## Full Length HiSET Mathematics Practice Test

Taking a full-length practice test of the HiSET math exam is not only preparation for your actual test, but also simulation of testing day. Not only will this help you to become familiar with the format and feel more confident on exam day, it will be an excellent way to measure your readiness for taking that professional level math certification.

It's essential to treat this practice test as a real one. By preparing everything you need and taking the test in one sitting, this will help you prepare your mind and body for the actual HiSET Math exam.

Take the following math practice test to simulate taking a real HiSET. After you finish, score your tests using the answer keys below.

Hope this helps with studying for that big day!

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## HiSET Mathematics Practice Test 4

50 questions
Total time: 90 Minutes
You may use a calculator for this test.
1- $$[4 \ × \ (– \ 18) \ + \ 6] \ – \ (– \ 2) \ + \ [4 \ × \ 4] \ ÷ \ 8 =$$?
(A) $$72$$
(B) $$- \ 62$$
(C) $$- \ 144$$
(D) $$100$$
(E) $$70$$
2- The mean of $$40$$ test scores was calculated as $$90$$. But, it turned out that one of the scores was misread as $$84$$ but it was $$68$$. What is the mean?
(A) $$90$$
(B) $$84$$
(C) $$89.6$$
(D) $$80.6$$
(E) $$88$$
3- What is the product of all possible values of $$x$$ in the following equation?
$$|x \ - \ 16| = 5$$
(A) $$90$$
(B) $$112$$
(C) $$85$$
(D) $$203$$
(E) $$231$$
4- What is the value of the expression $$6(x \ - \ 3 \ y) \ + \ (4 \ - \ x)^2$$ when $$x=5$$ and $$y=- \ 3$$ ?
(A) $$67$$
(B) $$- \ 67$$
(C) $$- \ 78$$
(D) $$90$$
(E) $$30$$
5- Four one – foot rulers can be split among how many users to leave each with $$\frac{1}{4}$$ of a ruler?
(A) $$30$$
(B) $$24$$
(C) $$16$$
(D) $$14$$
(E) $$8$$
6- The red box is $$30\%$$ greater than the blue box. If $$50$$ books exist in the red box, how many books are in the blue box?
(A) $$30$$
(B) $$25$$
(C) $$32$$
(D) $$26$$
(E) $$27$$
7- What is the slope of a line that is perpendicular to the line
$$6 \ x \ - \ 3\ y= 24$$?
(A) $$-\frac{1}{2}$$
(B) $$2$$
(C) $$- \ 4$$
(D) $$- \ 2$$
(E) $$12$$
8- Mr.Smith family are choosing a menu for their reception. They have $$5$$ choices of appetizers, $$3$$ choices of entrees, $$6$$ choices of cake. How many different menu combinations are possible for them to choose?
(A) $$90$$
(B) $$30$$
(C) $$15$$
(D) $$18$$
(E) $$50$$
9- Which of the following is equal to the expression below?
$$(3 \ x \ - \ 4 \ y) \ (5 \ x \ + \ y)$$
(A) $$23 \ x^2 \ - \ 5 \ x \ y \ + \ 4 \ y^2$$
(B) $$15 \ x^2 \ - \ 17 \ x \ y \ - \ 4 \ y ^2$$
(C) $$24 \ x^2 \ - \ 5 \ x \ y \ + \ 2 \ y ^2$$
(D) $$24 \ x^2 \ - \ 5 \ x \ y$$
(E) $$24 \ x^2 \ - \ 5 \ y$$
10- A swimming pool holds $$3,600$$ cubic feet of water. The swimming pool is $$30$$ feet long and $$15$$ feet wide. How deep is the swimming pool?
(A) $$25$$ feet
(B) $$50$$ feet
(C) $$62$$ feet
(D) $$48$$ feet
(E) $$8$$ feet
11- What is the area of a square whose diagonal is $$12$$?
(A) $$72$$
(B) $$144$$
(C) $$32$$
(D) $$14$$
(E) $$24$$
12- The ratio of boys and girls in a class is $$5:8$$. If there are $$39$$ students in the class, how many more boys should be enrolled to make the ratio $$1:1$$?
(A) $$15$$
(B) $$24$$
(C) $$9$$
(D) $$6$$
(E) $$12$$
13- A football team had $$\ 18,000$$ to spend on supplies. The team spent $$\ 10,000$$ on new balls. New sport shoes cost $$\ 140$$ each. Which of the following inequalities represent how many new shoes the team can purchase.
