Full Length ATI TEAS 6 Practice Test

The correct answer is \(25.12\)
Circumference \(= 2 \ πr\)
\(C = 2 \ π \ × \ 4 = 9 \ π\) 
\(π = 3.14    →      C = 8 \ π = 25.12\)

The correct answer is \(0\)
\((5.2 \ + \ 5.3 \ + \ 5.5) \ x =16 x\)
\(16 \ x = x\)
Then \(x = 0\)

The correct answer is \(\frac{5}{2}\)
\(\frac{1}{x} = \frac{\frac{1}{1}}{\frac{5}{2}} = \frac{5}{2}\)

The correct answer is \(2 \ (x \ – \ 5)\)
Let \(a\) and \(b\) be the numbers. Then: \(a \ + \ b = x\)
\(a=5  →  5 \ + \ b=x  →  b=x \ - \ 5\)
\(2 \ b = 2 \ (x \ – \ 5)\)

The correct answer is \(2 \ \frac{20}{42}\)
Converting mixed numbers to fractions, our initial equation becomes
\(\frac{8}{3} \ × \ \frac{13}{4}\)
Applying the fractions formula for multiplication
\(\frac{8 \ × \ 13}{3 \ × \ 14} = \frac{104}{42} = 2 \ \frac{20}{42}\)

The correct answer is \(0.45\)
\(\frac{9}{20} =0.45\)

The correct answer is \(4.5\)
If  \(4.5 \ < \ x \ ≤ \ 8.0\), then \(x\) cannot be equal to \(4.5\).

The correct answer is \(150\)
\(25 \ ÷ \ \frac{1}{6}=150\)

The correct answer is \(\frac{3}{2}\)
\(\frac{15}{10} = \frac{3}{2}\)

The correct answer is \(125\)
\(\frac{5^{4}}{5} = 5^{3} = 125\)

The correct answer is \(6\) meters
Perimeter of a rectangle \(= 2\) (width \(+\)  length)
P \(= 36\), width \(= 2 \ × \) length
Then: \(36=2 \ (2 \) length \(+\) length) \( →  \  36=6 \) length \(→\)  length\(=6\)

The correct answer is \(45\)
Let \(x\) be the average of numbers. Then:
\(\frac{150}{5} \ < \ x \ < \ \frac{250}{5}\)
\( 30\ < \ x \ < \ 50\)
From choices provided, only \(45\) is correct.

The correct answer is \(4\)  hours
The distance between Alex and Jack is \(6\) miles.
Alex running at \(4.5\) miles per hour and Jack is running at the speed of \(6\) miles per hour.
Therefore, every hour the distance is \(1.5\) miles less.
\(6 \ ÷ \ 1.5 = 4\)

The correct answer is \(\frac{1}{2}\)
\(3 \ \frac{1}{2} \ − \ 2 \ \frac{5}{6} = 3 \ + \ \frac{1}{3} \ - \ 2 \ - \ \frac{5}{6} = \frac{1}{2}\)

The correct answer is \(10\)
Volume \(=\) length \( × \) width \( × \) height
\(3000 = 15 \ × \ 20 \ × \) height \( →\) height \(= 10\)

The correct answer is \(9\) feet
yards \(= 12\) feet
\(\frac{(15 feet +7 yrds)}{4} = \frac{(15 feet +21 feet)}{4} = \frac{(36 feet)}{4} = 9\) feet

The correct answer is \(8 \ + \ c\)
If \(a = 4\)  then: \(b = \frac{4^{2}}{2} \ + \ c ⇒ \)
\(b = \frac{4^{2}}{2} \ + \ c = 8 \ + \ c\)

The correct answer is \(156\) inches
\(1\) foot \(= 12\) inches
\(4\) feet, \(8\) inches \(=56 \) inches
\(7\) feet, \(16\) inches \(= 100\) inches
\(56 \ + \ 100 =156\)

The correct answer is \((-3, -12)\)
Let’s review the choices provided. Put the values of \(x\) and \(y\) in the equation.
A. \((2, 4)\)              ⇒ \(x = 2\) ⇒ \(y = 4\)                This is true!
B. \((−3, −12)\)       ⇒ \(x = -3\) ⇒ \(y = -11\)       This is not true!
C. \((3, 7)\)            ⇒ \(x = 3\) ⇒ \(y = 7\)                 This is true!
D. \((1, 1)\)              ⇒ \(x = 1\) ⇒ \(y = 1\)                This is true!
Only choice B does not work in the equation.

The correct answer is \(151\)
Circumference \(= 2 \ π \ r →\)
Circumference \(= 2 \ (3.14) \ (24) = 150.72 \cong 151\)

The correct answer is \(58\) degrees
All angles in a triangle sum up to \(180\) degrees.
\(57 \ + \ 65 = 122\)
\(180 \ – \ 122 = 58\), The third angle is \(58\) degrees.

