## Full Length STAAR Grade 8 Practice Test

If you want to prepare for the STAAR Grade 8 Practice Test? It’s time to taking a Full-length STAAR Grade 8 Practice Test. It is the best way to simulate test day. To challenge your skills and simulate the full length STAAR Grade 8 Practice Test day experience, score your tests using the answer keys.

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## STAAR Math Practice Test 1

1- A rope weighs $$600$$ grams per meter of length. What is the weight in kilograms of $$12.2$$ meters of this rope? ($$1$$ kilograms $$= 1000$$ grams)
(A) $$0.0732$$
(B) $$0.732$$
(C) $$7.32$$
(D) $$7,320$$
2- In a school, the ratio of number of boys to girls is $$3:7$$. If the number of boys is $$180$$, what is the total number of students in the school?
(A) 600
(B) 600
(C) 600.0
3- In two successive years, the population of a town is increased by $$15\%$$ and $$20\%$$. What percent of its population is increased after two years?
(A) $$32$$
(B) $$35$$
(C) $$38$$
(D) $$68$$
4- Which graph shows a non–proportional linear relationship between $$x$$ and $$y$$?
(A)
(B)
(C)
(D)
5- In the rectangle below if $$y \ > \ 5$$ cm and the area of rectangle is $$50$$ cm$$^2$$ and the perimeter of the rectangle is $$30$$ cm, what is the value of $$x$$ and $$y$$ respectively?
(A) $$4, 11$$
(B) $$5, 11$$
(C) $$5, 10$$
(D) $$4, 10$$
6- A football team had $$40,000$$ to spend on supplies. The team spent $$22,000$$ on new balls. New sport shoes cost $$240$$ each. Which of the following inequalities represent how many new shoes the team can purchase.
(A) $$240 \ x \ + \ 22,000 \ ≤ \ 40,000$$
(B) $$240 \ x \ + \ 22,000 \ ≥ \ 40,000$$
(C) $$22,000 \ x \ + \ 240 \ ≤ \ 40,000$$
(D) $$22,000 \ x \ + \ 240 \ ≥ \ 40,000$$
7- Right triangle ABC has two legs of lengths $$6$$ cm (AB) and $$8$$ cm (AC). What is the length of the third side (BC)?
(A) $$4$$ cm
(B) $$6$$ cm
(C) $$8$$ cm
(D) $$10$$ cm
8- If $$3 \ x \ - \ 5=8.5$$, What is the value of $$5 \ x \ + \ 3$$ ?
(A) $$13$$
(B) $$15.5$$
(C) $$20.5$$
(D) $$25.5$$
9- A bank is offering $$4.5\%$$ simple interest on a savings account. If you deposit $$8,000$$, how much interest will you earn in five years?
(A) $$360$$
(B) $$720$$
(C) $$1800$$
(D) $$3600$$
10- In a party, $$10$$ soft drinks are required for every $$12$$ guests. If there are $$252$$ guests, how many soft drink is required?
(A) $$21$$
(B) $$105$$
(C) $$210$$
(D) $$2510$$
11- A chemical solution contains $$4\%$$ alcohol. If there is $$24$$ ml of alcohol, what is the volume of the solution?
(A) $$240$$ ml
(B) $$480$$ ml
(C) $$600$$ ml
(D) $$1200$$ ml
12- What is the area of the shaded region?
(A) $$31$$ ft.$$^2$$
(B) $$40$$ ft.$$^2$$
(C) $$64$$ ft.$$^2$$
(D) $$80$$ ft.$$^2$$
13- A $$40$$ shirt now selling for $$28$$ is discounted by what percent?
(A) $$20\%$$
(B) $$30\%$$
(C) $$40\%$$
(D) $$60\%$$
14- How much interest is earned on a principal of $$5000$$ invested at an interest rate of $$5\%$$ for four years?
