GED Math Practice Test

The correct answer is \(- \ 248\)
Use PEMDAS (order of operation):
\([ 8 × (-32) + 12] \) \(+\) \(4\) \(-\) \([ 8 \ ×\  2 ]\) \(÷\) \(2\) \(=\) \([ - \ 256 \ +\  12] \) \(+\) \(4\) \(-\) \([16] \) \(÷\) \(2\) \(=\)
\([ -\  256 \ + \  12] \) \(+\) \(4\) \(-\) \([8] \) \(=\) \([ - \  244] \) \(+\) \(4\) \(-\) \([8] \) \(=\) \([ - \ 244] \) \(+\) \(4\) \(-\) \(8\) \(=\) \(- \ 248\)

The correct answer is \(12\ x^2 \ -\ 5\ x\ y \ - \  2\ y^2\)
Use FOIL method.
\((4\ x \  + \ y) \ (3\ x \ - \ 2\ y)= 12\ x^2 \ -\  8\ x\ y + 3\ x\ y - 2\ y^2 = 12\ x^2 - 5\ x\ y \ - \ 2 \ y^2\)

The correct answer is \(24\)
To solve absolute values equations, write two equations 
\(y-7\) could be positive \(5\), or negative \(5\). Therefore, 
\(y-7\)\(=\) \(5\) \(⇒\) \(y\) \(=\) \(12\)
\(y-7\)\(=\) \(-5\) \(⇒\) \(y\) \(=\) \(2\)
Find the product of solutions: \(2\) \(×\) \(12\) \(=\) \(24\)

The correct answer is \(-\ \frac{2}{3}\)
The equation of a line in slope intercept form is: \(y = mx + b\)
Solve for \(y\).
\(3\ x\) \(-\) \(2\ y\) \(=\) \(8\) \(⇒\) \(-\ 2\ y\) \(=\) \(8\) \(-\) \(3\ x\) \(⇒\) \(y\) \(=\) \((8 \ -\  3\ x)\)  \(÷\) \((-\ 2)\) \(⇒\)
\(y\) \(=\) \(1.5\ x \ -\  4\)
The slope of this line is \(1.5\).
The product of the slopes of two perpendicular lines is \(-\ 1\). Therefore, the slope of a line that is perpendicular to this line is:
\(𝑚_1 \ ×\  𝑚_ 2 = −\ 1 ⇒ 1.5 × 𝑚_2 = −\ 1 ⇒ 𝑚_2 = −\ \frac{2}{3}\)

The correct answer is \(-\ 27\)
Plug in the value of \(x\) and \(y\).
 \(x = 1\) and \(y = 5\)
\(2\) \((x\ -\  3\ y)\) \(+\) \((4 \ -\  y)\)\((4 \ -\  y)\) \(=\) \(2\) \((1\ -\  3\ (5))\) \(+\) \((4 \ -\  5)\) \((4 \ -\  5)\) \(=\)
\(2\) \((1\ -\  15)\) \(+\) \((-\ 1)\) \((-\ 1)\) \(=\) \(2\) \((-\ 14)\) \(+\) \(1\) \(=\) \(-\ 27\)

The correct answer is \(20\)
Let \(x\) be the number. Write the equation and solve for \(x\).
\(60\)% of \(x\) \(=\) \(12\) \(⇒\) \(0.6 \ x\) \(=\) \(12\) \(⇒\) \(x\) \(=\) \(12\) \(÷\) \(0.6\) \(=\) \(20\)

The correct answer is \(10\)
\(x\) is \(1.5\) times of \(y\), then \(x = 1.5\ y\) \(⇒\) (\(x = 15\))   \(15\) \(=\) \(1.5\) \(×\) \(y\) \(⇒\)
\(y\) \(=\) \(15\) \(÷\) \(1.5\) \(=\) \(10\)

The correct answer is \(2\) hours
The distance between Alex and Jack is \(12\) miles.
Jack running at \(4\) miles per hour and  Alex is running at the speed of \(10\) miles per hour.
Therefore, every hour the distance is \(6\) miles less. \(12\) \(÷\) \(6\) \(=\) \(2\)

The correct answer is \(80\)%
The failing rate is \(6\) out of \(30\) \(=\) \(\frac{6}{30}\)
Change the fraction to percent:
\(\frac{6}{30}\) × \(100\)% \(=\) \(20\)%
\(20\) percent of students failed. Therefore, \(80\) percent of students passed the exam.

