How to Add and Subtract Complex Numbers
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Complex Numbers
A complex number is \(a+bi\), where \(a\) is the real part, \(b\) is the imaginary coefficient, and \(i^2=-1\).
Adding and Subtracting
Combine real parts with real parts and imaginary parts with imaginary parts: \((a+bi)+(c+di)=(a+c)+(b+d)i\).
Subtraction Reminder
Distribute the minus sign to both parts of the complex number being subtracted.
Adding and Subtracting Complex Numbers
Think of this lesson as more than a rule to memorize. Adding and Subtracting Complex Numbers is about real and imaginary parts working together. A strong student does not rush to the first formula on the page; they pause, identify the structure of the problem, and then choose the tool that matches that structure. That pause is what prevents most mistakes.
Complex numbers use \(i^2=-1\). Treat \(a+bi\) like a two-part number: the real part \(a\) and the imaginary part \(b\).
Here is the teacher way to approach the topic. First, read the problem slowly and underline the information that is actually given. Next, name the target: are you finding a value, simplifying an expression, comparing two quantities, solving for a variable, or interpreting a graph? Once the target is clear, the calculation becomes much less mysterious because every step has a job.
- Read what is given and what is being asked.
- Choose the rule that connects them.
- Substitute carefully and simplify in small steps.
- Check the final answer against the original question.
A helpful habit is to say what each number represents before using it. For example, if a number is a denominator, a radius, a slope, a common difference, or a coefficient, it should not be treated like an ordinary loose number. Its role tells you where it belongs in the formula. This is especially important on ACT-style questions because many wrong answer choices come from using the right numbers in the wrong places.
Another good habit is to keep the work organized vertically. Write one clean line for substitution, one line for simplifying, and one line for the final answer. If the problem has units, keep the units attached. If the problem has signs, exponents, or parentheses, copy them carefully from one line to the next. Most errors in this topic are not caused by a hard idea; they are caused by dropping a negative sign, combining unlike terms, using the wrong denominator, or skipping a check.
When you finish, ask a quick reasonableness question. Should the answer be positive or negative? Should it be larger or smaller than the original number? Does it fit the graph, table, shape, or equation? Can you plug it back into the original problem? This final check turns the lesson from a procedure into understanding.
On a test, the goal is not to write the longest solution. The goal is to write enough clear work that you can see the structure, avoid traps, and recover quickly if one line goes wrong. Practice the examples below with that mindset: identify the type of problem, choose the matching rule, show the substitution, simplify carefully, and check the answer before moving on.
Free printable Worksheets
Exercises for Adding and Subtracting Complex Numbers
1) \(Simplify (3+2i)+(4+5i).\)
2) \(Simplify (8-3i)+(2+i).\)
3) \(Simplify (5+9i)-(2+4i).\)
4) \(Simplify (7-6i)-(1-2i).\)
5) \(Simplify (-3+4i)+(9-10i).\)
6) \(Simplify (-5-2i)-(3+6i).\)
7) \(Simplify (4+7i)+(-9+2i).\)
8) \(Simplify (6-11i)-(8-3i).\)
9) \(Simplify (2+i)+(3-4i)+(-7+6i).\)
10) \(Simplify (10-5i)-(-4+8i).\)
11) \(Simplify -2(3-5i)+(4+i).\)
12) \(Simplify 3(2+i)-2(1-4i).\)
13) \(Simplify (5-2i)+(-1+7i).\)
14) \(Simplify (5-2i)-(-1+7i).\)
15) \(Simplify (x+3)+(y-2)i=7+5i.\)
16) \(Simplify (12+3i)-[(5-2i)+(-1+6i)].\)
17) \(Simplify (2a+bi)+(a-3bi),\ a=-2,\ b=4.\)
18) \(Simplify \text{what added to }4-9i\text{ gives }-3+2i.\)
19) \(Simplify (3+2i)-(4-5i)+(1-7i).\)
20) \(Simplify (x-2)+(3y+1)i=(4x+1)+(y-5)i.\)
1)\(Simplify (3+2i)+(4+5i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: add real parts and imaginary parts.
Answer: \(7+7i\)
2)\(Simplify (8-3i)+(2+i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: 8+2=10 and -3+1=-2.
Answer: \(10-2i\)
3)\(Simplify (5+9i)-(2+4i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: subtract matching parts.
Answer: \(3+5i\)
4)\(Simplify (7-6i)-(1-2i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: distribute the minus sign.
Answer: \(6-4i\)
5)\(Simplify (-3+4i)+(9-10i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: combine like terms.
Answer: \(6-6i\)
6)\(Simplify (-5-2i)-(3+6i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: subtract both the real and imaginary parts.
Answer: \(-8-8i\)
7)\(Simplify (4+7i)+(-9+2i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: 4-9=-5 and 7+2=9.
Answer: \(-5+9i\)
8)\(Simplify (6-11i)-(8-3i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: 6-8=-2 and -11-(-3)=-8.
Answer: \(-2-8i\)
9)\(Simplify (2+i)+(3-4i)+(-7+6i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: add all real parts and all imaginary parts.
Answer: \(-2+3i\)
10)\(Simplify (10-5i)-(-4+8i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: subtracting a negative real adds 4.
Answer: \(14-13i\)
11)\(Simplify -2(3-5i)+(4+i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: distribute first, then combine.
Answer: \(-2+11i\)
12)\(Simplify 3(2+i)-2(1-4i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: distribute both coefficients.
Answer: \(4+11i\)
13)\(Simplify (5-2i)+(-1+7i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: this is z+w.
Answer: \(4+5i\)
14)\(Simplify (5-2i)-(-1+7i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: this is z-w.
Answer: \(6-9i\)
15)\(Simplify (x+3)+(y-2)i=7+5i.\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: match real parts and imaginary coefficients.
Answer: \(x=4,\ y=7\)
16)\(Simplify (12+3i)-[(5-2i)+(-1+6i)].\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: simplify the bracket first.
Answer: \(8-i\)
17)\(Simplify (2a+bi)+(a-3bi),\ a=-2,\ b=4.\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: combine to 3a-2bi, then substitute.
Answer: \(-6-8i\)
18)\(Simplify \text{what added to }4-9i\text{ gives }-3+2i.\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: subtract the starting value from the target.
Answer: \(-7+11i\)
19)\(Simplify (3+2i)-(4-5i)+(1-7i).\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: all real and imaginary terms cancel.
Answer: \(0\)
20)\(Simplify (x-2)+(3y+1)i=(4x+1)+(y-5)i.\)
Step 1: Treat the real and imaginary parts as like terms.
Step 2: solve x-2=4x+1 and 3y+1=y-5.
Answer: \(x+y=-4\)
Adding and Subtracting Complex Numbers Practice Quiz