(A) $$140 \ x \ + \ 10,000 \ ≤18,000$$
(B) $$140 \ x \ + \ 12,000 \ ≤18,000$$
(C) $$140 \ x \ + \ 12,000 \ >18,000$$
(D) $$10000\ x \ + \ 14,000 \ ≤18,000$$
(E) $$10000\ x \ + \ 14 \ x \ ≤18,000$$
14- What is the value of $$x$$ in the following system of equations?
$$4 \ x \ + \ 3 \ y=15$$
$$8 \ x \ - \ 3 \ y=- \ 6$$
(A) $$3$$
(B) $$- \ 2$$
(C) $$\frac{- \ 3}{4}$$
(D) $$4$$
(E) $$2$$
15- Mr.Miller  saves $$\ 3,000$$ out of his monthly family income of $$\ 75,000$$. What fractional part of his income does he save?
(A) $$\frac{1}{5}$$
(B) $$\frac{2}{3}$$
(C) $$\frac{2}{20}$$
(D) $$\frac{1}{25}$$
(E) $$\frac{1}{2}$$
16- Jacob needs an $$60\%$$ average in his writing class to pass. On his first $$4$$ tests, he earned scores of $$45\ % \ , \ 65\% \ , \ 75\%$$, and $$85\%$$. What is the minimum score Jason can earn on his fifth and final test to pass?
(A) $$30\%$$
(B) $$25\%$$
(C) $$40\%$$
(D) $$20\%$$
(E) $$70\%$$
17- The average of five numbers is $$36$$. If a sixth number $$50$$ is added, then, what is the new average?
(A) $$26$$
(B) $$35$$
(C) $$22$$
(D) $$38$$
(E) $$16$$
18- What is the value of in the following equation?
$$\frac{4}{9} \ x \ + \frac {2}{3}=\frac{5}{6}$$
(A) $$\frac{3}{8}$$
(B) $$\frac{1}{6}$$
(C) $$\frac{4}{3}$$
(D) $$3$$
(E) $$4$$
19- A bank is offering $$2.5\%$$ simple interest on a savings account. If you deposit $$\ 16,000$$, how much interest will you earn in two years?
(A) $$\ 500$$
(B) $$\ 800$$
(C) $$\ 8400$$
(D) $$\ 80$$
(E) $$\ 458$$
20- Last week $$32,000$$ fans attended a football match. This week three times as many bought tickets, but one fourth of them cancelled their tickets. How many are attending this week?
(A) $$75000$$
(B) $$65000$$
(C) $$40000$$
(D) $$72000$$
(E) $$36000$$
21- Simplify   $$5\ x^2 \ y^4 (3 \ x^2 \ y)^3=$$
(A) $$135 \ x^8 \ y^7$$
(B) $$45 \ x^6 \ y^7$$
(C) $$95\ x^6 \ y^8$$
(D) $$130\ x^8 \ y^7$$
(E) $$75\ x^8 \ y^7$$
22- What are the zeros of the function: $$f(x)=2 \ x^3 \ + \ 6 \ x^2 \ + \ 8 \ x$$?
(A) $$0 \ , \ 1 \ , \ - \ 4$$
(B) $$0 \ , \ - \ 1 \ , \ 4$$
(C) $$\ - \ 1 \ , \ 4$$
(D) $$\ - \ 2\ , \ - \ 4$$
(E) $$\ - \ 2\ , \ 4$$
23- The square of a number is $$\frac{36}{49}$$. What is the cube of that number?
(A) $$\frac{216}{343}$$
(B) $$\frac{343}{216}$$
(C) $$\frac{25}{36}$$
(D) $$\frac{6}{7}$$
(E) $$\frac{49}{6}$$
24- What is the surface area of the cylinder below?
(A) $$56 \ π\ in^2$$
(B) $$45 \ π\ in^2$$
(C) $$120 \ π\ in^2$$
(D) $$112 \ π\ in^2$$
(E) $$450\ π\ in^2$$

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25- If $$f(x)=3 \ x^3 \ + \ 6 \ x^2 \ + \ 4 \ x$$ and $$g(x)=- \ 2$$, what is the value of $$f(g(x))$$?
(A) $$4$$
(B) $$0$$
(C) $$- \ 6$$
(D) $$12$$
(E) $$- \ 8$$
26- What is the perimeter of a square that has an area of $$49$$ inches?
(A) $$32$$ inches
(B) $$25$$ inches
(C) $$28$$ inches
(D) $$10$$ inches
(E) $$15$$ inches
27- What is the simplified form of $$(x^3 \ + \ 4 \ x^2 \ - \ 5 \ x) \ + (2 \ x^3 \ + \ x^2 \ + \ 7 \ x)$$?
