Free Full Length ACCUPLACER Mathematics Practice Test

Full Length ACCUPLACER Mathematics Practice Test

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ACCUPLACER Mathematics Practice Test 3

 

(Non–Calculator)   2 Sections – 40 questions Total time for two sections: No Time Limit  You may not use a calculator on this section.

Arithmetic and Elementary Algebra
1- Which of the following is a factor of both \( x^2 \ -\ 9 \ x \ + \ 18\) and \( x^2 \ – \ 7 \ x  \ +\ 6\) ?
(A) (\(x \ + \ 6\))
(B) (\(x \ + \ 3\))
(C) (\(x \ -  \ 6\))
(D) (\(x \ -  \ 1\))
2- What is the area of an isosceles right triangle that has one leg that measures \( 6 \) cm?
(A) \(18\) cm\(^2\)
(B) \(36\) cm\(^2\)
(C) \(9\) cm\(^2\)
(D) \(20\) cm\(^2\)
3- If two angles in a triangle measure \( 46  \) degrees and \(72\) degrees, what is the value of the third angle?
(A) \(64\) degrees
(B) \(56\) degrees
(C) \(46\) degrees
(D) \(62\) degrees
4- Which of the following expressions is equivalent to \( 15 \ – \ \frac{4}{3} \  x \  \leq \ 1\)
(A)  \(x \leq \ – \ 10.5 \)
(B)  \(x \geq \ 10.5 \)
(C)  \(x \geq \ 12 \)
(D)  \(x \leq \ 12 \)
5- \( \frac{1}{2\ b^2} \ + \ \frac{1}{ b} \ = \ \frac{1}{b^2} \) , then  \( b = \)  ?
(A) \(\frac{1}{2}\)
(B) \(- \ \frac{1}{2}\)
(C) \(- \ \frac{3}{2}\)
(D) \( \frac{3}{2}\)
6- \( 7^{\frac{6}{5}} \ × \  7^{\frac{4}{5}} \)=
(A) \(7^5\)
(B) \(7^3\)
(C) \(7^4\)
(D) \(7^2\)
7- If \( a^7 \ + \ c^7 \ = \ c^7 \ + \ b^7\) , then \(  a \ =\) ?
(A) \( c\)
(B) \( b\)
(C) \( b^{4} \ – \ a^{4} \)
(D) \( b^{3} \ – \ a^{4} \)
8- What is  \(178.4786 \) rounded to the nearest hundredth?
(A) \(178.47\)
(B) \(178.50\)
(C) \(178.46\)
(D) \(178.48\)
9- The equation of a line is given as: \( y \ = \ 6 \ x \ – \ 1\)  . Which of the following points does not lie on the line?
(A) \((1,2)\)
(B) \((- \ 2 ,- \ 13 )\)
(C) \((3 , 17 )\)
(D) \((1, 5 )\)
10- A soccer team played \(  210 \) games and won \( 60  \) percent of them. How many games did the team win?
(A) \(125\)
(B) \(124\)
(C) \(123\)
(D) \(126\)
11- The sum of three numbers is \( 64 \) . If another number is added to these three numbers, the average of the four numbers is \( 28 \) .
What is the fourth number?
(A) \(58\)
(B) \(48\)
(C) \(38\)
(D) \(28\)
12- Line m passes through the point \(  (2, 3) \) . Which of the following CANNOT be the equation of line m?
(A) \(y = 1 \ - \ x\)
(B) \( y =  3 \)
(C) \( x  = 2 \)
(D) \( y  =  x \ + \ 1\)
13- If \( a = 9 \)  what’s the value of \( 3 \ a^{2} \ + \ 7 \ a  \ - \ 8 \)?
(A) \(296\)
(B) \(298\)
(C) \(300\)
(D) \(295\)
14- David owed \( $7216 \) . After making \( 32 \) payments of \( $115 \) each , how much did he have left to pay?
(A) \($3,526\)
(B) \($3,525\)
(C) \($3,515\)
(D) \($3,536\)
15- \( (q^{3}) \ . \ (q^{3})  \ =\) ?
(A) \( q^3\)
(B) \( q^9\)
(C) \( q^6\)
(D) \( q^5\)
 
