Free Full Length ISEE Upper Level Mathematics Practice Test

Full Length ISEE Upper Level Mathematics Practice Test

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ISEE UPPER LEVEL
Mathematics Practice Test 4

  • 47 questions
  • Total time for this section: 40 Minutes
  • Calculators are not allowed at the test.
1- Ella (E) is \(6\) years older than her friend Ava (A) who is \(4\) years younger than her sister Sofia (S). If E, A and S denote their ages, which one of the following represents the given information?
(A) \(\begin{cases}E = 6 \ - \ A\\A = S \ +  \ 4\end{cases}\)
(B) \(\begin{cases}E = 4 \ - \ A\\A = S \ -  \ 2\end{cases}\)
(C) \(\begin{cases}A = 4 \ - \ E\\S = A \ -  \ 2\end{cases}\)
(D) \(\begin{cases}E = 6 \ + \ A\\A = S \ –  \ 4\end{cases}\)
2- An angle is equal to one fourth of its supplement. What is the measure of that angle?
(A) \(36^\circ\)
(B) \(30^\circ\)
(C) \(25^\circ\)
(D) \(39^\circ\)
3- \(3\) less than twice a positive integer is \(91\). What is the integer?
(A) \(44\)
(B) \(45\)
(C) \(47\)
(D) \(49\)
4- The cost, in thousands of dollars, of producing \(x\) thousands of textbooks is:
\(C(x)=x^2 \ - \ 4 \ x\).
The revenue, also in thousands of dollars, is \(R(x)=30 \ x\).
find the profit or loss if \(30\) textbooks are produced. (profit \(=\) revenue \(–\) cost)
(A) \($120\) profit
(B) \($240\) profit
(C) \($130\) loss
(D) \($180\) loss
5- \(\frac{1}{4 \ b^2} \ + \ \frac{1}{4 \ b} = \frac{1}{b^2}\), then \(b =\)?
(A) \(3\)
(B) \(\frac{2}{7}\)
(C) \(- \ \frac{15}{17}\)
(D) \(- \ 3\)
6- Simplify \(4 \ x^2 \ y^3 \ (3 \ x^2 \ y)^3=\) 
(A) \( 100 \ x^6 \ y^6\)
(B) \( 108 \ x^8 \ y^6\)
(C) \( 54 \ x^5 \ y^3\)
(D) \(68 \ x^8 \ y^2\)
7- \(\frac{|6 \ + \ x|}{2} \ ≤ \ 8\), then \(x =\)?
(A) \(– \ 28 \ ≤ \ x \ ≤ \ 12\)
(B) \(– \ 22 \ ≤ \ x \ ≤ \ 10\)
(C) \(– \ 24 \ ≤ \ x \ ≤ \ 15\)
(D) \(– \ 18\ ≤ \ x \ ≤ \ 18\)
8- Which of the following points lies on the line \(2 \ x \ + \ 5 \ y=12\)?
(A) \((2, 1)\)
(B) \((– \ 1, 3)\)
(C) \((– \ 2, 2)\)
(D) \((2, 2)\)
9- \(1.3\) is what percent of \(13\)?
(A) \(4\)
(B) \(10\)
(C) \(5\)
(D) \(12\)
10- Write \(674\) in expanded form, using exponents.
(A) \((6 \ ×  \ 10^3)  \ +  \ (7  \ ×  \ 10^2)  \ + \  (4  \ ×  \ 10) \)
(B) \((6  \ × \  10^2)  \ +  \ (7  \ × \  10^1)  \ – \  4 \)
(C) \((6  \ × \  10^2)  \ +  \ (7 \  × \  10^1) \  + \  4\)
(D)  \((6  \ × \  10^1)  \ +  \ (7  \ × \  10^1)  \ + \  4\)
11- What is the area of an isosceles right triangle that has one leg that measures \(4\) cm?
(A) \(4\) cm\(^2\)
(B) \(8\) cm\(^2\)
(C) \(12\) cm\(^2\)
(D) \(16\) cm\(^2\)
