How to Solve Powers of Products and Quotients
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Discovering a Product’s Power
In order to simplify a product’s power in 22 exponential expressions, one can utilize the power of a product rule of exponents. This separates the power of a product of factors into the product of the powers of the factors. For example, look at (pq)3(pq)3. You start via utilizing the associative and commutative properties of multiplication for regrouping the factors.
(pq)3 = (pq) × (pq) × (pq) = p × p × p × q × q × q = p3 × q3(pq)3 = (pq) × (pq) × (pq) = p × p × p × q × q × q = p3 × q3
So, (pq)3 = p3 × q3(pq)3 = p3 × q3
THE POWER OF A PRODUCT RULE OF EXPONENTS
With any actual numbers aa as well as bb and any integer nn, the power of a product rule of exponents says:
(ab)n = an × bn(ab)n = an × bn
Discovering a Quotient’s Power
In order to simplify the power of a quotient with 22 expressions, one can utilize the power of a quotient rule. It says the power of a quotient of factors equals the quotient of the powers of the factors. For instance, here is an example:
(e−2 × f2)7 = f14e14(e−2 × f2)7 = f14e14
Now redo the original problem in a different way and see the outcome.
(e−2 × f2)7 = (f2e2 )7 = f14e14(e−2 × f2)7 = (f2e2 )7 = f14e14
Based on the last 22 steps, it seems one can utilize the power of a product rule for a power of a quotient rule.
(e−2 × f2)7 = (f2e2 )7 = (f2)7(e2)7 = f2×7e2×7 = f14e14(e−2 × f2)7 = (f2e2 )7 = (f2)7(e2)7 = f2×7e2×7 = f14e14
THE POWER OF A QUOTIENT RULE OF EXPONENTS
With any true numbers aa and bb and any integer nn, the power of a quotient rule of exponents says that: (ab )n = anbn(ab )n = anbn
Free printable Worksheets
Exercises for Powers of Products and Quotients
1) (−3x2x2)3=(−3x2x2)3=
2) (4x2x2)3=(4x2x2)3=
3) (−9x3y)2=(−9x3y)2=
4) (6x2)3=(6x2)3=
5) (−9x2)3=(−9x2)3=
6) (−2x4y)2=(−2x4y)2=
7) (−x3y)2=(−x3y)2=
8) (−8x2)3=(−8x2)3=
9) (6x4y)3=(6x4y)3=
10) (−x3)2=(−x3)2=
1) (−3x2x2)3=(−3x2x2)3= (−33)x(2×3)x(2×3) =−27x12
2) (4x2x2)3= (43)x(2×3)x(2×3) =64x12
3) (−9x3y)2= (−92)x(3×2)y2 =81x6y2
4) (6x2)3= (63)x(2×3) =216x6
5) (−9x2)3= (−93)x(2×3) =−729x6
6) (−2x4y)2= (−22)x(4×2)y2 =4x8y2
7) (−x3y)2= (−12)x(3×2)y2 =x6y2
8) (−8x2)3= (−83)x(2×3) =−512x6
9) (6x4y)3= (63)x(4×3)y3 =216x12y3
10) (−x3)2= (−12)x(3×2) =x6
Powers of Products and Quotients Quiz