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16- \( x^{2} \  – \ 64 \ = \ 0 \) , \( x \) could equal to:
(A) \(8\)
(B) \(9\)
(C) \(6\)
(D) \(5\)
17- \( (x \ + \ 2) \ (x \ - \ 6) \ =\)
(A) \(x^{2} \ -  \ 4 \ x \ + \ 12\)
(B) \(x^{2} \ +  \ 4 \ x \ + \ 12\)
(C) \(x^{2} \ -   \ 4 \ x \ -  \ 12\)
(D) \(x^{2} \ +   \ 4 \ x \ -  \ 12\)
18- If \(x\) is a positive integer divisible by \(9\), and  \( x \ < \ 81 \) , what is the greatest possible value of \( x \) ?
(A) \(54\)
(B) \(72\)
(C) \(36\)
(D) \(45\)
19- If \( 7.5 \ < \ x  \ ≤ \ 11.0 \) , then  \( x\) cannot be equal to:
(A) \(7.5\)
(B) \(11.0\)
(C) \(9.2\)
(D) \(10.1\)
20- If \(a =  6\) , what is the value of b in this equation?
\(b  = \ \frac{a^{2}}{3} \ + \ 4\)
(A) \(14\)
(B) \(8\)
(C) \(16\)
(D) \(13\)
College–Level Mathematics
21- Suppose a triangle has the dimensions indicated below:
Then Sin \(B =\) ?
ACCUPLACER Mathematics
(A) \(\frac{3}{4}\)
(B) \(\frac{7}{3}\)
(C) \(\frac{3}{6}\)
(D) \(\frac{3}{7}\)
22- A number is chosen at random from \(1\) to \( 50 \) . Find the probability of not selecting a composite number.
(A) \(\frac{8}{25}\)
(B) \(\frac{6}{25}\)
(C) \(\frac{5}{25}\)
(D) \(\frac{4}{25}\)
23- The cost, in thousands of dollars, of producing \(x \) thousands of textbooks is \(C (x) \ = \ x^{2} \ + \ 10 \ x \ + \ 30\) . The revenue, also in thousands of dollars, is \(R (x) = 3 \ x \). Find the profit or loss if \( 2,000 \) textbooks are produced. (profit \(=\) revenue \(–\) cost)
(A) \($22,000\) profit
(B) \($22,000\) loss
(C) \($28,000\) loss
(D) \($28,000\) profit
24- Find the slope – intercept form of the graph \( 5 \ x \ – \ 9  \ y  \ = \ – \ 16\)
(A) \(\ y  =  \frac{5}{9} \ x \ + \ \frac{16}{9} \)
(B) \( - \ 9 \ y  =  - \ 5 \ x \ - \ 16 \)
(C) \(y  =  - \ 5 \ x \ - \ 16 \)
(D) \(y  =  5 \ x \ - \ 16 \)
25- Solve \( e^{(x \ + \ 4  )}  = 32 \)
(A) \(ln \ (32) \ +  \ 4\)
(B) \(ln \ (32) \ +  \ 2\)
(C) \(ln \ (32) \ -  \ 4\)
(D) \(ln \ (32) \ -  \ 2\)
26- If  tan \(\theta \ = \ \frac{8}{15} \)  and  sin \(\theta \  > \ 0 \), then cos \(\theta \ =\) ?
(A) \(\frac{17}{15} \)
(B) \(\frac{15}{17} \)
(C) \(\frac{8}{17} \)
(D) \(\frac{17}{8} \)
27- Michael (M ) is \( 3\) years older than her friend Alex  (A) who is \( 5\) years younger than her sister John (J ). If M , A and J denote their ages, which one of the following represents the given information?
(A) \(\begin{cases}M  \ = \ A \ + \ 3\\ J \ = \  A \ - \ 5\end{cases}\)
(B) \(\begin{cases}M  =  A  \ - \  3 \\ A  =  J \ - \ 5\end{cases}\)
(C) \(\begin{cases}M  =  3  \ + \  A \\ A  =   5 \ - \ J\end{cases}\)
(D) \(\begin{cases}M  =  3  \ + \  A \\ A  =  J \ - \ 5\end{cases}\)