(A) $$250$$
(B) $$500$$
(C) $$1000$$
(D) $$2000$$
15- A swimming pool holds $$2,000$$ cubic feet of water. The swimming pool is $$25$$ feet long and $$10$$ feet wide. How deep is the swimming pool?
(A) 8
(B) 8
(C) 8.0
16- The price of a car was $$20,000$$ in $$2014, \ 16,000$$ in $$2015$$ and $$12,800$$ in $$2016$$. What is the rate of depreciation of the price of car per year?
(A) $$15\%$$
(B) $$20\%$$
(C) $$25\%$$
(D) $$30\%$$
17- What is the area of the shaded region if the diameter of the bigger circle is $$12$$ inches and the diameter of the smaller circle is $$8$$ inches.
(A) $$16 \ π$$
(B) $$20 \ π$$
(C) $$36 \ π$$
(D) $$80 \ π$$
18- What is the area of an isosceles right triangle that has one leg that measures 6 cm?
(A) 18
(B) 18
(C) 18.0
(D) 18.00
19- A taxi driver earns $$9$$ per $$1-$$hour work. If he works $$10$$ hours a day and in $$1$$ hour he uses $$2-$$liters petrol with price $$1$$ for $$1-$$liter. How much money does he earn in one day?
(A) $$90$$
(B) $$88$$
(C) $$70$$
(D) $$60$$
20- Five years ago, Amy was three times as old as Mike was. If Mike is $$10$$ years old now, how old is Amy?
(A) $$4$$
(B) $$8$$
(C) $$12$$
(D) $$20$$
21- What is the solution of the following system of equations?
$$\begin{cases}\frac{ - \ x}{2} \ + \ \frac{y}{4}=1\\ \frac{- \ 5 \ y}{6} \ + \ 2 \ x =4 \end{cases}$$
(A) $$x=48, \ y=22$$
(B) $$x=50, \ y=20$$
(C) $$x=20, \ y=50$$
(D) $$x=22, \ y=48$$
22- What is the length of AB in the following figure if AE $$=4$$, CD $$=6$$ and AC $$=12$$?
(A) $$3.8$$
(B) $$4.8$$
(C) $$7.2$$
(D) $$24$$
23- If a gas tank can hold $$25$$ gallons, how many gallons does it contain when it is $$\frac{2}{5}$$  full?
(A) $$50$$
(B) $$125$$
(C) $$62.5$$
(D) $$10$$
24- In the $$x \ y -$$plane, the point $$(4, \ 3)$$ and $$(3, \ 2)$$ are on line A. Which of the following equations of lines is parallel to line A?
(A) $$y=3 \ x$$
(B) $$y=\frac{x}{2}$$
(C) $$y=2 \ x$$
(D) $$y=x$$
25- If $$x$$ is directly proportional to the square of $$y$$, and $$y=2$$ when $$x=12$$, then when $$x=75, \ y=$$ ?
(A) $$\frac{1}{5}$$
(B) $$1$$
(C) $$5$$
(D) $$12$$
26- Jack earns $$616$$ for his first $$44$$ hours of work in a week and is then paid $$1.5$$ times his regular hourly rate for any additional hours. This week, Jack needs $$826$$ to pay his rent, bills and other expenses. How many hours must he work to make enough money in this week?
(A) $$40$$
(B) $$48$$
(C) $$53$$
(D) $$54$$

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27- If $$a$$ is the mean (average) of the number of cities in each pollution type category, $$b$$ is the mode, and $$c$$ is the median of the number of cities in each pollution type category, then which of the following must be true?
(A) $$a \ < \ b \ < \ c$$
(B) $$b \ < \ a \ < \ c$$
(C) $$a=c$$
(D) $$b \ < \ c=a$$
28- What percent of cities are in the type of pollution A, C, and E respectively?
(A) $$60\%, \ 40\%, \ 90\%$$
(B) $$30\%, \ 40\%, \ 90\%$$
(C) $$30\%, \ 40\%, \ 60\%$$
(D) $$40\%, \ 60\%, \ 90\%$$
29- How many cities should be added to type of pollutions B until the ratio of cities in type of pollution B to cities in type of pollution E will be $$0.625$$?