The correct answer is \(3\) hours
Jason spent \(10\%\) of his total time (\(30\) hours) on Physics.
Then: \(\frac{10}{100} \ × \ 30 = 3\)

The correct answer is approximately \(70\) hours
Speed \(= \frac{distance}{time}\)
\(60 = \frac{4,200}{time}→\) tme \(=\frac{4,200}{60} = 70\)

The correct answer is \(32\)
Plug in \(120\) for F in the equation:
C \(= \frac{2}{6}\) (F \(– \ 24) = \frac{2}{6} \ (120 \ – \ 24) = \frac{2}{6} \ (96) = 32\)

The correct answer is \(10\) hours
Jason spent \(50\%\) of his time on Biology and History.
Then: \(\frac{50}{100} \ × \ 20 = 10\)

The correct answer is \(342\)
Since Lucy gives \(6\) pieces of candy to each of her friends, then, then number of pieces of candies must be divisible by \(6\).
A.  \(125 \ ÷ \ 6 = 20.833\)
B.  \(235 \ ÷ \ 6 = 39.166\)
C.  \(342 \ ÷ \ 6 =57 \)
D.  \(223 \ ÷ \ 6 = 37.166\)
Only choice C gives a whole number.

The correct answer is \(1.66\)
\(\frac{1}{2} \ + \ \frac{3}{6} \ + \ \frac{2}{3}= \frac{3 \ + \ 3 \ + \  4}{6}=\frac{10}{6}=1.66\)

The correct answer is \(0.89\) D
To find the discount, multiply the number by (\(100\%   \ –\)   rate of discount).
Therefore, for the first discount we get: (D) (\(100\% \ – \ 15\%\)) = (D) (\(0.85\)) = \(0.85\) D
For increase of \(5\%\) : (\(0.85\) D) (\(100\% \ + \ 5\%\)) = (\(0.85\) D) (\(1.05) = 0.89\) D \(= 89\%\) of D or \(0.89\) D

The correct answer is $\(3.8\)
\(25\%\) of \(x = 15.20\)
\(x=\frac{25 \ × \ 15.20}{100}=3.8\)

The correct answer is \(25\)
\(\frac{1}{8}=0.125→C=5, \frac{1}{20}=0.05→D=5→\)
\(C \ × \ D=5 \ × \ 5=25\)

The correct answer is ($1,\050\)
Use simple interest formula:
\(I= prt\)
(\(I=\) interest, \(p=\) principal, \(r=\) rate, \(t=\) time)
\(I=(14000) \ (0.025) \ (3)=1,050\)

The correct answer is \(115 \ x \ + \ 12,000 \ ≤ \ 25,000\)
Let \(x\) be the number of new shoes the team can purchase.
Therefore, the team can purchase \(115 \ x\).
The team had \($25,000\) and spent \($12,000\).
Now the team can spend on new shoes \($8,000\) at most.
Now, write the inequality:
\(115 \ x \ + \ 12,000 \ ≤ \ 25,000\)

The correct answer is \(5\)
Let \(x\) be the number. Then: \(4 \ x \ + \ 5=25\)
Solve for \(x: \ 4 \ x \ + \ 5=25   →4 \ x=25 \ - \ 5=20   →x=20 \ ÷ \ 4=5\)

The correct answer is \(\frac{1}{5}\)
\(\frac{3}{2} \ x \ + \ \frac{1}{5}= \frac{1}{2}  \  →\frac{3}{2} \ x = \frac{1}{2} \ - \ \frac{1}{5}  \  →\)
\(\frac{3}{2} \ x =\frac{5 \ - \ 2}{10}  \  →\frac{3}{2} \ x = \frac{3}{10}\)
\(x = \frac{6}{30} = \frac{1}{5}\)

The correct answer is \(\frac{1}{4}\)
To get a sum of \(4\) for two dice, we can get \(3\) different options:
\((1, 3)\), \((2, 2)\), \((3, 1)\)
To get a sum of \(7\) for two dice, we can get \(6\) different options:
\((1, 6)\), \((2, 5)\), \((3, 4),\ (4 , 3) , \ ( 5 , 2) , \ (6 , 1)\)
Therefore, there are \(9\) options to get the sum of \(4\) or \(7\).
Since, we have \(6 \ × \ 6 = 36\) total options, the probability of getting a sum of \(4\) and \(7\) is \(9\) out of \(36\) or \(\frac{1}{4}\).

The correct answer is D
Solve for \(x\). \(-2 \ ≤ \ 2 \ x \ - \ 4 \ < \ 8    ⇒\) (add \(4\) all sides) \(-2 \ + \ 4 \ ≤ \ 2 \ x \ - \ 4 \ + \ 4 \ < \ 8 \ + \ 4 \)
\(⇒ \ 2 \ ≤ \ 2 \ x \ < \ 12 \ ⇒\) (divide all sides by \(2) \ 1 \ ≤ \ x \ < \ 6 \ x\) is between \(1\) and \(6\).
Choice D represent this inequality.