28- Solve the equation: \( log_2⁡ \ (x \ + \ 6) \  –  \ log_2⁡(x \ - \ 2) \ = \ 1\)
(A) \( -  \ 2\)
(B) \( -  \ 10\)
(C) \(2\)
(D) \(10\)
29- From \(9\) students in an algebra class, a group of \(  3 \) students will be chosen to work on a group project. How many different groups of  \(4 \) students can be chosen?
(A) \(72\)
(B) \(21\)
(C) \(36\)
(D) \(48\)
30- What is the domain of the following function?
\( f (x) \ = \ \sqrt{(x \ - \ 6 )} \ + \ 4\)
(A) \(x \ ≥ - \ 6 \)
(B) \(x \leq   - \ 6 \)
(C) \(x \leq  6 \)
(D) \(x \ \geq  6 \)
31- Which of the following point is the solution of the system of equations?
\( \begin{cases}12\ x \ + \ 4 \ y \ = \ 32 \\6 \ x \ - \ 2 \  y  =  8\end{cases} \)
(A) \( (- \ 2, 2) \)
(B) \( ( 2, 2) \)
(C) \( ( 2, - \ 2) \)
(D) \( (- \  2, - \ 2) \)
32- if \( f  (x) \ = \ \frac{(4  \ x \ - \ 1 )}{2 } \) and \( f ^{ \ – \ 1}(x) \) , is the inverse of  \( f  (x) \), what is the value of \( f ^{ \ – \ 1}(3) \) ?
(A) \(\frac{5}{4}\)
(B) \(\frac{3}{4}\)
(C) \(\frac{7}{4}\)
(D) \(\frac{9}{4}\)
33- If  \( f (x) \ = \ 7 \ - \ x  \) and \(g (x) \ = \ – \ x^2 \ – \ 3 \ – \ 5 \ x\) , then find \((g \ + \ f)  (x)\)?
(A) \(– \ x^2 \ – \ 6  \ x \ + \ 4\)
(B) \(– \ x^2 \ – \ 6  \ x \ -  \ 4\)
(C) \(– \ x^2 \ + \ 6  \ x \ -  \ 4\)
(D) \(– \ x^2 \ + \ 6  \ x \ + \ 4\)
34- Find the Center and Radius of the graph \( (x \ - \ 4)^{2}  \ + \  (y  \ + \ 7)^{2} \ = \ 18  \) ?
(A) \(( 4 , 7 )\), \(3 \ \sqrt{2} \)
(B) \(( 4 , 7 )\), \(2 \ \sqrt{3} \)
(C) \((- \ 4 , 7 )\), \(3 \ \sqrt{2} \)
(D) \((4 ,- \  7 )\), \(3 \ \sqrt{2} \)
35- Which of the following lines is parallel to the graph of \( y \ = \  4 \ x \) ?
(A) \(4 \ x \ + \ y \ = \ 4\)
(B) \(4 \ x \ - \ y \ = \ 4\)
(C) \(2 \ x \ - \ y \ = \ 4\)
(D) \(2 \ x \ - \ y \ = \ 2\)
36- \( \frac{| \ 6 \ + \ x \ |}{8} \ ≤ \ 3 \) , then \( x \) =?
(A) \( - \ 30 \ ≤ \ x \ ≤ \ - \ 18 \)
(B) \( 30 \ ≤ \ x \ ≤ \ 18 \)
(C) \( - \ 30 \ ≤ \ x \ ≤ \ 18 \)
(D) \( - \ 18 \ ≤ \ x \ ≤ \ 18 \)
37- Simplify \( \frac{(4 \ + \  i)}{2\ - \  3 \ i} \)
(A) \( \frac{5}{13} \ -  \  i \ \frac{14}{13}\)
(B) \( \frac{5}{13} \  +\  i \ \frac{14}{13}\)
(C) \( - \ \frac{5}{13} \  +\  i \ \frac{14}{13}\)
(D) \( - \ \frac{5}{13} \  - \  i \ \frac{14}{13}\)
38- tan \(( \frac{π}{3}) \ =\) ? 
(A) \(- \ \sqrt3\)
(B) \(- \ 3 \  \sqrt3\)
(C) \(3 \  \sqrt3\)
(D) \( \sqrt3\)
39- \( \frac{\sqrt{48 \ a^7 \ b^2}}{\sqrt{4 \ a^2 \ b^2}} \) =?
(A) \( 2 \ a\ \sqrt{3}\)
(B) \( 2 \ a^2\ \sqrt{3 \ a}\)
(C) \( 2 \ a^2\ \sqrt{3 \ b}\)
(D) \( 2 \ a\ \sqrt{3 \ b}\)
40- Find the inverse function of   \( f (x) \ = \ \frac{(x \ - \ 4 )}{8} \)
(A) \(4 \ (2 \ x \ - \ 1)\)
(B) \(4 \ (2 \ x \ + \ 1)\)
(C) \( (2 \ x \ + \ 1)\)
(D) \( (2 \ x \ - \ 1)\)