(A) $$2$$
(B) $$3$$
(C) $$4$$
(D) $$5$$
30- In the following right triangle, if the sides AB and AC become twice longer, what will be the ratio of the perimeter of the triangle to its area?
(A) $$\frac{1}{2}$$
(B) $$2$$
(C) $$\frac{1}{3}$$
(D) $$3$$
31- The capacity of a red box is $$20\%$$ bigger than the capacity of a blue box. If the red box can hold $$30$$ equal sized books, how many of the same books can the blue box hold?
(A) $$9$$
(B) $$15$$
(C) $$25$$
(D) $$21$$
32- The sum of six different negative integers is $$- \ 70$$. If the smallest of these integers is $$- \ 15$$, what is the largest possible value of one of the other five integers?
(A) $$− \ 14$$
(B) $$− \ 10$$
(C) $$− \ 5$$
(D) $$− \ 1$$
33- In the figure below, what is the value of $$x$$?
(A) $$43^°$$
(B) $$67^°$$
(C) $$77^°$$
(D) $$90^°$$
34- The following table represents the value of $$x$$ and function $$f(x)$$. Which of the following could be the equation of the function $$f(x)$$?
(A) $$f(x)=x^2 \ − \ 5$$
(B) $$f(x)=x^2 \ − \ 1$$
(C) $$f(x)=\sqrt{x \ + \ 2}$$
(D) $$f(x)=\sqrt{x } \ + \ 4$$
35- The circle graph below shows all Mr. Green’s expenses for last month. If he spent $$660$$ on his car, how much did he spend for his rent?
(A) $$700$$
(B) $$740$$
(C) $$780$$
(D) $$810$$
36- The Jackson Library is ordering some bookshelves. If $$x$$ is the number of bookshelves the library wants to order, which each costs $$100$$ and there is a one-time delivery charge of $$800$$, which of the following represents the total cost, in dollar, per bookshelf?
(A) $$100\ x \ + \ 800$$
(B) $$100 \ + \ 800 \ x$$
(C) $$\frac{100 \ x + \ 800}{100}$$
(D) $$\frac{100 \ x + \ 800}{x}$$
37- What is the sum of $$\sqrt{x \ - \ 7}$$ and $$\sqrt{x \ - \ 7}$$ when $$\sqrt{x=4}$$ ?
(A) $$− \ 3$$
(B) $$− \ 1$$
(C) $$0$$
(D) $$3$$
38- In the following figure, point Q lies on line n, what is the value of $$y$$ if $$x = 35$$?
(A) $$15$$
(B) $$25$$
(C) $$35$$
(D) $$45$$
39-  What is the smallest integer whose square root is greater than $$6$$?
(A) $$16$$
(B) $$25$$
(C) $$37$$
(D) $$49$$
40- What is the value of $$|- \ 12 \ - \ 5| \ - \ |- \ 8 \ + \ 2|$$?