(A) $$3 \ x^3 \ + \ 5 \ x^2 \ + \ 2 \ x$$
(B) $$3 \ x^3 \ - \ 5 \ x^2 \ + \ 2 \ x$$
(C) $$2 \ x^3 \ - \ 5 \ x^2 \ + \ 2 \ x$$
(D) $$2 \ x^3 \ - \ 5 \ x^2 \ + \ 6 \ x$$
(E) $$2 \ x^3 \ + \ 4 \ x^2 \ + \ 6 \ x$$
28- A cruise line ship left Port A and traveled $$60$$ miles due west and then $$120$$ miles due north. At this point, what is the shortest distance from the cruise to port A?
(A) $$120$$ miles
(B) $$170$$ miles
(C) $$134$$ miles
(D) $$150$$ miles
(E) $$145$$ miles
29- If the ordered pair $$(– \ 5 \ , \ 8)$$ is reflected over the $$x-$$axis, what is the new ordered pair?
(A) $$(- \ 5 \ , \ 8 )$$
(B) $$( 5 \ , \ - \ 8 )$$
(C) $$( 5 \ , \ 8 )$$
(D) $$( - \ 5 \ , \ - \ 8 )$$
(E) $$( - \ 8 \ , \ - \ 5 )$$
30- What is the median of these numbers? $$3 \ , \ 30 \ , \ 26 \ , \ 15 \ , \ 54 \ , \ 45 \ , \ 37$$
(A) $$30$$
(B) $$15$$
(C) $$40$$
(D) $$22$$
(E) $$19$$
31- What is the missing term in the given sequence? $$3\ , \ 4 \ , \ 6 \ , \ 9 \ , \ 13 \ , \ 18 \ , \ 24 \ , \ .... \ , \ 39$$
(A) $$30$$
(B) $$35$$
(C) $$31$$
(D) $$38$$
(E) $$32$$
32- What is the equivalent temperature of $$120^°$$F in Celsius?
$$C = \frac{6}{8}(F \ – \ 24)$$
(A) $$45$$
(B) $$72$$
(C) $$81$$
(D) $$27$$
(E) $$36$$
33- The average of $$8$$ numbers is $$16$$. The average of $$6$$ of those numbers is $$10$$. What is the average of the other two numbers?
(A) $$36$$
(B) $$34$$
(C) $$40$$
(D) $$14$$
(E) $$24$$
34- Ashly’s trick–or–treat bag contains $$14$$ pieces of chocolate, $$15$$ suckers, $$10$$ pieces of gum, $$22$$ pieces of licorice. If she randomly pulls a piece of candy from her bag, what is the probability of her pulling out a piece of sucker?
(A) $$\frac{1}{4}$$
(B) $$\frac{1}{2}$$
(C) $$\frac{3}{2}$$
(D) $$2$$
(E) $$3$$
35- What is the volume of a box with the following dimensions? Hight $$= 6$$ cm                     Width $$= 7$$ cm              Length $$= 8$$ cm
(A) $$270$$ cm$$^3$$
(B) $$150$$ cm$$^3$$
(C) $$336$$ cm$$^3$$
(D) $$120$$ cm$$^3$$
(E) $$60$$ cm$$^3$$
36- In two successive years, the population of a town is increased by $$20\%$$ and $$25\%$$. What percent of the population is increased after two years?
(A) $$65\%$$
(B) $$35\%$$
(C) $$25\%$$
(D) $$50\%$$
(E) $$70\%$$
37- If $$180\%$$ of a number is $$80$$ , then what is the $$85\%$$ of that number?
(A) $$44$$
(B) $$85$$
(C) $$70$$
(D) $$50$$
(E) $$65$$
38- Simplify the expression.
$$(8 \ x^3 \ + \ 4 \ x^2 \ - \ 4 \ x^4 ) \ - \ (5 \ x^2 \ + \ 6 \ x^4 \ - \ 3 \ x^3 )$$
(A) $$- \ 10 \ x^4 \ + \ 11\ x^3 \ - \ x^2$$
(B) $$- \ 10 \ x^4 \ + \ 11\ x^3 \ - \ 5 \ x^2$$
(C) $$10 \ x^4 \ - \ 11\ x^3 \ - \ 5 \ x^2$$
(D) $$2 \ x^4 \ - \ 4 \ x^3 \ - \ 5 \ x^2$$
(E) $$2 \ x^4 \ - \ 4 \ x^3 \ + \ 6 \ x^2$$
39- The perimeter of a rectangular yard is $$36$$ meters. What is its length if its width is twice its length?