1- Choice C is correct

The correct answer is (\(x \ – \ 6\))
Factor each trinomial
\( x^2 \ - \ 9 \ x \ + \ 18 \ \) and \( x^2 \ – \ 7 \ x \ + \ 6 \)
\(x^2 \ - \ 9 \ x \ + \ 18 \Rightarrow (x \ – \ 6) \ (x \ - \ 3) \)
\( x^2 \ – \ 7 \ x \ + \ 6 \Rightarrow (x \ – \ 1) \ (x \ – \ 6) \)

2- Choice A is correct

The correct answer is \(18\) cm\(^2\)
\( a=6  \Rightarrow \) area of triangle is \( =  \frac{1}{2} \ (  6\times \ 6)  =  \frac{36}{2} \ = 18 \) cm\(^2\)

3- Choice D is correct

The correct answer is \(62\) degrees
\( 46^{\circ} \ + \ 72^{\circ }  =  118^{\circ} \)
\( 180^{\circ } \ – \ 118^{\circ}  =  62^{\circ} \)
The value of the third angle is \( 62^\circ \) .

4- Choice B is correct

The correct answer is \(x \geq \ 10.5 \)
Simplify:
\( 15 \ –  \ \frac{4}{3} \ x \  \leq \  1 \  \Rightarrow \ –  \ \frac{4}{3} \ x \  \leq \  – \ 14 \  \Rightarrow \ –  \ x \ \leq\  – \ 10.5 \  \Rightarrow x \geq \ 10.5 \)

5- Choice A is correct

The correct answer is \(\frac{1}{2}\)
\( \frac{1 \ + \ 2\ b}{2 \ b^2} \ = \ \frac{1}{b^2} \Rightarrow (b\neq 0) \)
\(\ b^2 \ + \ 2 \  b^3 \ = \ 2 \ b^2 \ \Rightarrow\)
\(2 \ b^3 \ - \  \ b^2 \ = \ 0 \ \Rightarrow\)
\(\ b^2 \ (2 \ b  \ -  \ 1) \ = \ 0 \ \Rightarrow\)
\(2 \ b \ -  \ 1  \ = \ 0 \ \Rightarrow \ b \ = \frac{1}{2} \)

6- Choice D is correct

The correct answer is \(5^2\)
\( 7^{\frac{6}{5} } \ × \ 7^{\frac{4}{5} }  =  7^ { \frac{6}{5} \ + \ \frac{4}{5}  }  = 7^\frac{10}{5}  =  7^2  \)

7- Choice B is correct

 The correct answer is \(b\)
If \( a^7 \ + \ c^7 \ = \ c^7 \ + \ b^7 \)
then:  \( a^7 \ = \ b^7 \ ⇒ \ a \ = \ b \)