12- Right triangle ABC has two legs of lengths \(5\) cm (AB) and \(12\) cm (AC). What is the length of the third side (BC)?
(A) \(12\) cm
(B) \(11\) cm
(C) \(13\) cm
(D) \(15\) cm
13- A circle has a diameter of \(12\) inches. What is its approximate circumference?
(A) \(44.24\)
(B) \(64.91\)
(C) \(34.28\)
(D) \(37.68\)
14- A company pays its writer \($5\) for every \(200\) words written. How much will a writer earn for an article with \(1,100\) words?
(A) \($22.5\)
(B) \($21.7\)
(C) \($27.5\)
(D) \($30.6\)
15- Which is the longest time?
(A) \(23\) hours
(B) \(1610\) minutes
(C) \(1\) days
(D) \(3,900\)
16- The equation of a line is given as : \(y = 6 \ , x \ – \ 2\). Which of the following points lie on the line?
17- \(85.23 \ ÷ \ 0.03 =\)?
(A) \(1,931\)
(B) \(2,969\)
(C) \(2,841\)
(D) \(2,691\)
18- The drivers at G & G trucking must report the mileage on their trucks each week. The mileage reading of Ed’s vehicle was \(42,687\) at the beginning of one week, and \(47,353\) at the end of the same week. What was the total number of miles driven by Ed that week?
(A) \(489\) Miles
(B) \(723\) Miles
(C) \(692\) Miles
(D) \(666\) Miles
19- A circular logo is enlarged to fit the lid of a jar. The new diameter is \(25\%\) larger than the original. By what percentage has the area of the logo increased?
(A) \(69\%\)
(B) \(54\%\)
(C) \(76\%\)
(D) \(39\%\)
20- What is the area of an isosceles right triangle that has one leg that measures \(8\) cm?
(A) \(32\) cm\(^2\)
(B) \(64\) cm\(^2\)
(C) \(53\) cm\(^2\)
(D) \(24\) cm\(^2\)
21- If \(x \ + \ y = 24\), what is the value of \(4 \ x \ + \ 4 \ y\)?
(A) \(76\)
(B) \(80\)
(C) \(100\)
(D) \(96\)
22- What’s the area of the non-shaded part of the following figure? 
ISEE Upper Level Mathematics
(A) \(104\)
(B) \(78\)
(C) \(120\)
(D) \(112\)
23- What’s the reciprocal of \(\frac{x^3}{16}\)?
(A) \(\frac{16}{x^3}\)
(B) \(\frac{16}{x^3} \ - \ 1\)
(C) \(\frac{x^3}{16} \ - \ 1\)
(D) \(\frac{x^3}{16} \ + \ 1\)
24- Given that \(x = 0.5\) and \(y = 3\), what is the value of \(2 \ x^2 \ (y \ + \ 8)\)?
(A) \(5.5\)
(B) \(7.2\)
(C) \(11.4\)
(D) \(8.9\)
25- Mario loaned Jett \($2,500\) at a yearly interest rate of \(4\%\). After two year what is the interest owned on this loan?
(A) \($245\)
(B) \($195\)
(C) \($185\)
(D) \($200\)
26- Which equation represents the statement Two plus the sum of the squares of \(w\) and \(x\) is \(25\).
(A) \( 2 \ (w^2 \ - \  x) = 25\)
(B) \( 2 \ (w^2 \ + \  x) = 25\)
(C) \( 25 \ (w^2 \ + \  x) = 2\)
(D) \( 2 \ (w \ + \  x) = 25\)
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27- \(29\) hr. \(21\) min
\(23\) hr. \(44\) min
_________________