(A) $$12$$ meters
(B) $$24$$ meters
(C) $$6$$ meters
(D) $$36$$ meters
(E) $$20$$ meters
40- What is the slope of the line: $$8 \ x \ - \ 2 \ y=10$$
(A) $$2$$
(B) $$4$$
(C) $$1.5$$
(D) $$1$$
(E) $$- \ 1$$
41- Four years ago, Ann was three times as old as Michael was. If Michael is $$14$$ years old now, how old is Ann?
(A) $$12$$
(B) $$24$$
(C) $$32$$
(D) $$20$$
(E) $$28$$
42- If $$60\%$$ of a number is $$9$$, what is the number?
(A) $$6$$
(B) $$11$$
(C) $$20$$
(D) $$8$$
(E) $$15$$
43- Simplify:
$$(x^6) \ (x^4)$$
(A) $$x^2$$
(B) $$x^{10}$$
(C) $$x^7$$
(D) $$x^{12}$$
(E) $$x^5$$
44- John earns $$\ 720$$ for his first $$45$$ hours of work in a week and is then paid $$2.5$$ times his regular hourly rate for any additional hours. This week, John needs $$\ 850$$ to pay his rent, bills and other expenses. How many hours must he work to make enough money in this week?
(A) $$40$$
(B) $$35$$
(C) $$45$$
(D) $$48$$
(E) $$53$$
45- Mike is $$7$$ miles ahead of Alex running at $$4.5$$ miles per hour and Alex is running at the speed of $$5$$ miles per hour. How long does it take Alex to catch Mike?
(A) $$8$$ hours
(B) $$14$$ hours
(C) $$4$$ hours
(D) $$6$$ hours
(E) $$2$$ hours
46- The area of a circle is $$49\ π$$. What is the diameter of the circle?
(A) $$12$$
(B) $$14$$
(C) $$4$$
(D) $$6$$
(E) $$10$$
47- Julia left a $$\ 16.00$$ tip on a lunch that cost $$\ 54.00$$, approximately what percentage was the tip?
(A) $$15\%$$
(B) $$25\%$$
(C) $$29\%$$
(D) $$14\%$$
(E) $$16\%$$
48- There are four equal tanks of water. If $$\frac{3}{6}$$of a tank contains $$300$$ liters of water, what is the capacity of the four tanks of water together?
(A) $$240$$
(B) $$24$$
(C) $$300$$
(D) $$2400$$
(E) $$1800$$
49- If a tree casts a $$36 –$$foot shadow at the same time that a $$5$$ feet yardstick casts a $$3–$$foot shadow, what is the height of the tree?
(A) $$25$$ ft
(B) $$45$$ ft
(C) $$26$$ ft
(D) $$60$$ ft
(E) $$49$$
50- $$70$$ students took a test and $$15$$ of them failed. What percent of the students passed the test?
(A) $$80\%$$
(B) $$79\%$$
(C) $$75\%$$
(D) $$95\%$$
(E) $$40\%$$
 1- Choice B is correct The correct answer is $$- \ 62$$Use PEMDAS (order of operation):$$[4 \ × \ (– \ 18)\ + \ 6] \ – \ (– \ 2)\ + \ [4 \ × \ 4] \ ÷ \ 8 = [– \ 72 \ + \ 6] \ – \ (– \ 2) \ + \ [16] \ ÷ \ 8 = [– \ 72 \ + \ 6] \ – \ (– \ 2)\ + \ 2 = [– \ 66] \ – \ (– \ 2)\ + \ 2 = [– \ 66] \ + \ 2 \ + \ 2 = – \ 62$$ 2- Choice C is correct The correct answer is $$89.6$$average (mean) $$= \frac{sum \ of \ terms}{number \ of \ terms}⇒ 90 = \frac{sum \ of \ terms}{40}⇒ sum = 90 \ × \ 40 = 3600$$The difference of $$84$$ and $$68$$ is $$16$$. Therefore, $$16$$ should be subtracted from the sum.