How to Solve Integers and Absolute Value Problems
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An integer is a whole number that can be positive, negative, or zero. Absolute value measures distance from zero on the number line, so it is never negative.
For any number \(a\), \(|a|\) means the distance between \(a\) and \(0\). For example, \(|-6|=6\) and \(|6|=6\) because both numbers are 6 units from zero.
When an expression contains absolute value bars, simplify what is inside the bars first. Then take the absolute value. After that, follow the usual order of operations.
Example 1
Evaluate \(|-8| + 3\). The absolute value is \(|-8|=8\). Then \(8 + 3 = 11\).
Example 2
Evaluate \(2|5 - 12| - 4\). First simplify inside the bars: \(5 - 12 = -7\). Then \(|-7|=7\). Multiply: \(2 \times 7=14\). Subtract: \(14 - 4 = 10\).
Integers and Absolute Value
Think of this lesson as more than a rule to memorize. Integers and Absolute Value is about number-line meaning, signs, and distance from zero. A strong student does not rush to the first formula on the page; they pause, identify the structure of the problem, and then choose the tool that matches that structure. That pause is what prevents most mistakes.
Integers are easiest when you picture direction on a number line. Positive numbers move right, negative numbers move left, and absolute value measures distance from zero.
Here is the teacher way to approach the topic. First, read the problem slowly and underline the information that is actually given. Next, name the target: are you finding a value, simplifying an expression, comparing two quantities, solving for a variable, or interpreting a graph? Once the target is clear, the calculation becomes much less mysterious because every step has a job.
- Read what is given and what is being asked.
- Choose the rule that connects them.
- Substitute carefully and simplify in small steps.
- Check the final answer against the original question.
A helpful habit is to say what each number represents before using it. For example, if a number is a denominator, a radius, a slope, a common difference, or a coefficient, it should not be treated like an ordinary loose number. Its role tells you where it belongs in the formula. This is especially important on ACT-style questions because many wrong answer choices come from using the right numbers in the wrong places.
Another good habit is to keep the work organized vertically. Write one clean line for substitution, one line for simplifying, and one line for the final answer. If the problem has units, keep the units attached. If the problem has signs, exponents, or parentheses, copy them carefully from one line to the next. Most errors in this topic are not caused by a hard idea; they are caused by dropping a negative sign, combining unlike terms, using the wrong denominator, or skipping a check.
When you finish, ask a quick reasonableness question. Should the answer be positive or negative? Should it be larger or smaller than the original number? Does it fit the graph, table, shape, or equation? Can you plug it back into the original problem? This final check turns the lesson from a procedure into understanding.
On a test, the goal is not to write the longest solution. The goal is to write enough clear work that you can see the structure, avoid traps, and recover quickly if one line goes wrong. Practice the examples below with that mindset: identify the type of problem, choose the matching rule, show the substitution, simplify carefully, and check the answer before moving on.
Free printable Worksheets
Exercises for Integers and Absolute Value
1) \(|-7| =\)
2) \(|12| =\)
3) \(-|9| =\)
4) \(|-4| + 6 =\)
5) \(15 - |-8| =\)
6) \(|-3| + |-10| =\)
7) \(|5 - 13| =\)
8) \(|-6| - |-11| =\)
9) \(-14 + |-5| =\)
10) \(|-9 + 2| =\)
11) \(3|-4| - 7 =\)
12) \(|-18| \div 3 + |-2| =\)
13) \(|6 - 15| + |4 - 10| =\)
14) \(20 - 2|-7| =\)
15) \(|-5|^2 - |12 - 20| =\)
16) \(4|3 - 9| - |-16| =\)
17) \(||-14| - 20| =\)
18) \(|-3|\,|-8| - |7 - 19| =\)
19) \(30 \div |-6| + |2^3 - 15| =\)
20) \(|-4(6 - 11)| - 3|-5 + 1| =\)
1) \(|-7|\) is the distance from \(-7\) to \(0\). That distance is \(\color{red}{7}\).