(A) \(5\) hr. \(37\) min
(B) \(6\) hr. \(37\) min
(C) \(6\) hr. \(13\) min
(D) \(5\) hr. \(13\) min
28- A bread recipe calls for \(4 \ \frac{1}{2}\) cups of flour. If you only have \(5 \frac{4}{3}\) cups, how much more flour is needed?
(A) \( \frac{ 5}{4}\)
(B) \(- \ \frac{ 5}{4}\)
(C) \(- \ \frac{ 1}{2}\)
(D) \(1\)
29- Which of the following is a factor of both \(x^2 \ - \ 2 \ x \ -  \ 8\) and \(x^2 \ - \ 6 \ x \ + \ 8\)?
(A) \((x \ – \ 2)\)
(B) \((x \ + \ 2)\)
(C) \((x \ + \ 4)\)
(D) \((x \ - \ 4)\)
30- What is the solution of the following system of equations?
\(\begin{cases}- \ 2 \ x \ - \ 3 \ y =\ - \ 12\\4 \ x\ + \ y= 25\end{cases}\)
(A) \((4, 2)\)
(B) \((7, 2)\)
(C) \((6, 1)\)
(D) \((5, 3)\)
31- Ellis just got hired for on-the-road sales and will travel about \(1,200\) miles a week during an \(60-\)hour work week. If the time spent traveling is \(\frac{2}{3}\) of his week, how many hours a week will he be on the road?
(A) Ellis spends about \(48\) hours of his \(60-\)hour work week on the road.
(B) Ellis spends about \(40\) hours of his \(60-\)hour work week on the road.
(C) Ellis spends about \(44\) hours of his \(60-\)hour work week on the road.
(D) Ellis spends about \(42\) hours of his \(60-\)hour work week on the road.
32- \(\frac{12}{27}\) is equal to:
(A) \(0.444\)... 
(B) \(0.25\)
(C) \(0.40\)
(D) \(0.38\)
33- Find the perimeter of a rectangle with the dimensions \(49 \ × \ 28\).
(A) \(132\)
(B) \(281\)
(C) \(154\)
(D) \(164\)
34- In a school, the ratio of number of boys to girls is \(5:9\). If the number of boys is \(235\), what is the total number of students in the school?
(A) \(780\)
(B) \(658\)
(C) \(568\)
(D) \(865\)
35- A car uses \(12\) gallons of gas to travel \(240\) miles. How many miles per gallon does the car get?
(A) \(20\)
(B) \(12\)
(C) \(30\)
(D) \(25\)
36- How many square feet of tile is needed for a \(12\) foot \(x \ 12\) foot room?
(A) \(256\) square feet
(B) \(144\) square feet
(C) \(169\) square feet
(D) \(218\) square feet
37- If \(x\) is \(38\%\) percent of \(740\), what is \(x\)?
(A) \(270.5\)
(B) \(240.1\)
(C) \(281.2\)
(D) \(269.7\)
38- Karen is \(6\) years older than her sister Michelle, and Michelle is \(4\) years younger than her brother David. If the sum of their ages is \(67\), how old is Michelle?
(A) \(21\)
(B) \(19\)
(C) \(25\)
(D) \(17\)
39- A tree \(24\) feet tall casts a shadow \(8\) feet long. Jack is \(6\) feet tall. How long is Jack’s shadow?
(A) \(3\) ft.
(B) \(5\) ft.
(C) \(2\) ft.
(D) \(\frac{1}{2}\) ft.
40- Calculate the area of a parallelogram with a base of \(3\) feet and height of \(4.2\) feet.
(A) \(10.2\) square feet
(B) \(15.5\) square feet
(C) \(18.6\) square feet
(D) \(12.6\) square feet
41- What is the result of the expression?
\(\begin{bmatrix}2 & 6 \\- \ 1 & - \ 2\\- \ 5 & - \ 4 \end{bmatrix} \ + \ \begin{bmatrix}0 & - \ 6 \\1 & 0\\2 & 7 \end{bmatrix}=\)
(A) \(\ \begin{bmatrix}2 & 0\\0 & - \ 2\\- \ 3 & 3 \end{bmatrix}\)
(B) \(\ \begin{bmatrix}0 & 2\\0 & - \ 2\\3 & - \ 3 \end{bmatrix}\)
(C) \(\ \begin{bmatrix}1 & 3\\0 & - \ 3\\2 & - \ 2 \end{bmatrix}\)
(D) \(\ \begin{bmatrix}- \ 1 & 0\\2 & - \ 3\\2 & 0 \end{bmatrix}\)
42- If \(x∎y=\sqrt{x^2 \ + \ y}\), what is the value of \(7∎15\)?
(A) \(\sqrt{63}\)
(B) \(8\)
(C) \(6\)
(D) \(9\)
43- A shirt costing \($150\) is discounted \(15\%\). After a month, the shirt is discounted another \(15\%\). Which of the following expressions can be used to find the selling price of the shirt?
(A) \((150) \ (0.85)\)
(B) \((150) \ (0.85) \ - \ (0.70)\)
(C) \((150) \ (0.85) \ - \ (150) \ (0.70)\)
(D) \((150) \ (0.85) \ (0.70)\)
44- The average weight of \(21\) girls in a class is \(65\) kg and the average weight of \(30\) boys in the same class is \(72\) kg. What is the average weight of all the \(51\) students in that class?
(A) \(69.11\) kg
(B) \(73\) kg
(C) \(65.32\) kg
(D) \(70\) kg
45- There are three equal tanks of water. If \(\frac{3}{4}\) of a tank contains \(320\) liters of water, what is the capacity of the two tanks of water together?
(A) \(450\) Liters
(B) \(240\) Liters
(C) \(720\) Liters
(D) \(480\) Liters
46- \((2 \ x  \ + \ 6) \ (- \ x \ + \ 2) =\)
(A) \( 2 \ x^2 \ + \ 2 \ x \ - \ 12 \)
(B) \( x^2 \ + \ 4 \ x \ - \ 4 \)
(C) \(- \ 2 \ x^2 \ - \ 2 \ x \ + \ 12 \)
(D) \(- \ 2 \ x^2 \ + \ 2 \ x \ - \ 6\)
47- What is the area of the shaded region if the diameter of the bigger circle is \(18\) inches and the diameter of the smaller circle is \(8\) inches? 
ISEE Upper Level Mathematics1
(A) \( 49 \ π\)
(B) \( 81 \ π\)
(C) \( 72 \ π\)
(D) \( 65 \ π\)
1- Choice D is correct