$$3600 \ – \ 16 = 3584$$ mean $$= \frac{sum \ of \ terms }{number \ of \ terms}⇒$$ mean $$= \frac{3584}{40}= 89.6$$ 3- Choice E is correct The correct answer is $$231$$To solve absolute values equations, write two equations. $$x \ - \ 16$$ could be positive $$5$$, or negative $$5$$. Therefore, $$x \ - \ 16=5⇒x=21$$$$x \ - \ 16=- \ 5⇒x=11$$Find the product of solutions: $$11 \ × \ 21 = 231$$ 4- Choice A is correct The correct answer is $$67$$Plug in the value of $$x$$ and $$y$$. $$x=5$$ and $$y=- \ 3$$$$6(x \ - \ 3 \ y) \ + \ (4 \ - \ x)^2=6 \ (5 \ - \ 3 \ (- \ 3)) \ + \ (4 \ - \ 5)^2=6(5 \ + \ 6) \ + \ (- \ 1)^2 = 66 \ + \ 1=67$$ 5- Choice C is correct The correct answer is $$16$$$$4 \ ÷ \frac{1}{4} =16$$ 6- Choice E is correct The correct answer is $$27$$The red box is $$30\%$$ greater than the blue box. Let $$x$$ be the capacity of the blue box. Then: $$x \ + \ 30\%$$ of $$= 50 →1.8 \ x=50 → x=\frac{50}{1.8}=27$$ 7- Choice A is correct The correct answer is$$-\frac{1}{2}$$The equation of a line in slope intercept form is: $$y=m \ x \ + \ b$$Solve for $$y$$ .$$6 \ x \ - \ 3 \ y=24 ⇒- \ 3 \ y=24 \ - \ 6 \ x⇒y =(24 \ - \ 6 \ x) \ ÷ \ (- \ 3)⇒y=2 \ x \ - \ 8$$The slope is $$2$$. The slope of the line perpendicular to this line is:$$m_1 \ × \ m_2= - \ 1 ⇒ 2 \ × \ m_2= - \ 1⇒ m_2= -\frac{1}{2}$$ 8- Choice A is correct The correct answer is $$90$$To find the number of possible outfit combinations, multiply number of options for each factor:$$5 \ × \ 3 \ × \ 6 =90$$ 9- Choice B is correct The correct answer is $$15 \ x^2 \ - \ 17 \ x \ y \ - \ 4 \ y ^2$$Use FOIL method.$$(3 \ x \ - \ 4 \ y) \ (5 \ x \ + \ y) = 15 \ x^2 \ + \ 3 \ x \ y \ - \ 20 \ x \ y \ - \ 4 \ y^2=15 \ x^2 \ - \ 17 \ x \ y \ - \ 4 \ y^2$$ 10- Choice E is correct The correct answer is $$8$$ feetUse formula of rectangle prism volume.V = (length) (width) (height) ⇒ $$(3600) = (30) \ (15) \ (height) ⇒ height = 3600 \ ÷ \ 450= 8$$ 11- Choice A is correct The correct answer is $$72$$The diagonal of the square is $$12$$. Let $$x$$ be the side. Use Pythagorean Theorem: $$a^2 \ + \ b^2 = c^2$$$$x^2 \ + \ x^2 = 12^2⇒2 \ x^2= 12^2⇒2 \ x^2= 144⇒x^2= 72 ⇒x= \sqrt{72}$$The area of the square is:$$\sqrt{72} \ × \sqrt {72} = 72$$ 12- Choice C is correct The correct answer is $$9$$Th ratio of boy to girls is $$5:8$$. Therefore, there are $$5$$ boys out of $$13$$ students.To find the answer, first divide the total number of students by $$13$$, then multiply the result by $$5$$.$$39 \ ÷ \ 13 = 3 ⇒ 3 \ × \ 5 = 15$$There are $$15$$ boys and $$24$$ $$(39 \ – \ 15)$$ girls.So, $$9$$ more boys should be enrolled to make the ratio $$1:1$$ 13- Choice A is correct The correct answer is $$140 \ x \ + \ 10,000 \ ≤18,000$$Let  be the number of shoes the team can purchase. Therefore, the team can purchase $$140 \ x$$.The team had $$\ 18,000$$ and spent $$\ 10000$$. Now the team can spend on new shoes $$\ 8000$$ at most. Now, write the inequality:$$140 \ x \ + \ 10,000 \ ≤18,000$$ 14- Choice C is correct The correct answer is $$\frac{- \ 3}{4}$$Solving Systems of Equations by EliminationMultiply the first equation by $$(– \ 2)$$, then add it to the second equation$$- \ 2 (4 \ x \ + \ 3 \ y =15)$$$$8 \ x \ - \ 3 \ y =- \ 6$$$$- \ 8 \ x \ - \ 6 \ y =- \ 30$$$$8 \ x \ - \ 3 \ y = - \ 6$$$$- \ 9 \ y =- \ 36$$$$y=4$$Plug in the value of$$y$$ into one of the equations and solve for $$x$$$$4 \ x \ + \ 3 \ (4)= 15⇒4 \ x \ + \ 12 = 15⇒4 \ x= - \ 3⇒x=\frac{- \ 3}{4}$$. 