The correct answer is \(16\)
\(2^4\)\(=\) \(2\)\(×\)\(2\)\(×\)\(2\)\(×\)\(2\)\(=\) \(16\)

The correct answer is  \(2\) \(≤\) \(x\) \(<\) \(3\) 
Solve for \(x\).
\(2\) \(≤\) \(3x - 4\) \(<\) \(5\) \(⇒\) (add 4 all sides) \(2 + 4\) \(≤\)  \(3x\) \(<\) \(5 + 4\) \(⇒\)
\(6\) \(≤\) \(3x\) \(<\) \(9\) \(⇒\) (divide all sides by \(3\))  \(2\) \(≤\) \(x\) \(<\) \(3\) 
\(x\) is between \(2\) and \(3\) . 

The correct answer is \(14\)
Let \(x\) be the width of the rectangle. Use Pythagorean Theorem:
\(a^2 + b^2 = c^2\)
\(4^2 + x^2 = 5^2\) \(⇒\) \( x^2 + 16 = 25\) \(⇒\) \( x^2\) \(=\) \(25 - 16\) \(=\) \(9\)  \(⇒\)  \(x\) \(=\) \(3\)
Perimeter of the rectangle \(=\) \(2\) (length + width) \(=\) \(2\) \((4 + 3 )\) \(=\) \(2\) \((7)\) \(=\) \(14\)

The correct answer is \(160\)
The perimeter of the trapezoid is \(50\) cm.
Therefore, the missing side (height) is \( = 50 \ – \ 14 \  – \ 12 \ – \ 8 = 16\)
Area of a trapezoid: A \(= \frac{1}{2}\  h \ (b_1 \ +\  b_ 2) =  \frac{1}{2} \ (16) \ (12 \ + \ 8) = 160\)

The correct answer is \(\frac{1}{3}\)
The probability of choosing a diamond is \(\frac{21}{63}\) = \(\frac{1}{3}\)

The correct answer is : \(\frac{1}{3}\)\(<\)\(0.35\)\(<\)\(36\%<65\%\)
Change the numbers to decimal and then compare.
\(\frac{1}{3}\) = \(0.333...\)
\(0.35\)
\(36\)% = \(0.36\)
\(65\)% = \(0.65\)
\(0.333...\)\(<\)\(0.35\)\(<\)\(0.36\)\(<\)\(0.65\)

The correct answer is \(84.5\)
average (mean) = \(\frac{sum \ of \  terms}{number \ of \  terms}\)\(⇒\) \(85\) = \(\frac{sum \ of \  terms}{40}\)\(⇒\) sum = \(85 × 40 = 3400\)
The difference of \(92\) and \(72\) is \(20\). Therefore, \(20\) should be subtracted from the sum. 
\(3400 - 20 = 3380\)
mean = \(\frac{sum \ of \  terms}{number \ of \  terms}\)\(⇒\) mean = \(\frac{3380}{40}\) = \(84.5\)

The correct answer is \(\frac{1}{6}\)
To get a sum of \(6\) or \(8\) for two dice, we should get \(3\) and \(3\), or \(2\) and \(4\), or \(1\) and \(5\) or \(3\) and \(5\) or \(2\) and \(6\) or \(4\) and \(4\).
Therefore, there are \(6\) options.
Since, we have \(6 × 6 = 36 \) total options, the probability of getting a sum of \(6\) and \(8\) is \(6\) out of \(36\) or \(\frac{1}{6}\).

The correct answer is \(10\)
Use formula of rectangle prism volume
\(V =\) (length) (width) (height) ⇒ \(1500 = (20\)) (\(7.5\)) (height) ⇒  height \( =1500 \ ÷ \ 150 =  10\)

The correct answer is \(8\)
To find the number of possible outfit combinations, multiply the number of options for each factor:
\(4 × 1 × 2 = 8\)

The correct answer is : \(12\)
\(4 \ ÷ \ \frac{1}{3}\) = \(12\)

The correct answer is : \(50\)
The diagonal of the square is \(10\). Let \(x\) be the side.
Use Pythagorean Theorem: \(a^2\) + \(b^2\) = \(c^2\)
\(x^2\) \(+\) \(x^2\) \(=\) \(10^2\) \(⇒\) \(2\ x^2\) \(=\) \(10^2\)
 \(⇒\)  \(x^2\) \(=\) \(50\) \(⇒\) \(x\) \(=\) \(\sqrt{50}\)
The area of the square is: \(\sqrt{50}\) \(×\) \(\sqrt{50}\) \(=\) \(50\)

The correct answer is : \(\frac{1}{5}\)
Probability = \(\frac{number \ of \  desired\ outcomes}{number \ of\  total \  outcomes}\) =  \(\frac{12}{20 + 12 + 12 + 16}\) = \(\frac{1}{5}\)

