Free Full Length TABE Battery Math Practice Test

The correct answer is $71$
$1420\ ÷\  20= 71$ 

The correct answer is $3,273$
$$4,558 \ –\ $1,285=3,273$ 

The correct answer is $4.3$
$7.9 \ −\  3.6 = 4.3$

The correct answer is $22.88$
$\cfrac{\begin{align}4.4 \\× \ 5.2 \end{align}}{22.88}$

The correct answer is $435$
$390\ +\ 45=435$

The correct answer is $12$
$27.6 \ ÷\  2.3 =12$

The correct answer is $1.25$
$12.5 \ ÷\  10 =1.25$ 

The correct answer is $917$
$\cfrac{\begin{align}882 \\+ \ 35 \end{align}}{917}$

The correct answer is $1,920$
$\cfrac{\begin{align}1,452 \\+ \ 468 \end{align}}{1,920}$

The correct answer is $48$
$6 \ ×\  8 =48$ 

The correct answer is $83.51$
$\cfrac{\begin{align}48.35 \\ + \ 35.16 \end{align}}{83.51}$

The correct answer is $1,657$
$\cfrac{\begin{align}2,580 \\- \ 923 \end{align}}{1,657}$

The correct answer is $913$
$3,652 \ ÷\  4 =913$ 

The correct answer is $\frac{1}{2}$
$\frac{2}{3}\ -\  \frac{1}{6}=\frac{1}{2}$

The correct answer is $9$
$\frac{1}{4}\ ÷\   \frac{1}{36}=9$ 

The correct answer is $215$
$43\ ×\ 5=215$

The correct answer is $7 \ \frac{1}{10}$
$7\  \frac{3}{5}\ -\ \frac{1}{2} =7\  \frac{1}{10}$ 

The correct answer is $6^9$
$6^7\ ×\ 6^2=6^9$

The correct answer is $17 \ x \ y$
$12\ x\ y\ +\ 5\ x\ y\ =17 \ x \ y$

The correct answer is $206$
$824 \ ÷\  4 =206$ 

The correct answer is $4\ \frac{1}{10}$
$6\ \frac{2}{5}\ -\ 2\  \frac{3}{10}=6\ +\ \frac{2}{5}\ -\ 2\ -\ \frac{3}{10}=4\ \frac{1}{10}$

The correct answer is $105$
$420 \ ÷\  4 =105$ 

The correct answer is $23\ x$
$15\ x\ +\ 8\ x=23\ x$

The correct answer is $21$
$\frac{30}{100 }\ ×\ 70=\frac{2100}{100 }=21$

The correct answer is $\frac{2}{9}$
$\frac{4}{9}\ -\ \frac{2}{9}=\frac{2}{9}$ 

The correct answer is $-\ 60$
$12\ ×\ (−\ 5)=-\ 60$

The correct answer is $-\ 7$
$−\ 9\ +\ 4 \ –\ 2=-\ 7$

The correct answer is $3\ \frac{29}{32}$
$1 \  \frac{1}{4}\ ×\  3\  \frac{1}{8}=\frac{5}{4}\ ×\ \frac{25}{8} = \frac{125}{32}=3\ \frac{29}{32}$

The correct answer is $\frac{11}{15}$
$\frac{2}{5}\ +\ \frac{1}{3}=\frac{6 \ + \ 5}{15}=\frac{11}{15}$ 

The correct answer is $11\ \frac{3}{4}$
$6\ \frac{2}{4}\ +\ 5\ \frac{1}{4}=6\ +\ \frac{2}{4}\ +\ 5\ +\ \frac{1}{4}=11\ \frac{3}{4}$

The correct answer is $\frac{7}{36}$
$\frac{1}{3}\ ×\   \frac{7}{12}=$ $\frac{7}{36}$