8- Choice D is correct

The correct answer is \(178.48\)
Underline the hundredths place:
\( 178.4\underline{\\7}86 \)
Look to the right if it is \( 7 \) or above, give it a shove.
Then, round up to \( 178.48 \)

9- Choice A is correct

The correct answer is \((1, 2)\)
\( y \ = \ 6 \ x \ – \ 1 \)
A.\( (1, 2) \Rightarrow 2 \ = \ 6 \ – \ 1 \Rightarrow 2 \ ≠ \ 5 \)
B.\( (– \ 2, \ –\ 13) \Rightarrow \ – \ 13 \ = \ – \ 12 \ – \ 1 \Rightarrow \ – \ 13 \ = \ – \ 13 \)
C.\( (3, 17) \Rightarrow \ 17 \ = \ 18 \ – \ 1 \Rightarrow 17 = 17 \)
D.\( (1, 5) \Rightarrow 5 \ = \ 6 \ – \ 1 \Rightarrow \ 5 \ = \ 5 \)

10- Choice D is correct

The correct answer is \(126\)
\( 210 \ × \  \frac{60}{100} \ = \  126 \)

11- Choice B is correct

The correct answer is \(35\)
\( a \ + \ b \ +\ c  =  64 \)
\( \frac{a \ +\ b \ +\ c \ +\ d}{4} \ =\ 28 \ ⇒\ a \ + \ b \ + \ c \ + \ d \ = \ 112  \ ⇒ \ 64 \ + \ d \ = \ 112 \)
\( d \ = \ 112 \ – \ 64 \ = \ 48 \)

12- Choice A is correct

The correct answer is \(y = 1 \ - \ x\)
Solve for each equation:
\( (2, 3) \)
A.\( y \ = \ 1 \ – \ x \ ⇒ \ 3 \ = \ 1 \ – \  3 \ ⇒ \ 3 ≠ - \ 2 \)
B.\( y \ = 3 \ ⇒ 3 =  3\)
C.\( x  = 2 \ ⇒  2  = 2 \)
D.\( y  =  x \ + \ 1  ⇒  3 =  2 \ + \ 1 \ ⇒ \ 3 \ = \ 3\)

13- Choice B is correct

The correct answer is \(298\)
If \( a \ = \ 9 \) 
then : \( 3 \ a^2 \ + \ 7 \ a \ - \ 8  ⇒  3 \ (9)^2 \ + \ 7 \ (9) \ -  \ 8  ⇒  3 \ (81) \ + \ 63  \ - \ 8   =  298 \)

14- Choice D is correct

The correct answer is \($3,536\)
\(32 \ × \ $115 \ = \ $ 3680 \)
Payable amount is:
\( $7216 \ - \ $3680 \ = \ $3536 \)

15- Choice C is correct

The correct answer is \(q^{6}\)
\( (q^3) \ . \ q^3) \ = \ q ^{3 \ + \ 3} \ = \ q^{6} \)

16- Choice A is correct

The correct answer is \(8\)
\( x^2 \ – \ 64 \ = \ 0 \ ⇒ \ x^2 \ = \ 64 \ ⇒ \ x \ = \ 8 \)

17- Choice C is correct

The correct answer is \(x^{2} \ -  \ 4 \ x \ - \ 12\)
Use FOIL (First, Out, In, Last)
\( (x \ + \ 2) \ (x \ - \ 6) \ = \ x^2 \ - \ 6 \ x \ + \ 2 \ x \ - \ 12  = x ^2 \ -  \ 4 \ x \ -  \ 12 \)

18- Choice B is correct

The correct answer is \(72\)
\( \frac{54}{9} \ = \ \frac{18}{3}  = 6\) , \( \frac{72}{9} \ = \ \frac{24}{3}  =  8 \) , \( \frac{36}{9} \ = \ \frac{18}{3} =4 \) , \( \frac{45}{9} \ = \ \frac{15}{3}= 5  \) 
\( 72 \) is prime number