The correct answer is:
\(E = 6 \ + \ A\)
\(A = S \ – \ 4\)

2- Choice A is correct

The correct answer is \(36^\circ\)
The sum of supplement angles is \(180\).
Let \(x \) be that angle.
Therefore, \(x \ + \ 4 \ x = 180\)
\(5 \ x = 180\), divide both sides by \(5: \ x = 36\)

3- Choice C is correct

The correct answer is \(47\)
Let \(x\) be the integer. Then:
\(2 \ x \ – \ 3 = 91\)
Add 5 both sides: \(2x = 94\)
Divide both sides by \(2: \ x = 47\)

4- Choice A is correct

The correct answer is \($120\) profit
Plug in the value of \(x=30\) into both equations. Then:
\(𝐢(x)=x^2 \ - \ 4 \ x=(30)^2 \ - 4 \ (30)=900 \ - \ 120=780\)
\(𝑅(x)=30 \ x=30 \ × \ 30=900\)
\(900 \ − \ 780=120\)

5- Choice A is correct

The correct answer is \(3\)
Subtract \(\frac{1}{4 \ b}\) and \(\frac{1}{𝑏^2}\) from both sides of the equation. Then:
\(\frac{1}{4 \ b^2} \ + \ \frac{1}{4 \ b} = \frac{1}{b^2}→\frac{1}{4 \ b^2} \ − \ \frac{1}{b^2}=− \ \frac{1}{4 \ 𝑏}\)
Multiply both numerator and denominator of the fraction \(\frac{1}{b^2}\) by \(4\). Then:
\(\frac{1}{4 \ b^2} \ − \ \frac{4}{4 \ b^2}=− \ \frac{1}{4 \ b}\)
Simplify the first side of the equation: \(− \ \frac{3}{4 \ b^2 }=− \ \frac{1}{4 \ b}\)
Use cross multiplication method: \(12 \ 𝑏=4 \ 𝑏^2→12=4 \ 𝑏→𝑏=3\)

6- Choice B is correct

The correct answer is \( 108 \ x^8 \ y^6\)
Simplify.
\(4 \ x^2 \ y^3 \ (3 \ x^2 \ y)^3=4 \ x^2 \ y^3 \ (27 \ x^6 \ y^3) = 108 \ x^8 \ y^6\)

7- Choice B is correct

The correct answer is \(– \ 22 \ ≤ \ x \ ≤ \ 10\)
First, multiply both sides of inequality by \(2\).
Then: \(\frac{|6 \ + \ x|}{2} \ ≤ \ 8→|6 \ +\ x| \ ≤ \ 16\)
Since \(6 \ + \ x\) can be positive or negative, then: \(6 \ + \ x \ ≤ \ 16\) or \(6 \ + \ x \ ≥ \ − \ 16\)
Then: \(x \ ≤ \ 10\) or \(x \ ≥ \ − \ 22\)

8- Choice D is correct

The correct answer is \((2, 2)\)
Plug in each pair of numbers in the equation.
The answer should be \(12\).
A. \((2, 1): \ \ \ 2 \ (2) \ + \ 5 \ (1) = 9\) No!
B. \((– \ 1, 3): \ \ \ 2 \ (–1) \ + \ 5 \ (2) = 8\) No!
C. \((– \ 2, 2): \ \ \ 2 \ (– \ 2) \ + \ 5 \ (2) = 6\) No!
D. \((2, 2): \ \ \ 2 \ (2) \ + \ 5 \ (2) = 12\) Yes!

