What are the Properties of Logarithms
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Logarithmic properties
In math, logarithm problems are solved using the properties of the functions that make up logarithms. In basic math, we learned a lot of properties, like commutative, associative, and distributive, that can be used in algebra. When it comes to logarithmic functions, there are five main things to know:
- Quotient Property
- Power rule
- Change of Base Rule
- Reciprocal rule
- Product Property
Product Property
Let b, m, n be positive integers and b ≠ 1, logb (mn ) = logb m + logb n.
So, the log of the product of two numbers m and n with base b is the same as adding the log of m and n with the same base b.
Example:
log2 (32×16 ) = log2 32 + log2 16 = log2 25 + log2 24 = 5log2 2 + 4log2 2 = 5 + 4 = 9
Quotient Property
Let b, m, n be positive integers and b ≠ 1, logb (mn) = logb m − logb n.
The difference between log m and log n with the same base b is equal to the logarithm of a quotient of m and n.
Example:
log3 (81729) = log3 81 − log3 729 = log3 34 − log3 36 = 4log3 3 − 6log3 3 = 4 − 6 = −2
Power Rule
Let b, m, n be positive integers and b ≠ 1, logb mn = nlogb m.
The above property says that the logarithm of a positive number m to the power of n is equal to the product of n and the log of m.
Example:
The most important properties of logarithms are the above three. Here are some other properties and examples of how to use them.
Change of Base Rule
Let a, b, m be positive integers and a ≠ 1, b ≠ 1, loga m = logb mlogb a.
Example:
log5 25 = log2 25log2 5
Reciprocal Rule
Let m, n be positive integers and m ≠ 1, n ≠ 1, logn m = 1logm n.
Example:
log3 12 = 1log12 3
Summary:
- alogab=b
- loga1=0
- logaa=1
- loga(x.y)=logax+logay
- logaxy=logax−logay
- loga1x=−logax
- logaxp=plogax
- logxkx=1xlogax, for k≠0
- logax=logacxc
- logax=1logxa
Free printable Worksheets
Exercises for Properties of Logarithms
1) Expand this logarithm: loga (x×y×z)
2) Expand this logarithm: log6 (25×32×7)
3) Expand this logarithm: logb x6×y4z3
4) Expand this logarithm: log7 35z6×y
5) Expand this logarithm: loga 132
6) Reduce this phrase to a single logarithm: logb q + logb p
7) Reduce this phrase to a single logarithm: 4 log5 3 − 6 log5 7
8) Reduce this phrase to a single logarithm: 4 logc a + 3 logc b
9) Reduce this phrase to a single logarithm: 5 loga x − 7 loga y
10) Reduce this phrase to a single logarithm: 7 logb q + 3 logb p
1) Expand this logarithm: loga (x×y×z)
loga (x×y×z) = loga x + loga y + loga z
2) Expand this logarithm: log6 (25×32×7)
log6 (25×32×7) = 5 log6 2 + 2 log6 3 + log6 7
3) Expand this logarithm: logb x6×y4z3
logb x6×y4z3 = 6 logb x + 4 loga y − 3 loga z
4) Expand this logarithm: log7 35z6×y
log7 35z6×y = 5 log7 3 − 6 log7 z − log7 y
5) Expand this logarithm: loga 132
loga 132 = −loga 32 = −2loga 3
6) Reduce this phrase to a single logarithm: logb q + logb p
logb q + logb p = logb (q×p)
7) Reduce this phrase to a single logarithm: 4 log5 3 − 6 log5 7
4 log5 3 − 6 log5 7 = log5 3476
8) Reduce this phrase to a single logarithm: 4 logc a + 3 logc b
4 logc a + 3 logc b = logc (a4×b3)
9) Reduce this phrase to a single logarithm: 5 loga x − 7 loga y
5 loga x − 7 loga y = loga x5y7
10) Reduce this phrase to a single logarithm: 7 logb q + 3 logb p
7 logb q + 3 logb p = logb (q7×p3)
Properties of Logarithms Practice Quiz