y\) in the coordinates doesn’t change and the sign of \(x\) changes. Therefore:
the coordinates of point B is \((- \ 5, 3)\).

The correct answer is \(- \ 36\)
\(g(x)= \ - \ 2\), then:
\(f(g(x))= f(- \ 2)=2 \ (- \ 2)^3 \ - \ 3 \ (- \ 2)^2 \ + \ 4 \ (- \ 2)=\)
\(- \ 16 \ - \ 12 \ - \ 8=- \ 36\)

The correct answer is \(50\) miles
Use the information provided in the question to draw the shape.
Use Pythagorean Theorem: \(a^2 \ + \ b^2 = c^2\)
\(40^2 \ + \ 30^2 = c^2 ⇒\)
\(1600 \ + \ 900 = c^2 ⇒\)
\(2500 = c^2 ⇒ c = 50\)

The correct answer is \(29\)
The area of trapezoid is: \((\frac{6 \ + \ 10}{2}) \ × \ x=64→8 \ x=64→x=8\)
\(y=\sqrt{3^2 + \ 4^2}=5\)
Perimeter is: \(10 \ + \ 6 \ + \ 8 \ + \ 5=29\)

The correct answer is \(50\)
The area of \(\triangle\)BED is \(16\), then:
\(\frac{4 \ × \ AB}{2}=18→4 \ ×\) AB \(=36→\) AB \(=9\)
The area of \(\triangle\)BDF is \(24\), then:
\(\frac{3 \ × \ BC}{2}=24→3 \ × \) BC \(=48→\) BC \(=16\)
The perimeter of the rectangle is \(= 2 \ × \ (9 \ + \ 16)=50\)

The correct answer is \(6.6\) kg
The weight of \(12.2\) meters of this rope is: \(13.2 \ × \ 500\) g \(= 6600\) g
\(1\) kg \(= 1000\) g, therefore, \(6600\) g \(÷ \ 1000 = 6.6\) kg

The correct answer is \(\frac{100 \ z}{x} \)
Let the number be \(A\). Then:
\(z=x\% \ × \ A\)
Solve for \(A\).
\(z=\frac{x}{100} \ × \ A\)
Multiply both sides by \(\frac{100}{x}\):
\(z \ × \ \frac{100}{x}=\frac{x}{100} \ × \ \frac{100}{x} \ × \ A\)
\(A=\frac{100 \ z}{x}\)

The correct answer is \(\frac{2}{5}\)
Set of number that are not composite between \(1\) and \(25\): A \(= \left\{1, 2, 3, 5, 7, 11, 13, 17, 19, 23\right\}\)
Probability \(=\frac{ number \ of \ desired \ outcomes}{number \ of \ total \ outcomes}=\frac{10}{25}=\frac{2}{5}\)