9- Choice B is correct

The correct answer is \(10\)
\(x\% \ 13 = 1.3\)
\(\frac{x}{100} \ 13 = 1.3 →\)
\(x = \frac{1.3 \ × \ 100}{13} = 10\)

10- Choice C is correct

The correct answer is \((6 \ × \ 10^2) \ + \ (7 \ × \ 10^1) \ + \ 4  \)
Let’s review the choices provided:
A. \((6 \ × \ 10^3) \ + \ (7 \ × \ 10^2) \ + \ (4 \ × \ 10) = 6,000 \ + \ 700 \ + \ 40 = 6,740\)
B. \((6 \ × \ 10^2) \ + \ (7 \ × \ 10^1) \ – \ 4 = 600 \ + \ 70 \ – \ 4= 666\)
C. \((6 \ × \ 10^2) \ + \ (7 \ × \ 10^1) \ + \ 4 = 600 \ + \ 70 \ + \ 4 = 674\)
D. \((6 \ × \ 10^1) \ + \ (7 \ × \ 10^1) \ + \ 4 = 60 \ + \ 70 \ + \ 4 = 134\)
Only choice C equals to \(674\).

11- Choice A is correct

The correct answer is \(4\) cm\(^2\)
First draw an isosceles triangle.
Remember that two sides of the triangle are equal.
Let put \(a\) for the legs. Then:
\(π‘Ž=4⇒\) area of the triangle is \(=\frac{1}{2} \ (4 \ × \ 4)=\frac{16}{2}=4\) cm\(^2\)

12- Choice C is correct

The correct answer is \(13\) cm
Use Pythagorean Theorem: \(a^2 \ + \ b^2 = c^2\)
\(5^2 \ + \ 12^2 = c^2 ⇒\)
\(25 \ + \ 144 = c^2 ⇒\)
\(c^2 = 169 ⇒ c=13\)

13- Choice D is correct

The correct answer is \(37.68\)
\(C = 2 \ π \ r\)
\(C = 2 \ π \ × \ 6 = 12 \ π\)
\(π = 3.14 → C = 12 \ π = 37.68\)

14- Choice C is correct

The correct answer is \($27.5\)
\(\frac{5}{200} = \frac{x}{1,100}\)
\(x = \frac{5 \ × \ 1,100}{200} =27.5\)

15- Choice B is correct

The correct answer is \(1610\) minutes
\(23\) hours \(= 82,800\) seconds
\(1610\) minutes \(= 96,600\) seconds
\(1\) days \(= 24\) hours \(= 86,400\) seconds
\(3,900\) seconds

15- Choice B is correct

The correct answer is \(1610\) minutes
\(23\) hours \(= 82,800\) seconds
\(1610\) minutes \(= 96,600\) seconds
\(1\) days \(= 24\) hours \(= 86,400\) seconds
\(3,900\) seconds

17- Choice C is correct

The correct answer is \(2,841\)
\(85.23 \ ÷ \ 0.03 =2,841\)

18- Choice D is correct

The correct answer is \(666\) Miles
To find total number of miles driven by Ed that week, you only need to subtract \(46,687\) from \(47,353\).
\(47,353 \ − \ 46,687=666\)

19- Choice A is correct

The correct answer is \(69\%\)
Area of a circle equals: \( 𝐴=\pi \ r^2\)
The new diameter is \(30\%\) larger than the original then the new radius is also \(30\%\) larger than the original.
\(30\%\) larger than \(π‘Ÿ\) is \(1.3 \ r\).
Then, the area of larger circle is: \(𝐴=\pi \ r^2=\pi \ (1.3 \ π‘Ÿ)^2=\pi \ (1.69 \ π‘Ÿ^2)=1.69 \ πœ‹ \ r^2\)
\(1.69 \ \pi \ r^2\) is \(69\%\) bigger than \(\pi \ r^2\).