19- Choice A is correct

The correct answer is \(7.5\)
If \(7.5 \ < \ x \ ≤ \ 11.0 \), then \( x\) cannot be equal to \(7.5\)

20- Choice C is correct

The correct answer is \(16\)
If \(a  = \  8 \) , then:
\(b = \ \frac{6^2}{3} \ + \ 4 \ ⇒ \)
\(b  = \ \frac{36}{3} \ + \ 4 \ ⇒ \) 
\(b  = \ 12 \ + \ 4 \ = \ 16 \)

21- Choice D is correct

The correct answer is \(\frac{3}{7}\)
sin\( B = \ \frac{(the \ length \ of \ the \ side \ that \ is \ opposite \ that \ angle)}{(the \ length \ of \ the \ longest \ side \ of \ the \ triangle)} \ = \ \frac{3}{7} \)

22- Choice A is correct

The correct answer is \(\frac{8}{25}\)
Set of number that are not composite between \( 1 \) and \( 50  \) : \(A = \ {1, 2, 3, 5, 7, 11, 13, 17, 19, 23 , 29, 31, 37 , 41,43,47}\)
\(n (A) = \ 16 \ ⇒  p  = \ \frac{16}{50} \ = \ \frac{8}{25} \)

23- Choice B is correct

The correct answer is \($22,000\) loss
\(c  (2) \ = \ (2)^2 \ + \ 6\ (2) \ + \ 12 \ = \ 4 \ + \ 12 \ + \ 12  =  28\)
\(3 \ × \ 2 =  6  ⇒  6 \ - \ 28   = \ - \ 22 \ ⇒ \ $22,000\) loss

24- Choice A is correct

The correct answer is\(\ y  =  \frac{5}{9} \ x \ + \ \frac{16}{9} \)
\( - \ 9 \ y  =  - \ 5 \ x \ - \ 16 \ ⇒\)
\(\ y  =  \frac{- \ 5}{- \ 9} \ x \  - \ \frac{16}{- \ 9} \ ⇒\)
\(\ y  =  \frac{5}{9} \ x \ + \ \frac{16}{9} \)

25- Choice C is correct

The correct answer is \(ln \ (32) \ -  \ 4\)
\( e^{x \ + \ 4}  = 32  ⇒   ln \ (e^{x \ + \ 4}) = \ ln \ (32)\)
\( (x \ + \ 4) \ ln \ (e) =   ln \ (32) \)
\( x \ + \ 4  =  ln \ (32) \ ⇒ \ x \ = \ ln \ (32) \ -  \ 4 \)

26- Choice B is correct

The correct answer is \(\frac{15}{17} \)
tan \(\theta \ = \ \frac{8}{15} \ ⇒\) we have following triangle, then
\( c \ = \ \sqrt{8^2 \ + \ 15^2} \ = \ \sqrt{64 \ + \ 225} \ = \ \sqrt{289} \ = \ 17 \)
cos \(\theta \ = \ \frac{15}{17} \)

27- Choice D is correct

The correct answer is:
M \( = \  3  \ + \) A 
A \( = \)  J  \(  – \ 5 \)