2) \(|12|\) is the distance from \(12\) to \(0\). That distance is \(\color{red}{12}\).
3) \(-|9|\). First find \(|9|=9\). The negative sign is outside the absolute value, so the result is \(\color{red}{-9}\).
4) \(|-4| + 6\). Absolute value first: \(|-4|=4\). Then add: \(4 + 6 = \color{red}{10}\).
5) \(15 - |-8|\). Absolute value first: \(|-8|=8\). Then subtract: \(15 - 8 = \color{red}{7}\).
6) \(|-3| + |-10|\). Absolute values: \(|-3|=3\) and \(|-10|=10\). Add: \(3 + 10 = \color{red}{13}\).
7) \(|5 - 13|\). Inside absolute value first: \(5 - 13 = -8\). Then \(|-8| = \color{red}{8}\).
8) \(|-6| - |-11|\). Absolute values: \(|-6|=6\) and \(|-11|=11\). Subtract: \(6 - 11 = \color{red}{-5}\).
9) \(-14 + |-5|\). Absolute value first: \(|-5|=5\). Then add: \(-14 + 5 = \color{red}{-9}\).
10) \(|-9 + 2|\). Inside absolute value: \(-9 + 2 = -7\). Then \(|-7| = \color{red}{7}\).
11) \(3|-4| - 7\). Absolute value: \(|-4|=4\). Multiply: \(3 \times 4 = 12\). Subtract: \(12 - 7 = \color{red}{5}\).
12) \(|-18| \div 3 + |-2|\). Absolute values: \(|-18|=18\) and \(|-2|=2\). Divide: \(18 \div 3 = 6\). Add: \(6 + 2 = \color{red}{8}\).
13) \(|6 - 15| + |4 - 10|\). Inside bars: \(6 - 15=-9\) and \(4 - 10=-6\). Absolute values: \(9\) and \(6\). Add: \(9 + 6 = \color{red}{15}\).
14) \(20 - 2|-7|\). Absolute value: \(|-7|=7\). Multiply: \(2 \times 7 = 14\). Subtract: \(20 - 14 = \color{red}{6}\).
15) \(|-5|^2 - |12 - 20|\). Absolute values: \(|-5|=5\) and \(|12-20|=|-8|=8\). Square: \(5^2=25\). Subtract: \(25 - 8 = \color{red}{17}\).
16) \(4|3 - 9| - |-16|\). Inside bars: \(3 - 9 = -6\). Absolute values: \(|-6|=6\) and \(|-16|=16\). Multiply: \(4 \times 6 = 24\). Subtract: \(24 - 16 = \color{red}{8}\).
17) \(||-14| - 20|\). Inner absolute value: \(|-14|=14\). Then inside the outer bars: \(14 - 20 = -6\). Outer absolute value: \(|-6|=\color{red}{6}\).
18) \(|-3|\,|-8| - |7 - 19|\). Absolute values: \(|-3|=3\), \(|-8|=8\), and \(|7-19|=|-12|=12\). Multiply: \(3 \times 8 = 24\). Subtract: \(24 - 12 = \color{red}{12}\).
19) \(30 \div |-6| + |2^3 - 15|\). Absolute value: \(|-6|=6\). Exponent: \(2^3=8\). Second bars: \(|8 - 15|=|-7|=7\). Divide: \(30 \div 6=5\). Add: \(5 + 7 = \color{red}{12}\).
20) \(|-4(6 - 11)| - 3|-5 + 1|\). Parentheses: \(6 - 11=-5\), so \(-4(-5)=20\) and \(|20|=20\). Second bars: \(-5+1=-4\), so \(|-4|=4\). Multiply: \(3 \times 4=12\). Subtract: \(20 - 12 = \color{red}{8}\).
Integers and Absolute Value Practice Quiz