20- Choice A is correct

The correct answer is \(32\) cm\(^2\)
First draw an isosceles triangle.
Remember that two sides of the triangle are equal.
Let put \(π‘Ž \) for the legs. Then:
\(π‘Ž=5⇒\) area of the triangle is \(=\frac{1}{2} \ (8 \ × \ 8)=\frac{64}{2}=32\) cm\(^2\)

21- Choice D is correct

The correct answer is \(96\)
\(x \ + \ y = 24\)
Then: \(4 \ x \ + \ 4 \ y = 24 \ × \ 4 = 96\)

22- Choice A is correct

The correct answer is \(104\)
The area of the non-shaded region is equal to the area of the bigger rectangle subtracted by the area of smaller rectangle.
Area of the bigger rectangle \(= 12 \ × \ 10 = 120\)
Area of the smaller rectangle \(= 8 \ × \ 2 = 16\)
Area of the non-shaded region \(= 120 \ – \ 16 = 104\)

23- Choice A is correct

The correct answer is \(\frac{16}{x^3}\)
\(\frac{x^3}{16} ⇒\) reciprocal is : \(\frac{16}{x^3}\)

24- Choice A is correct

The correct answer is \(5.5\)
\(2 \ x^2 \ (y \ + \ 8) = 2 \ (0.5)^2 \ (3 \ + \ 8) = 2 \ (0.25) \ (11) = 5.5\)

25- Choice D is correct

The correct answer is \($200\)
Use interest rate formula:
Interet \(=\) principal \(×\) rate \(×\) time \(=2,500 \ × \ 0.04 \ × \ 2=200\)

26- Choice B is correct

The correct answer is \( 2 \ (w^2 \ + \  x) = 25\)

27- Choice A is correct

The correct answer is \(5\) hr. \(37\) min
\(29\) hr. \(21\) min
\(23\) hr. \(44\) min
_________________
\(5\) hr. \(37\) min

28- Choice B is correct

The correct answer is \(- \ \frac{ 5}{4}\)
\(4 \ \frac{1}{2} - 5 \frac{3}{4}=\)
\(4 \ \frac{2}{4} \ - \ 5 \frac{3}{4} =\)
\(\frac{18}{4} \ - \ \frac{23}{4} =\)
\(\frac{- \ 5}{4} =- \ \frac{ 5}{4}\)

29- Choice D is correct

The correct answer is \((x \ – \ 4)\)
Factor each trinomial \(x^2 \ – \ 2 \ x \ – 8\) and \(x^2 \ – \ 6 \ x \ + \ 8\)
\(x^2 \ – \ 2 \ x \ – 8 ⇒ (x \ – \ 4) \ (x \ + \ 2)\)
\(x^2 \ – \ 6 \ x \ + \ 8 ⇒ (x \ – \ 2) \ (x \ – \ 4)\)

30- Choice C is correct

The correct answer is \((6, 1)\)
\(\begin{cases}- \ 2 \ x \ - \ 3 \ y =\ - \ 15\\4 \ x\ + \ y= 25\end{cases}⇒\) Multiplication \((3)\) in first equation
\(⇒\begin{cases}- \ 2 \ x \ - \ 3 \ y =\ - \ 15\\12 \ x\ + \ 3 y= 75\end{cases}\)
Add two equations together \(⇒ 10 \ x =60 ⇒ x=6\) then; \(y=1\)

31- Choice B is correct

The correct answer is Ellis spends about \(40\) hours of his \(60-\)hour work week on the road.
Ellis travels \(\frac{2}{3}\) of \(60\) hours. \(\frac{2}{3} \ × \ 60=40\)
Ellis will be on the road for \(40\) hours.

32- Choice A is correct

The correct answer is \(0.444\)... 
\(\frac{12}{27} =0.444\)... 

33- Choice C is correct

The correct answer is \(154\)
Perimeter of a rectangle \(=2\) (width \(+\) length) \(=2 \ (49 \ + \ 28)=154\)

34- Choice B is correct

The correct answer is \(658\)
The ratio of boys to girls is \(5:9\).
Therefore, there are \(5\) boys out of \(14\) students.
To find the answer, first divide the number of boys by \(5\), then multiply the result by \(14\).
\(235 \ ÷ \ 5 = 47 ⇒ 47 \ × \ 10 = 658\)

35- Choice A is correct

The correct answer is \(20\)
\(\frac{240}{12} = 20\)

