How to Solve Quadratic Equations
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Solving Quadratic Equations
A quadratic equation is usually written \(ax^2+bx+c=0\). Solving means finding every value of \(x\) that makes the equation true.
Choosing a Method
Use square roots for \((x-h)^2=k\), factoring when the trinomial is friendly, and \(x=\frac{-b\pm\\sqrt{b^2-4ac}}{2a}\) when factoring is not quick.
Checking
Every solution should satisfy the original equation. In word problems, reject values that do not make sense in context.
Solving Quadratic Equations
Think of this lesson as more than a rule to memorize. Solving Quadratic Equations is about parabolas, roots, factoring, and graph behavior. A strong student does not rush to the first formula on the page; they pause, identify the structure of the problem, and then choose the tool that matches that structure. That pause is what prevents most mistakes.
A quadratic usually has the form \(ax^2+bx+c\). Factoring, graphing, square roots, and the quadratic formula are different tools for the same family of problems.
Here is the teacher way to approach the topic. First, read the problem slowly and underline the information that is actually given. Next, name the target: are you finding a value, simplifying an expression, comparing two quantities, solving for a variable, or interpreting a graph? Once the target is clear, the calculation becomes much less mysterious because every step has a job.
- Clear clutter such as parentheses or fractions.
- Collect like terms.
- Undo operations in reverse order.
- Substitute the answer back or test a point.
A helpful habit is to say what each number represents before using it. For example, if a number is a denominator, a radius, a slope, a common difference, or a coefficient, it should not be treated like an ordinary loose number. Its role tells you where it belongs in the formula. This is especially important on ACT-style questions because many wrong answer choices come from using the right numbers in the wrong places.
Another good habit is to keep the work organized vertically. Write one clean line for substitution, one line for simplifying, and one line for the final answer. If the problem has units, keep the units attached. If the problem has signs, exponents, or parentheses, copy them carefully from one line to the next. Most errors in this topic are not caused by a hard idea; they are caused by dropping a negative sign, combining unlike terms, using the wrong denominator, or skipping a check.
When you finish, ask a quick reasonableness question. Should the answer be positive or negative? Should it be larger or smaller than the original number? Does it fit the graph, table, shape, or equation? Can you plug it back into the original problem? This final check turns the lesson from a procedure into understanding.
On a test, the goal is not to write the longest solution. The goal is to write enough clear work that you can see the structure, avoid traps, and recover quickly if one line goes wrong. Practice the examples below with that mindset: identify the type of problem, choose the matching rule, show the substitution, simplify carefully, and check the answer before moving on.
Free printable Worksheets
Exercises for Solving Quadratic Equations
1) \(Solve x^2=25.\)
2) \(Solve x^2-9=0.\)
3) \(Solve x^2+7x=0.\)
4) \(Solve x^2-5x+6=0.\)
5) \(Solve x^2+2x-15=0.\)
6) \(Solve (x-4)^2=49.\)
7) \(Solve 2x^2-8x=0.\)
8) \(Solve 3x^2-12=0.\)
9) \(Solve 2x^2-7x+3=0.\)
10) \(Solve 4x^2+8x+3=0.\)
11) \(Solve x^2+6x+5=0 by completing the square.\)
12) \(Solve 5x^2-20x+15=0.\)
13) \(Solve x^2-4x-12=0.\)
14) \(Solve 9x^2-30x+25=0.\)
15) \(Solve 2x^2+3x-7=0.\)
16) \(Solve (x+2)(x-5)=18.\)
17) \(The product of two consecutive positive integers is 72. What are they?\)
18) \(Solve \frac{x^2-1}{x-1}=6, with x\ne1.\)
19) \(Solve x^4-13x^2+36=0.\)
20) \(A rectangle has length x+5, width x-2, and area 84. Find x.\)
1)\(Solve x^2=25.\)
Step 1: Take square roots.
Step 2: \(x=\pm5\).
Answer: \(x=-5,5\)
2)\(Solve x^2-9=0.\)
Step 1: Move 9 to the other side.
Step 2: \(x^2=9\), so \(x=\pm3\).