(A) $$11$$
(B) $$- \ 11$$
(C) $$23$$
(D) $$- \ 23$$
 1- Choice C is correct The correct answer is $$7.32$$The weight of $$12.2$$ meters of this rope is:$$12.2 \ × \ 600$$ g $$= 7320$$ g$$1$$ kg $$= 1000$$ g, therefore, $$7320$$ g $$÷ 1000 = 7.32$$ kg 2- Choice C is correct The correct answer is $$600$$The ratio of boys to girls is $$3:7$$. Therefore, there are $$3$$ boys out of $$10$$ students.To find the answer, first divide the number of boys by $$3$$, then multiply the result by $$10$$. $$180 \ ÷ \ 3 = 60 ⇒$$$$60 \ × \ 10 = 600$$ 3- Choice C is correct The correct answer is $$38$$the population is increased by $$15\%$$ and $$20\%$$.$$15\%$$ increase changes the population to $$115\%$$ of original population. For the second increase, multiply the result by $$120\%$$.$$(1.15) \ × \ (1.20) = 1.38 = 138\%$$$$38$$ percent of the population is increased after two years. 4- Choice B is correct A linear equation is a relationship between two variables, $$x$$ and $$y$$, that can be put in the form $$y = m \ x \ + \ b$$. A non-proportional linear relationship takes on the form $$y = m \ x \ + \ b$$, where $$b ≠ 0$$ and its graph is a line that does not cross through the origin. 5- Choice C is correct The correct answer is $$5, \ 10$$The perimeter of the rectangle is:$$2 \ x \ + \ 2 \ y=30→$$$$x \ + \ y=15→$$$$x=15 \ - \ y$$ The area of the rectangle is:$$x \ × \ y=50→$$$$(15 \ - \ y) \ (y)=50→$$$$y^2 \ - \ 15 \ y \ + \ 50=0$$ Solve the quadratic equation by factoring method.$$(y \ - \ 5) \ (y \ - \ 10)=0→$$$$y=5$$ (Unacceptable, because $$y$$ must be greater than $$5$$) or $$y=10$$If $$y=10 →$$$$x \ × \ y=50→$$$$x \ × \ 10=50→$$$$x=5$$ 6- Choice A is correct The correct answer is $$120 \ x\ + \ 22.000 \ ≤ \ 40.000$$Let $$x$$ be the number of new shoes the team can purchase. Therefore, the team can purchase $$240 \ x$$.The team had $$40,000$$ and spent $$22,000$$.Now the team can spend on new shoes $$18,000$$ at most. Now, write the inequality: $$120 \ x\ + \ 22.000 \ ≤ \ 40.000$$ 7- Choice D is correct The correct answer is $$10$$ cmUse the information provided in the question to draw the shape.Use Pythagorean Theorem: $$a^2 \ + \ b^2 = c^2$$$$6^2 \ + \ 8^2 = c^2 ⇒$$$$100 = c^2 ⇒ c = 10$$ 8- Choice D is correct The correct answer is $$25.5$$$$3 \ x \ - \ 5=8.5→$$$$3 \ x=8.5 \ + \ 5=13.5→$$$$x=\frac{13.5}{3}=4.5$$Then; $$5 \ x \ + \ 3=5 \ (4.5) \ + \ 3=22.5 \ + \ 3=25.5$$ 9- Choice C is correct The correct answer is $$1800$$Use simple interest formula:$$I=prt$$($$I =$$ interest, $$p =$$ principal, $$r =$$ rate, $$t =$$ time)$$I=(8000) \ (0.045) \ (5)=1800$$ 10- Choice C is correct The correct answer is $$210$$Let $$x$$ be the number of soft drinks for $$252$$ guests.Write the proportion and solve for $$x$$.