28- Choice D is correct

The correct answer is \(2\)
METHOD ONE:
\( \log_{2}{(x \ + \ 6)} \ – \ \log_{2}{(x \ - \ 2)} = 1 \)
Add \( \log_{2}{(x \ - \ 2)} \) to both sides:
\( \log_{2}{(x \ + \ 6)} \ – \ \log_{2}{(x \ - \ 2)} + \log_{2}{(x \ - \ 2)} = 1 + \log_{2}{(x \ - \ 2)} \)
And simplify:
\( \log_{2}{(x \ + \ 6)} = 1 + \log_{2}{(x \ - \ 2)} \)
Logarithm rule: \( a \ = \ \log_{b}{b^a} \ ⇒ \ 1 \ = \log_{2}{2^1} \ = \ \log_{2}{2} \)
then: \( \log_{2}{(x \ + \ 6)} = \log_{2}{2} \ + \ \log_{2}{(x \ - \ 2)} \)
Logarithm rule: \( \log_{c}{a} +\log_{c}{b} = \log_{c}{a\ b} \)
then: \( \log_{2}{2} \ + \ \log_{2}{(x \ - \ 2)} \ = \ \log_{2}{2 \ (x \ - \ 2)}⇒
\log_{2}{(x \ + \ 6)} \ = \ \log_{2}{2 \ (x \ - \ 2)} \)
When the logs have the same base: \( \log_{b}{(f(x))} \ = \ \log_{b}{(g(x))} \ ⇒ \ f (x) \ = \ g (x) \)
\( x \ + \ 6 \ = \ 2 \ (x \ - \ 2) \ ⇒ \ x \ + \ 6 \ = \ 2 \ x \ – \ 4 \ ⇒ \ - \ x \ = \ - \ 10 \ ⇒ \ x \ = \ 10 \)
METHOD TWO
We know that: \(\log_{a}{b} \ - \ \log_{a}{c} \ = \ \log_{a}{\frac{b}{c}} \) and \( \log_{a}{b} \ = \ c \ ⇒ \ b \ = \ a^c \)
Then: \( \log_{2}{(x \ + \ 6)} \ - \ \log_{2}{(x \ - \ 2)}=\log_{2}{\frac{x \ + \ 6}{x \ - \ 2}} \ = \ 1⇒\)
\(\frac{x \ + \ 6 }{x \ - \ 2}  =  2^1  =  2  ⇒  x  \ + \ 6 \ = \ 2 \ (x \ - \ 2)\)
\( ⇒ \ x \ + \ 6   =  2 \ x \ - \ 4  ⇒ 2 \ x \ - \ x \ = \ 6 \ + \ 4 \ ⇒ \ x \ = \ 10\)

 

29- Choice B is correct

The correct answer is \(21\)
\( C_4^9 \ = \ \frac{9!}{4!(9 \ - \ 3)!} \ = \ \frac {9!}{4! \ 6!} \ = \ \frac{9 \ × \ 8 \ × \ 7 \ × \ 6!}{4! \ × \ 6!} \ = \ \frac{9\ ×\ 8 \ × \ 7 }{4 \ × \ 3 \ × \ 2 \ × \ 1} \ = \ 21  \)

30- Choice D is correct

The correct answer is \(x \ ≥ \ 6 \)
The number under the square root symbol must be zero or greater than zero therefore: 
\( x \ - \ 6 \ ≥ \ 0 \ ⇒ \ x \ ≥ \ 6 \) domain of function \(= \ [6 , \ + \ ∞) \)

31- Choice B is correct

The correct answer is \( (2, 2) \)
\( \begin{cases}12 \ x \ + \ 4 \ y = 32 \\6 \ x \ - \ 2 \ y = 8 \end{cases}\Rightarrow \) Multiplication \( (– \ 2)\) in first equation \( \begin{cases}12 \ x \ + \ 4 \ y = 32 \\- \ 12 \ x \ + \ 4 \ y = - \ 16\end{cases} \)
Add two equations together \( \ ⇒8 \ y = 16 \ ⇒ \ y =2\) then: \( x = 2 \)

32- Choice C is correct

The correct answer is \(\frac{7}{4}\)
\( f  (x)=\frac{4 \ x \ - \ 1}{2} ⇒\)
\(y=\frac{4  \ x \ - \ 1}{2} \ ⇒\)
\(2 \ y \ = \ 4 \ x \ – \ 1 \ ⇒\)
\(2 \ y \ + \ 1 \ = \ 4\ x \ ⇒\)
\( \frac{2 \ y \ + \ 1}{4} \ = \ x \)
\( f^{ \ - \ 1} = \frac{2 \ y \ + \ 1}{4} \ ⇒\)
\(f^{ \ - \ 1} (3) \ = \ \frac{7}{4}  \)