15- Choice D is correct The correct answer is $$\frac{1}{25}$$$$3,000$$out of $$75,000$$ equals to $$\frac{30000}{75000} = \frac{30}{750} = \frac{1}{25}$$ 16- Choice A is correct The correct answer is $$30$$Jacob needs an $$60\%$$ average to pass for five tests. Therefore, the sum of $$5$$ tests must be at least $$5 \ × \ 60 = 300$$The sum of$$4$$ tests is: $$45 \ + \ 65 \ + \ 75 \ + 85 =270$$.The minimum score Jacob can earn on his fifth and final test to pass is:$$300 \ – \ 270 =30$$ 17- Choice D is correct The correct answer is $$38$$Solve for the sum of five numbers. average $$= \frac{sum \ of \ terms}{number \ of \ terms}⇒ 36= \frac{sum \ of \ 5 \ numbers}{5}⇒$$sum of $$5$$ numbers $$= 36 \ × \ 5 = 180$$The sum of $$5$$ numbers is $$180$$. If a sixth number $$50$$ is added, then the sum of $$6$$ numbers is $$180 \ + \ 50 = 230$$average$$=\frac{sum \ of \ terms}{number \ of \ terms} = \frac{230}{6} = 38$$ 18- Choice A is correct The correct answer is $$\frac{3}{8}$$Isolate and solve for $$x$$. $$\frac{4}{9}x \ + \frac{2}{3}=\frac{5}{6}⇒\frac{4}{9} \ x=\frac{5}{6} \ - \frac{2}{3} = \frac{1}{6}⇒\frac{4}{9} \ x= \frac{1}{6}$$Multiply both sides by the reciprocal of the coefficient of $$x$$.$$(\frac{9}{4})\frac{4}{9} \ x= \frac{1}{6}(\frac{9}{4})⇒x= \frac{9}{24}=\frac{3}{8}$$ 19- Choice B is correct The correct answer is $$\ 800$$Use simple interest formula: (I = interest, p = principal, r = rate, t = time)$$I=(16000)(\ 0.025)\ (2)=800$$ 20- Choice D is correct The correct answer is $$72000$$Three times of $$32,000$$ is $$96,000$$. One fourth of them cancelled their tickets.One fourth of $$96,000$$ equals$$24,000$$ $$\frac{1}{4}\ × \ 96000 = 24000$$. $$72,000$$ $$(96000 \ – \ 24000 =72000)$$ fans are attending this week 21- Choice A is correct The correct answer is $$135 \ x^8 \ y^7$$Simplify. $$5 \ x^2 \ y^4 \ (3 \ x^2 \ y)^3= 5 \ x^2 \ y^4 \ (27 \ x^6 \ y^3 ) =135 \ x^8 \ y^7$$ 22- Choice D is correct The correct answer is $$- \ 2 \ , \ - \ 4$$Frist, factor the function:$$x \ (x \ + \ 2) \ (x \ + \ 4)$$To find the zeros, $$f(x)$$ should be zero.$$f(x)=x \ (x \ + \ 2) \ (x \ + \ 4)=0$$Therefore, the zeros are:$$x=0$$$$(x \ + \ 2)=0 ⇒x= - \ 2$$        $$(x \ + \ 4)=0 ⇒x= - \ 4$$ 23- Choice A is correct The correct answer is $$\frac{216}{343}$$The square of a number is $$\frac{36}{49}$$,then the number is the square root of $$\frac{36}{49}$$$$\sqrt\frac{36}{49}= \frac{6}{7}$$The cube of the number is:$$(\frac{6}{7})^3 =\frac{216}{343}$$ 24- Choice D is correct The correct answer is $$112 \ π\ in^2$$Surface Area of a cylinder $$= 2 \ π \ r \ (r \ + \ h)$$,The radius of the cylinder is $$4$$       $$(8 \ ÷ \ 2)$$ inches and its height is $$10$$ inches. Therefore, Surface Area of a cylinder $$= 2 \ π \ (4) \ (4 \ + \ 10) = 112 \ π$$ 25- Choice E is correct The correct answer is $$- \ 8$$$$g(x)= \ - \ 2$$, then:$$f(g(x))= f(- \ 2)=3 \ (- \ 2)^3 \ + \ 6(- \ 2)^2 \ + \ 4(- \ 2) =$$$$- \ 24\ + \ 24 \ - \ 8 = - \ 8$$ 26- Choice C is correct The correct answer is $$28$$ inchesThe area of the square is $$49$$ inches.Therefore, the side of the square is square root of the area.