The correct answer is \(37\)
Find the difference of each pairs of numbers:
\(2\), \(4\), \(7\), \(11\), \(16\), \(22\), \(29\), ___, \(46\)
The difference of \(2\) and \(4\) is \(2\), \(4\) and \(7\) is \(3\), \(7\) and \(11\) is \(4\), \(11\) and \(16\) is \(5\),
\(16\) and \(22\) is \(6\), \(22\) and \(29\) is \(7\), \(29\) and next number should be \(8\). The number is \(29\) + \(8\) = \(37\)

The correct answer is \(13.33\) 
The width of the rectangle is twice its length. Let \(x\) be the length. Then, width\( =2\ x\)
Perimeter of the rectangle is \(2\) (width + length) \( = 2 \ (2\ x  \ + \ x ) =  80 ⇒  6\ x = 80  ⇒  x  =  13.33\)
The length of the rectangle is \(13.33\) meters.

The correct answer is : \(32\)
average = \(\frac{sum \ of \ terms}{number \ of \ terms}\) \(⇒\) (average of \(6\) numbers) \(16\) =  \(\frac{sum \ of \ terms}{6}\)
\(⇒\) sum  of \(6\) numbers is \(16 × 6 = 96\)  (average of \(4\) numbers) \(8\) = \(\frac{sum \ of \ numbers}{4}\)
\(⇒\) sum  of \(4\) numbers is \(4 × 8 = 32\) 
 sum  of \(6\) numbers - sum  of \(4\) numbers = sum  of \(2\) numbers \(⇒\) \(96 - 32 = 64\) 
(average of \(2\) numbers) = \(\frac{64}{2}\) = \(32\)

The correct answer is \(0\)
Solving Systems of Equations by Elimination
Multiply the first equation by (\(-3\)), then add it to the first equation.
\(-\ 3 \  (3\ x \ +\  y = 9\))
\(x \ +\  3\ y = 3\)
\(⇒\) \(-\ 9\ x \ -\  3\ y = -\ 27\)   \(⇒\) \(-\ 8\ x = -\ 24\) \(⇒\) \(x = 3\)
\(x \ +\  3\ y = 3\)
Plug in the value of \(x\) into one of the equations and solve for \(y\).
 \( 3\ (3\)) + \(y\) \(=\) \(9\) \(⇒\) \(y = 0\)

The correct answer is \(35\)
Solve for the sum of four numbers.  
average = \(\frac{sum \ of \  terms}{number \ of \  terms}\) \(⇒\) \(32\) =  \(\frac{sum  \ of \  4 numbers}{4}\)
\(⇒\) sum  of  \(4\) numbers = \(32 \ ×\   4 = 128\)  
The sum of \(4\) numbers is \(128\). If a fifth number \(47\) is added, then the sum of \(5\)  numbers is \(128 \ +\  47 = 175\)
average = \(\frac{sum  \ of \  terms}{number \ of \ terms} = \frac{175}{5}\) = \(35\)

The correct answer is \(5\)
Th ratio of boy to girls is \(3: 7\). Therefore, there are \(3\) boys out of \(10\) students.
To find the answer, first divide the total number of students by \(10\), then multiply the result by 4.
\(30\) ÷ \(10\) = \(3\) ⇒ \(3\) × \(3\) = \(9\)
There are \(9\) boys and \(21\) (\(30 - 9\)) girls.
So, \(5\) more boys should be enrolled to make the ratio \(2:3\)

The correct answer is \(\frac{1}{6}\)
\(5000\) out of \(30000\) equals to = \(\frac{5000}{30000}\) = \(\frac{5}{30}\) =  \(\frac{1}{6}\)

The correct answer is \(150\ x + 38000 ≤ 50000\)
Let \(x\) be the number of new shoes the team can purchase. Therefore, the team can purchase \(150\ x\).
The team had $\(50000\) and spent \($38000\). Now the team can spend on new shoes \($12000\) at most.
Now, write the inequality:
\(150\ x \  + \ 38000  ≤ 50000\)

The correct answer is \(65\)
Jack needs an \(70\%\) average to pass for four exams.
Therefore, the sum of \(4\) exams must be at lease \(4 \ × \ 70  = 280\)The sum of \(3\) exams is: \(63\) \(+\) \(67\) \(+\) \(85\) \(=\) \(215\)
The minimum score Jack can earn on his fifth and final test to pass is:
\(280 \ -\  215 = 65\)