33- Choice A is correct

The correct answer is \(– \ x^2 \ – \ 6  \ x \ + \ 4\)
\( (g \ + \ f) (x) \ = \  g  (x) \ + \  f (x) \ = \ (– \ x^2 \  – \ 3 \ – \ 5  \ x) \ +  \ (7 \ -  \ x) \)
\( – \ x^2 \ +  \ 4 \ – \ 5 \ x \  – \ x \ = \ – \ x^2 \ – \ 6\ x \ + \ 4\)

34- Choice D is correct

The correct answer is \((4 , - \ 7 )\), \(3 \ \sqrt{2} \)
\( (x \ – \ h)^2 \ + \ (y \ – \ k)^2 \ = \ r^2 \ ⇒\) 
center: \( (h,k)\) and radius:\( r \)
\((x \ – \  4)^2 \ + \ (y \ + \ 7 )^2 \ = \ 18 \ ⇒\)
center: \((4 , - \ 7) \) and radius: \( 3 \ \sqrt{2} \)

35- Choice A is correct

The correct answer is \(4 \ x \ + \ y \ = \ 4\)
If two lines are parallel with each other, then the slope of the two lines is the same.
Then in line \( y \ = \ 4 \ x \) , the slope is equal to \( 4\)
And in the line \( 4 \ x \ + \ y \ = \ 4 \ ⇒ y \ = \ 4 \ x \ - \ 4\)
the slope equal to \( 4\)

36- Choice C is correct

The correct answer is \( - \ 30 \ ≤ \ x \ ≤ \ 18 \)
\( \frac{| \ 6 \ + \ x \ |}{8} \ ≤ \ 3 \ ⇒ \ | \ 6 \ + \ x \ | \ ≤ \ 24 \ ⇒\)
\( - \ 24 \ ≤ \ 6 \ + \ x \ ≤ \ 24 \ ⇒\)
\( - \ 24\ - \ 6 \ ≤ \ x \ ≤ \ 24 \ - \ 6 \ ⇒ \)
\( - \ 30 \ ≤ \ x \ ≤ \ 18 \)

37- Choice B is correct

The correct answer is \( \frac{5}{13} \ + \  i \ \frac{14}{13}\)
If \( z_1 \ = \ x_1 \ + \ i \ y_1\) and \( z_2 \ = \ x_2 \ + \ i \ y_2 \ ⇒\)
\( \frac{z _ 1}{z _  2} \ = \ \frac{x_1 \ x_2 \ + \ y_1 \ y_2}{x_2^2 \ + \ y_2^2} \ + \ i  \ \frac{x_2 \ y_1 \ - \ x_1 \ y_2}{x_2^2 \ + \ y_2^2}\)
In this problem: \( x_1 \ = \ 4, \  x_2 \ = 2, \  y_1 \ = \ 1, \ y_2 \ =  - \ 3\)
\(\frac{4 \ +\ i}{ 2 \ - \ 3  \ i} \ = \ \frac{5}{13} \ + \  i \ \frac{14}{13}  \)

38- Choice D is correct

The correct answer is \(\sqrt{3}\)
tan \(( \frac{π}{3}) \ = \sqrt{3} \)

39- Choice B is correct

The correct answer is \( 2 \ a^2 \ \sqrt{3 \ a}\)
\( \frac{\sqrt{48 \ a^7 \ b^2}}{\sqrt{2 \ a^2 \ b^2}} = \frac{4 \ a^2 \ b \sqrt{3}}{2 \ a \ b  } \ = \ 2 \ a^2 \ \sqrt{3 \ a} \)

40- Choice B is correct

The correct answer is \(4 \ (2 \ x \ + \ 1)\)
\( f(x)=\frac{x \ - \ 4}{8} \ ⇒ \ y \ = \ \frac{x \ - \ 4}{8} \ ⇒ \ 8 \ y \ = \ x \ – \ 4 \ ⇒ \ 8\ y \ + \  4 \ = \ x \)
\( f ^{ \ - \ 1} \ = \ 8 \ x \ + \ 4 \ = \ 4 \ ( 2 \ x \ + \ 1) \)

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