$$\sqrt{49}=7$$ inches,Four times the side of the square is the perimeter : $$4 \ × \ 7 = 28$$ inches 27- Choice A is correct The correct answer is $$3 \ x^3 \ 5 \ x^2 \ 2 \ x$$Combine like terms: $$(x^3 \ + \ 4 \ x^2 \ - \ 5 \ x) \ + \ (2 \ x^3 \ + \ x^2 \ + \ 7 \ x)=(x^3 \ + 2 \ x^3) \ + \ (4 \ x^2 \ +x^2 ) \ + \ (- \ 5 \ x \ + \ 7 \ x)=$$$$3 \ x^3 \ + \ 5 \ x^2 \ + \ 2 \ x$$ 28- Choice C is correct The correct answer is $$134$$ milesUse the information provided in the question to draw the shape.Use Pythagorean Theorem: $$a^2 \ + \ b^2 = c^2$$$$60^2 \ + \ 120^2 = c2⇒ 3600 \ + \ 14400 = c2 ⇒ 18000 = c2 ⇒ c =134$$ 29- Choice D is correct The correct answer is $$( - \ 5 \ , \ - \ 8)$$Since the ordered pair is reflected over the $$x-$$axis, then, the value of $$x$$ of the point doesn’t change and the sign of $$y$$ changes. $$(– \ 5 \ , \ 8) ⇒ (– \ 5 \ , \ – \ 8)$$ 30- Choice A is correct The correct answer is $$30$$Write the numbers in order: $$3 \ , \ 15 \ , \ 26 \ , \ 30 \ , \ 37 \ , \ 45 \ , \ 54$$Median is the number in the middle. So, the median is $$30$$. 31- Choice C is correct The correct answer is $$31$$Find the difference of each pairs of numbers:$$3 \ , \ 4 \ , \ 6\ , \ 9 \ , \ 13 \ , \ 18 \ , \ 24 \ , ...., \ 39$$The difference of $$3$$ and $$4$$ is $$1$$, $$4$$ and $$6$$ is $$2$$ , $$6$$ and $$9$$ is $$3$$ , $$9$$ and $$13$$ is $$4$$ , $$13$$ and $$18$$ is $$5$$, $$18$$ and $$24$$ is $$6$$ , $$24$$ and next number should be $$7$$.The number is $$24 \ + \ 7 = 31$$ 32- Choice B is correct The correct answer is $$72$$Plug in $$120$$ for F and then solve for C.         C$$= \frac{6}{8}(F \ ­– \ 24) ⇒ C = \frac{6}{8} (120 \ ­– \ 24) ⇒ C = \frac{6}{8} \ (96) =72$$ 33- Choice B is correct The correct answer is $$34$$$$average = \frac{sum \ of \ terms}{number \ of \ terms}$$⇒ (average of $$8$$ numbers)$$16$$$$= \frac{sum \ of \ numbers}{8}$$⇒sum of $$8$$ numbers is $$16 \ × \ 8 = 128$$(average of $$6$$ numbers) $$10$$ $$=\frac{sum \ of \ numbers}{6}$$⇒sum of $$6$$ numbers is $$10 \ × \ 6 = 60$$sum of $$8$$ numbers $$–$$ sum of $$6$$ numbers = sum of $$2$$ numbers$$128 \ – \ 60 = 68$$ average of $$2$$ numbers = $$\frac{68}{2} = 34$$ 34- Choice A is correct The correct answer is $$\frac{1}{4}$$Probability$$= \frac{number \ of \ desired \ outcomes}{number \ of \ total \ outcomes} =\frac {15}{10 \ + \ 14 \ + \ 15 \ + \ 22}= \frac{15}{61} =\frac {1}{4}$$ 35- Choice C is correct The correct answer is $$336$$ cm$$^3$$Volume of a box = length × width × height $$= 6 \ × \ 7 \ × \ 8 =336$$ 36- Choice D is correct The correct answer is $$50\%$$the population is increased by $$20\%$$ and $$25\%$$. $$20\%$$ increase changes the population to $$120\%$$ of original population. For the second increase, multiply the result by $$125\%$$.$$(1.20) \ × \ (1.25) = 1.50 = 150\%$$$$50$$ percent of the population is increased after two years. 37- Choice A is correct The correct answer is $$44$$First, find the number.Let $$x$$ be the number. Write the equation and solve for $$x$$. $$180\%$$ of a number is $$80$$,then:$$1.8 \ × \ x= 80⇒ x=80 \ ÷ \ 1.8=44$$$$85\%$$ of $$44$$ is:$$0.85 \ × \ 44 = 37$$ 38- Choice A is correct The correct answer is $$- \ 10 \ x^4 \ + \ 11\ x^3 \ - \ x^2$$Simplify and combine like terms.