36- Choice B is correct

The correct answer is \(144\) square feet
The area of a \(12\) feet \(x \ 12\) feet room is \(144\) square feet.
\(12 \ × \ 12 = 144\)

37- Choice C is correct

The correct answer is \(281.2\)
\(\frac{38}{100} \ × \ 740 =x\)
\(x=281.2\)

38- Choice B is correct

The correct answer is \(19\)
Michelle \(=\) Karen \(– \ 6\)
Michelle \(=\) David \(– \ 4\)
Karen \(+\) Michelle \(+\) David \(= 67\)
Karen \(+ \ 6 =\) Michelle \(⇒\) Karen \(=\) Michelle \(– \ 6\)
Karen \(+\) Michelle \(+\) David \(= 67\)
Now, replace the ages of Karen and David by Michelle. Then:
Michelle \(+ \ 6 \ +\) Michelle \(+\) Michelle \(+ \ 4 =67\)
\(3\) Michelle \(+ \ 10 = 67 ⇒ 3\) Michelle \(= 67 \ – \ 10\)
\(3\) Michelle \(= 57\)
Michelle \(= 19\)

39- Choice C is correct

The correct answer is \(2\) ft.
Write a proportion and solve for the missing number.
\(\frac{24}{8} =\frac{ 6}{x}→ 24 \ x=6 \ × \ 8=48\)
\(24 \ x=48→x=\frac{48}{24}=2\)

40- Choice D is correct

The correct answer is \(12.6\) square feet
\(A = b \ h\)
\(A = 3 \ × \ 4.2 = 12.6\)

41- Choice A is correct

The correct answer is \(\ \begin{bmatrix}2 & 0\\0 & - \ 2\\- \ 3 & 3 \end{bmatrix}\)
\(\begin{bmatrix}2 & 6 \\- \ 1 & - \ 2\\- \ 5 & - \ 4 \end{bmatrix} \ + \ \begin{bmatrix}0 & - \ 6 \\1 & 0\\2 & 7 \end{bmatrix} = \ \begin{bmatrix}2 & 0\\0 & - \ 2\\- \ 3 & 3 \end{bmatrix}\)

42- Choice B is correct

The correct answer is \(8\)
\(7∎13=\sqrt{7^2 \ + \ 15}=\sqrt{49 \ + \ 15} =\sqrt{64} = 8\)

43- Choice D is correct

The correct answer is \((150) \ (0.85) \ (0.70)\)
To find the discount, multiply the number by \((100\% \ –\) rate of discount).
Therefore, for the first discount we get: \((150) \ (100\% \ – \ 15\%) = (150) \ (0.85)\)
For the next \(15\%\) discount: \((150) \ (0.85) \ (0.70)\)

44- Choice A is correct

The correct answer is \(69.11\) kg
Average \(=\frac{ sum \ of \ terms}{ number \ of \ terms}\)
The sum of the weight of all girls is: \(21 \ × \ 65 = 1,365\) kg
The sum of the weight of all boys is: \(30 \ × \ 72 = 2,160\) kg
The sum of the weight of all students is: \(1,365 \ + \ 2,160 = 3,525\) kg
Average \(= \frac{3,525 }{51} = 69.11\)

45- Choice D is correct

The correct answer is \(480\) Liters
Let \(x \) be the capacity of one tank. Then, \(\frac{3}{4} \ x=320→x=320 \ × \ \frac{3}{4}=240\) Liters
The amount of water in two tanks is equal to: \(2 \ × \ 240=480\) Liters

46- Choice C is correct

The correct answer is \(- \ 2 \ x^2 \ - \ 2 \ x \ + \ 12 \)
Use FOIL (First, Out, In, Last)
\((2 \ x \ + \ 6) \ (- \ x \ + \ 2) = - \ 2 \ x^2 \ + 4 \ x \ - \ 6 \ x \ + \ 12 =- \ 2 \ x^2 \ - \ 2 \ x \ + \ 12 \)

47- Choice D is correct

The correct answer is \( 65 \ π\)
To find the area of the shaded region subtract smaller circle from bigger circle.
\(S_{bigger} \ – \ S_{smaller} = π \ (r_{bigger} )^2 \ – \ π \ (r_{smaller} )^2 ⇒ S_{bigger} \ – \ S_{smaller }= π \ (9)^2 \ – \ π \ (4)^2\)
\(⇒ 81 \ π \ – \ 16 \ π = 65 \ π\)

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