$$\frac{10 \ soft \ drinks}{12 guests}= \frac{x}{252 \ guests}$$ $$x = \frac{252 \ × \ 10}{12} ⇒x=210$$ 11- Choice C is correct The correct answer is $$600$$ ml$$4\%$$ of the volume of the solution is alcohol.Let $$x$$ be the volume of the solution. Then: $$4\%$$ of $$x = 24$$ ml $$⇒ 0.04 \ x = 24 ⇒$$$$x = 24 \ ÷ \ 0.04 = 600$$ 12- Choice B is correct The correct answer is $$40$$ ft.$$^2$$Use the area of rectangle formula $$(s = a \ × \ b)$$.To find area of the shaded region subtract smaller rectangle from bigger rectangle.S$$_{1} \ –$$ S$$_{2} = (10$$ ft $$× \ 8$$ ft) $$– \ (5$$ ft $$× \ 8$$ ft) $$⇒$$ S$$_{1} \ –$$ S$$_{2} = 40$$ ft.$$^2$$ 13- Choice B is correct The correct answer is $$30\%$$Use the formula for Percent of Change$$\frac{New \ Value-Old \ Value}{Old \ Value} \ × \ 100\%$$$$\frac{28 \ - \ 40}{40} \ × \ 100\% = \ – \ 30\%$$(negative sign here means that the new price is less than old price). 14- Choice C is correct The correct answer is $$1000$$Use simple interest formula:$$I=prt$$($$I =$$ interest, $$p =$$ principal, $$r =$$ rate, $$t =$$ time)$$I=(5000) \ (0.05) \ (4)=1000$$ 15- Choice C is correct The correct answer is $$8$$Use formula of rectangle prism volume.$$V =$$ (length) (width) (height) $$⇒ 2000 = (25) \ (10)$$ (height) $$⇒$$ height $$= 2000 \ ÷ \ 250 = 8$$ feet 16- Choice B is correct The correct answer is $$20\%$$Use this formula: Percent of Change$$\frac{New \ Value-Old \ Value}{Old \\ Value} \ × \ 100\%$$$$\frac{16000 \ - \ 20000}{20000} \ × \ 100\% = 20\%$$ and$$\frac{12800 \ - \ 16000}{16000} \ × \ 100\% = 20\%$$ 17- Choice B is correct The correct answer is $$20 \ \pi$$To find the area of the shaded region subtract smaller circle from bigger circle.S $$_{bigger} \ –$$ S $$_{smaller} = π \ (r _{bigger} )^2 \ – \ π \ (r _{smaller} )^2 ⇒$$S $$_{bigger} \ –$$ S $$_{smaller} = π \ (6)^2 \ – \ π \ (4)^2 ⇒$$$$36 \ π \ – \ 16 \ π = 20 \ π$$ 18- Choice D is correct The correct answer is $$18$$$$a=6⇒$$ area of the triangle is $$=\frac{1}{2} \ (6 \ × \ 6)=\frac{36}{2}=18$$ cm $$^2$$ 19- Choice C is correct The correct answer is $$70$$$$9 \ × \ 10=90$$Petrol use: $$10 \ × \ 2=20$$ litersPetrol cost:$$20 \ × \ 1=20$$Money earned:$$90 \ - \ 20=70$$ 20- Choice D is correct The correct answer is $$20$$Five years ago, Amy was three times as old as Mike.Mike is $$10$$ years now.Therefore, $$5$$ years ago Mike was $$5$$ years. Five years ago, Amy was:A $$=3 \ × \ 5=15$$Now Amy is $$20$$ years old: $$15 \ + \ 5 = 20$$ 21- Choice D is correct The correct answer is $$22$$$$\begin{cases}\frac{ - \ x}{2} \ + \ \frac{y}{4}=1\\ \frac{- \ 5 \ y}{6} \ + \ 2 \ x =4 \end{cases} \mapsto$$ Multiply the top equation by $$4$$. Then:$$\begin{cases}- \ 2 \ x \ + \ y=4\\ \frac{- \ 5 \ y}{6} \ + \ 2 \ x =4 \end{cases} \mapsto$$ Add two equations.