Answer: \(x=-3,3\)
3)\(Solve x^2+7x=0.\)
Step 1: Factor: \(x(x+7)=0\).
Step 2: Set each factor equal to 0.
Answer: \(x=0,-7\)
4)\(Solve x^2-5x+6=0.\)
Step 1: Factor: \((x-2)(x-3)=0\).
Step 2: Solve each factor equation.
Answer: \(x=2,3\)
5)\(Solve x^2+2x-15=0.\)
Step 1: Factor: \((x+5)(x-3)=0\).
Step 2: Apply the zero product property.
Answer: \(x=-5,3\)
6)\(Solve (x-4)^2=49.\)
Step 1: \(x-4=\pm7\).
Step 2: Add 4 to both solutions.
Answer: \(x=-3,11\)
7)\(Solve 2x^2-8x=0.\)
Step 1: Factor: \(2x(x-4)=0\).
Step 2: Solve each factor.
Answer: \(x=0,4\)
8)\(Solve 3x^2-12=0.\)
Step 1: \(3x^2=12\), so \(x^2=4\).
Step 2: Take square roots.
Answer: \(x=-2,2\)
9)\(Solve 2x^2-7x+3=0.\)
Step 1: Factor: \((2x-1)(x-3)=0\).
Step 2: Solve both factors.
Answer: \(x=\frac12,3\)
10)\(Solve 4x^2+8x+3=0.\)
Step 1: \(D=8^2-4(4)(3)=16\).
Step 2: \(x=\frac{-8\pm4}{8}\).
Answer: \(x=-\frac32,-\frac12\)
11)\(Solve x^2+6x+5=0 by completing the square.\)
Step 1: \(x^2+6x=-5\); add 9.
Step 2: \((x+3)^2=4\), so \(x+3=\pm2\).
Answer: \(x=-5,-1\)
12)\(Solve 5x^2-20x+15=0.\)
Step 1: Divide by 5.
Step 2: \(x^2-4x+3=(x-1)(x-3)=0\).
Answer: \(x=1,3\)
13)\(Solve x^2-4x-12=0.\)
Step 1: Factor: \((x-6)(x+2)=0\).
Step 2: Solve each factor.
Answer: \(x=6,-2\)
14)\(Solve 9x^2-30x+25=0.\)
Step 1: Recognize \((3x-5)^2=0\).
Step 2: \(3x-5=0\).
Answer: \(x=\frac53\)
15)\(Solve 2x^2+3x-7=0.\)
Step 1: Use the quadratic formula.
Step 2: \(D=3^2-4(2)(-7)=65\).
Answer: \(x=\frac{-3\pm\\sqrt{65}}{4}\)
16)\(Solve (x+2)(x-5)=18.\)
Step 1: Expand to get \(x^2-3x-10=18\).
Step 2: \(x^2-3x-28=(x-7)(x+4)=0\).
Answer: \(x=7,-4\)
17)\(The product of two consecutive positive integers is 72. What are they?\)
Step 1: Let the integers be \(n\) and \(n+1\).
Step 2: \(n^2+n-72=(n+9)(n-8)=0\); choose the positive solution.
Answer: \(8\text{ and }9\)
18)\(Solve \frac{x^2-1}{x-1}=6, with x\ne1.\)
Step 1: Factor: \(x^2-1=(x-1)(x+1)\).
Step 2: Since \(x\ne1\), simplify to \(x+1=6\).
Answer: \(x=5\)
19)\(Solve x^4-13x^2+36=0.\)
Step 1: Let \(u=x^2\); then \(u^2-13u+36=0\).
Step 2: \((u-9)(u-4)=0\), so \(x^2=9\) or \(x^2=4\).
Answer: \(x=-3,-2,2,3\)
20)\(A rectangle has length x+5, width x-2, and area 84. Find x.\)
Step 1: \((x+5)(x-2)=84\) gives \(x^2+3x-94=0\).
Step 2: Formula gives \(x=\frac{-3\pm\\sqrt{385}}{2}\); choose the positive value.
Answer: \(x=\frac{-3+\\sqrt{385}}{2}\)
Solving Quadratic Equations Practice Quiz