$$(8 \ x^3 \ + \ 4 \ x^2 \ - \ 4 \ x^4 ) \ - \ (5 \ x^2 \ + \ 6 \ x^4 \ - \ 3 \ x^3 )⇒(8 \ x^3 \ +4 \ x^2 \ - \ 4 \ x^4 ) \ - \ 5 \ x^2 \ - \ 6 \ x^4 \ + \ 3 \ x^3⇒- \ 10 \ x^4 \ + \ 11\ x^3 \ - \ x^2$$ 39- Choice C is correct The correct answer is $$6$$ metersThe width of the rectangle is twice its length.Let $$x$$ be the length. Then, width$$=2 \ x$$Perimeter of the rectangle is $$2$$ (width + length) $$= 2 \ (2 \ x \ + \ x)=36 ⇒ 6 = 36 ⇒x=6$$Length of the rectangle is $$6$$ meters. 40- Choice B is correct The correct answer is $$4$$Solve for $$y$$ .$$8 \ x \ - \ 2 \ y= 10 ⇒- \ 2 \ y=10 \ - \ 8 \ x⇒y=4 \ x \ - \ 5$$The slope of the line is $$4$$. 41- Choice C is correct The correct answer is $$32$$Five years ago, Ann was three times as old as Michael . Michael is $$14$$ years now. Therefore, $$5$$ years ago Michael was $$9$$ years. Five years ago, Ann was:A:$$=3 \ × \ 9=27$$Now Amy is $$32$$ years old:$$27 \ + \ 5 = 32$$ 42- Choice E is correct The correct answer is $$15$$Let $$x$$ be the number. Write the equation and solve for $$x$$. $$60\%$$ of $$x=9⇒ 0.60 \ x=9⇒x=9 \ ÷ \ 0.60=15$$ 43- Choice B is correct The correct answer is $$x^{10}$$The exponent "product rule" says that,when multiplying two powers that have the same base, you can add the exponents:$$(x^6)(x^4 )= x^{(6 \ + \ 4)}=x^{10}$$ 44- Choice D is correct The correct answer is $$48$$The amount of money that John earns for one hour: $$\frac{\ 720}{45}=\ 16$$Number of additional hours that he needs to work in order to make enough money is: $$\frac{\ 850 \ - \ \ 720}{2.5 \ × \ \ 16}=3$$Number of total hours is: $$45 \ + \ 3=48$$ 45- Choice B is correct The correct answer is $$14$$ hoursThe distance between Mike and Alex is $$7$$ miles. Mike running at $$4.5$$ miles per hour and Alex is running at the speed of $$5$$ miles per hour. Therefore, every hour the distance is $$0.5$$ miles less.$$7 \ ÷ \ 0.5 =14$$ 46- Choice B is correct The correct answer is $$14$$The formula for the area of the circle is: A$$=π \ r^2$$The area is $$49 \ π$$. Therefore:A$$=π \ r^2⇒49 \ π = π \ r^2$$Divide both sides by $$π$$:   $$49 = r^2⇒r=7$$Diameter of a circle is $$2 \ x$$ radius. Then:Diameter $$= 2 \ × \ 7 = 14$$ 47- Choice C is correct The correct answer is $$29\%$$$$\ 16$$ is what percent of $$\ 54$$ ?  $$16 \ ÷ \ 54 = 0.29 = 29\%$$ 48- Choice D is correct The correct answer is $$2400$$Let $$x$$ be the capacity of one tank. Then, $$\frac{3}{6} x=300→x=\frac{300 \ × \ 6}{3}=600$$ LitersThe amount of water in four tanks is equal to: $$4 \ × \ 600=2400$$ Liters 49- Choice D is correct The correct answer is $$60$$ ftWrite a proportion and solve for $$x$$.$$\frac{5}{3}=\frac{x}{36}⇒3 \ x=5 \ × \ 36⇒x=60$$ ft 50- Choice B is correct The correct answer is $$79\%$$The failing rate is $$15$$ out of $$70 = \frac{15}{70}$$Change the fraction to percent:$$\frac{15}{70} \ × \ 100\%=21\%$$$$21$$ percent of students failed. Therefore, $$79$$ percent of students passed the test.

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