$$\frac{1}{6} \ y=8→y=48$$ , plug in the value of $$y$$ into the first equation $$→x=22$$ 22- Choice B is correct The correct answer is $$4.8$$Two triangles $$\triangle$$BAE and $$\triangle$$BCD are similar. Then: $$\frac{AE}{CD}=\frac{AB}{BC}→$$$$\frac{4}{6}=\frac{x}{12}→$$$$48 \ - \ 4 \ x=6 \ x→$$$$10 \ x=48→$$$$x=4.8$$ 23- Choice D is correct The correct answer is $$10$$$$\frac{2}{5} \ × \ 25=\frac{50}{5}=10$$ 24- Choice D is correct The correct answer is $$y=x$$The slop of line A is: $$m=\frac{y_{2} \ - \ y_{1}}{x_{2} \ - \ x_{1}}=\frac{3 \ - \ 2}{4 \ - \ 3}=1$$ Parallel lines have the same slope and only choice D $$(y=x)$$ has slope of $$1$$. 25- Choice C is correct The correct answer is $$5$$$$x$$ is directly proportional to the square of $$y$$. Then:$$x=c \ y^2$$$$12=c \ (2)^2→$$$$12=4 \ c→$$$$c=\frac{12}{4}=3$$The relationship between $$x$$ and $$y$$ is:$$x=3 \ y^2$$$$x=75$$$$75=3 \ y^2→$$$$y^2=\frac{75}{3}=25→y=5$$ 26- Choice D is correct The correct answer is $$54$$The amount of money that jack earns for one hour:$$\frac{616}{44}=14$$$$\frac{826 \ - \ 616}{1.5 \ × \ 14}=10$$Number of total hours is:$$44 \ + \ 10=54$$ 27- Choice C is correct The correct answer is $$a= c$$ Let’s find the mean (average), mode and median of the number of cities for each type of pollution. Number of cities for each type of pollution: $$6, \ 3, \ 4, \ 9, \ 8$$ average (mean) $$= \frac{sum \ of \ terms}{number \ of \ terms}= \frac{6 \ + \ 3 \ + \ 4 \ + \ 9 \ + \ 8}{5}=\frac{30}{5}=6$$Median is the number in the middle. To find median, first list numbers in order from smallest to largest. $$3, \ 4, \ 6, \ 8, \ 9$$ Median of the data is $$6$$. Mode is the number which appears most often in a set of numbers.Therefore, there is no mode in the set of numbers. Median $$=$$ Mean, then, $$a= c$$ 28- Choice A is correct The correct answer is $$60\%, \ 40\%, \ 90\%$$ Percent of cities in the type of pollution A: $$\frac{6}{10} \ × \ 100=60\%$$Percent of cities in the type of pollution C: $$\frac{4}{10} \ × \ 100=40\%$$Percent of cities in the type of pollution E: $$\frac{9}{10} \ × \ 100=90\%$$ 29- Choice A is correct The correct answer is $$2$$ Let the number of cities should be added to type of pollutions B be $$x$$. Then:$$\frac{x \ + \ 3}{8}=0.625→$$$$x \ +\ 3=8 \ × \ 0.625→$$$$x \ + \ 3=5→$$$$x=2$$ 30- Choice A is correct The correct answer is $$\frac{1}{2}$$ AB $$=12$$ And AC $$=5$$BC $$=\sqrt{12^2 \ + \ 5^2}=\sqrt{144\ +\ 25}=\sqrt{169}=13$$Perimeter $$=5 \ + \ 12\ + \ 13=30$$Area $$=\frac{5 \ × \ 12}{2}=5 \ × \ 6=30$$In this case, the ratio of the perimeter of the triangle to its area is: $$\frac{30}{30}=1$$If the sides AB and AC become twice longer, then:AB $$=24$$ And AC $$=10$$BC $$=\sqrt{24^2 \ + \ 10^2}=\sqrt{576 \ + \ 100}=\sqrt{676}=26$$Perimeter $$=26 \ + \ 24 \ + \ 10=60$$ Area $$=\frac{10 \ × \ 24}{2}=10 \ × \ 12=120$$In this case the ratio of the perimeter of the triangle to its area is: $$\frac{60}{120}=\frac{1}{2}$$ 31- Choice D is correct The correct answer is $$21$$ The capacity of a red box is $$20\%$$ bigger