The correct answer is  \(\frac{1}{3}\)
\(\frac{1}{4}\ x \  - \ \frac{1}{6} =  \frac{-\ 1}{12}\) 
\(⇒\) \(\frac{1}{4}\ x =  \frac{-\ 1}{12} \ + \ \frac{1}{6} = \frac{1}{12}\) \(⇒\) \(\frac{1}{4}\  x =  \frac{1}{12}\)
Multiply both sides by the reciprocal of the coefficient of \(x\)
(\(\frac{4}{1}\)) \(\frac{1}{4}\ x = \frac{1}{12}\) (\(\frac{4}{1}\)) \(⇒\) \(x =  \frac{1}{3}\)

The correct answer is \(2160\)
Use simple interest formula:
\(I=prt\)
(\(I =\) interest, \(p =\) principal, \(r =\) rate, \(t =\) time)
\( I = (18000\)) (\(0.03\)) (\(4\)) = \(2160\)

The correct answer is \(21\ x^5\  y^4\)
Simplify. 
\(3\  x\  y^2 \  (7\ x^4 \ y^2 ) = 21\ x^5 \  y^4\) 

The correct answer is \(110\ π\ i n^2\)
Surface Area of a cylinder \(= 2\ π\ r\ (r\ +\ h)\),
The radius of the cylinder is \(5\ (10 \ ÷\ 2)\) inches and its height is \(6 \) inches. Therefore, 
Surface Area of a cylinder \(= 2\ π\ (5 )\ (5 \ +\ 6 ) = 110 \ π\)

The correct answer is \(\frac{512}{1331}\)
The square of a number is \(\frac{64}{121}\), then the number is the square root of \(\frac{64}{121}\)
\(\sqrt{\frac{64}{121}}\) = \(\frac{8}{11}\)
The cube of the number is: (\(\frac{8}{11}\))³ = \(\frac{512}{1331}\)

The correct answer is \(12\)
Write the numbers in order:
\(2\),\(4\),\(12\),\(14\),\(21\)
edian is the number in the middle. So, the median is \(12\).

The correct answer is \(100\) miles
Use the information provided in the question to draw the shape.
Use Pythagorean Theorem: \(a^2 + b^2 = c^2\)
\(60^2 \ + \ 80^2 = c^2\) \(⇒\) \(3600 \ + \ 6400 = c^2\) \(⇒\) \(10000 = c^2\) \(⇒\) \(c = 100\) miles

The correct answer is \(25.55\)
Plug in \(78\) for F and then solve for C.
C\( = \frac{5}{9} (F \ -\  32) ⇒\) C\( =\frac{5}{9}\)(\(78 \ -\  32\)) \(⇒\) C\( = \frac{5}{9}\)(\(46\)) \(= 25.55\)

The correct answer is \(34\) 
First, find the number. Let \(x\) be the number. Write the equation and solve for \(x\).
\(250\) % of a number is \(100\), then:
\(2.5 × x = 100\) \(⇒\) \(x =100 ÷ 2.5 = 40\)  
\(85\) % of \(40\) is \(34\) 

The correct answer is \(1\)
Solve for \(y\) .
\(3\ x \ -\  3\ y = 1\) \(⇒\) \(-\ 3\ y = 1 \ -\  3\ x\) \(⇒ y = x \ - \ \frac{1}{3}\)
The slope of the line is \(1\).

The correct answer is \(126\)
Volume of a box = length × width × height = \(3 × 6 × 7 = 126\) 

The correct answer is (\( 5\ x^4\  +\  3\ x^3 \))
(\(3\ x \ + \ 4\ x^3 \ +\  3\ x^4) \ +\  (-\ x^3 \ -\ 3\ x\  + \ 2\ x^4\)) \(⇒\) \(( 3 \ x^4\ + \ 4\ x^3\  +\  3\ x ) \ +\  ( 2\ x^4\  -\  x^3\  -\  3\ x\)) \(=\) (\( 5\ x^4 \ + \ 3\ x^3 \))

The correct answer is \(145\%\)
the population is increased by \(10\%\) and \(12\%\) and \(18\%\) . \(10\%\) increase changes the population to \(110\%\) of original population.
For the second increase, multiply the result by \(112\%\).
For the third increase, multiply the result by \(118\%\)
(\(1.10) \ × \ (1.12) \ × \ ( 1.18) = 1.45 = 145\%\)

The correct answer is \(72000\)
Three times of \(30000\) is \(90000\). One fifth of them cancelled their tickets.
One fifth of \(90000\) equals \(18000\).
\(72000\)  (\(90000\) – \(18000\) = \(72000\)) fans are attending this week

The correct answer is \(88.4\)
The area of the square is \(488.41\). Therefore, the side of the square is a square root of the area.
\(\sqrt{488.41} = 22.1\)
Four times the side of the square is the perimeter:
\(4 \ ×\  22.1 = 88.4\)