than the capacity of a blue box and it can hold $$30$$ books.Therefore, we want to find a number that $$20\%$$ bigger than that number is $$30$$.Let $$x$$ be that number. Then:$$1.20 \ × \ x=30$$, Divide both sides of the equation by $$1.2$$. Then:$$x=\frac{30}{1.20}=25$$Number of books in $$30\%$$ of red box $$= \frac{30}{100} \ × \ 30=9→$$$$30 \ - \ 9=21$$ 32- Choice C is correct The correct answer is $$- \ 5$$ The smallest number is $$- \ 15$$.To find the largest possible value of one of the other five integers, we need to choose the smallest possible integers for four of them. Let $$x$$ be the largest number. Then:$$- \ 70=(- \ 15) \ + \ (- \ 14) \ + \ (- \ 13) \ + \ (- \ 12) \ + \ (- \ 11) \ + \ x→$$$$- \ 70=- \ 65 \ +\ x→$$$$x=- \ 70 \ + \ 65=- \ 5$$ 33- Choice B is correct The correct answer is $$- \ 5$$ $$α=180^° \ - \ 112^°=68^°$$$$β=180^° \ -\ 135^°=45^°$$$$x \ + \ α \ + \ β=180^°→$$$$x=180^° \ - \ 68^° \ - \ 45^°=67^°$$ 34- Choice D is correct The correct answer is $$f(x)=\sqrt{x} \ + \ 4$$ A. $$f(x)=x^2 \ - \ 5$$      if $$x=1→f(1)=(1)^2 \ - \ 5=1 \ - \ 5=- \ 4≠5$$ B. $$f(x)=x^2 \ - \ 1$$      if $$x=1→f(1)=(1)^2 \ - \ 1=1 \ - \ 1=0≠5$$C. $$f(x)=\sqrt{x \ + \ 2}$$    if $$x=1→f(1)=\sqrt{1 \ + \ 2}=\sqrt{3}≠5$$D. $$f(x)=\sqrt{x} \ + \ 4$$   if $$x=1→f(1)=\sqrt{1} \ + \ 4=5$$ 35- Choice D is correct The correct answer is $$810$$ Let $$x$$ be all expenses, then $$\frac{22}{100} \ x=660→$$$$x=\frac{100 \ × \ 660}{22}=3000$$He spent for his rent: $$\frac{27}{100} \ × \ 3000=810$$ 36- Choice C is correct The correct answer is $$\frac{100 \ x \ + \ 800}{x}$$ The amount of money for $$x$$ bookshelf is: $$100 \ x$$Then, the total cost of all bookshelves is equal to: $$100 \ x \ + \ 800$$The total cost, in dollar, per bookshelf is:$$\frac{Total \ cost}{number \ of \ items}=\frac{100 \ x \ + \ 800}{x}$$ 37- Choice C is correct The correct answer is $$0$$ $$\sqrt{x}=4→x=16$$then; $$\sqrt{x} \ - \ 7=\sqrt{16} \ - \ 7=4 \ - \ 7=- \ 3$$ and $$\sqrt{x \ - \ 7}=\sqrt{16 \ - \ 7}=\sqrt{9}=3$$Then: $$(\sqrt{x \ - \ 7}) \ + \ (\sqrt{x \ - \ 7})=3 \ + \ (-\ 3)=0$$ 38- Choice B is correct The correct answer is $$25$$ The angles on a straight line add up to $$180$$ degrees. Then:$$x \ + \ 25 \ + \ y \ + \ 2 \ x \ + \ y=180$$Then, $$3 \ x \ + \ 2 \ y=180 \ - \ 25→$$$$3 \ (35) \ + \ 2y=155→$$$$2 \ y=155 \ - \ 105=50→$$$$y=25$$ 39- Choice C is correct The correct answer is $$37$$ Square root of $$16$$ is $$\sqrt{16}=4\ < \ 6$$Square root of $$25$$ is $$\sqrt{25}=5 \ < \ 6$$Square root of $$37$$ is $$\sqrt{37}=\sqrt{36 \ + \ 1} \ >\ \sqrt{36}=6$$Square root of $$49$$ is $$\sqrt{49}=7 \ > \ 6$$Since, $$\sqrt{37} \ < \ \sqrt{49}$$, then the answer is C. 40- Choice A is correct The correct answer is $$11$$ $$|- \ 12 \ -\ 5| \ - \ |- \ 8 \ + \ 2|=|- \ 17| \ - \ |- \ 6|=17 \ - \ 6=11$$

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