The correct answer is $8$
$\sqrt{64}=8$

The correct answer is $\frac{1}{8}$
$16\ x\  = 2, \ x= \frac{2}{16}=\frac{1}{8}$

The correct answer is $40\%$
___$\%$ of $20 = 8$
$\frac{x}{100 }\  ×\ 20=8\\ x=\frac{800}{20 }=40\%$ 

The correct answer is $2$
$5\%$ of $40$
$\frac{5}{100} \ ×\ 40=\frac{200}{100}=2$ 

The correct answer is $220$
$\frac{25}{100 }\  ×\ x=55\\ x=\frac{5500}{25 }=220$ 

The correct answer is $7$
$(5\ +\ 2)^2\ ÷\ 7=7^2\ ÷\  7=49\ ÷\ 7=7$

The correct answer is $15$
$12 \ –\  (\ –\ 3)=12 \ + \ 3= 15$

The correct answer is $1 \ \frac{1}{10} \ x$
$5\ x\ +\ \frac{1}{2} \ x =1 \ \frac{1}{10} \ x$

The correct answer is $\frac{11}{9}$
$5 \  \frac{2}{4}\ ÷\   4\  \frac{6}{12}= \frac{11}{2}\ \div \ \frac{27}{6} = \frac{66}{54}= \frac{11}{9}$

The correct answer is $\frac{11}{9}$
$5 \  \frac{2}{4}\ ÷\   4\  \frac{6}{12}= \frac{11}{2}\ \div \ \frac{27}{6} = \frac{66}{54}= \frac{11}{9}$

The correct answer is $104$
A.$\frac{38}{4} = 9.5$
B.$\frac{46}{4} = 11.5$
D.$\frac{85}{4} = 21.25$
C.$\frac{104}{4} = 26$

The correct answer is $2.90$ ft
Write a proportion and solve for the missing number.
$\frac{44}{16} = \frac{8}{x}→ 44\ x\ =8\ ×\ 16=128$
$44\ x\ =128→x=\frac{128}{44}=2.90$

The correct answer is $243$ 
$3^5 = 3 \ ×\ 3 \ ×\ 3 \ ×\ 3 \ ×\ 3 = 243$

The correct answer is $7\ x^4\ +\ 2\ x^3\ -\ 10\ x^2$
Simplify and combine like terms.
$(5\ x^3\ -\ 6\ x^2\ +\ 2\ x^4\ )\ -\ (4\ x^2\ -\ 5\ x^4\ +\ 3\ x^3\ ) ⇒$
$(5\ x^3\ -\ 6\ x^2\ +2\ x^4\ )\ -\ 4\ x^2\ +\ 5\ x^4\ -\ 3\ x^3\ ⇒$
$7\ x^4\ +\ 2\ x^3\ -\ 10\ x^2$

The correct answer is $\frac{8}{9}$
A.$\frac{5}{8} = 0.625$
B.$\frac{3}{7} = 0.43$
D.$\frac{8}{9} = 0.88$
C.$\frac{5}{11} = 0.45$

The correct answer is $113.2$ 
The area of the square is $800.89$.
Therefore, the side of the square is square root of the area.
$\sqrt{800.89}=28.3$
Four times the side of the square is the perimeter: $4 \ ×\ 28.3 =113.2$

Solve for $x$.
$-\ 2≤2\ x\ -\ 4\ <8 ⇒$ (add $4$ all sides) 
$-\ 2\ +\ 4≤2\ x\ -\ 4\ +\ 4<8\ +\ 4 ⇒$ 
$2≤2\ x\ <12 ⇒$ (divide all sides by $2$) $1≤\ x\ <6$
$x$ is between $1$ and $6$.
Choice D represent this inequality.

The correct answer is $-\ 27$ 
To solve absolute values equations, write two equations. 
$3\ x\ -\ 9$ can equal positive $18$, or negative $18$. Therefore, 
$3\ x\ -\ 9= 18 ⇒ 3\ x=27⇒ x=9$
$3\ x\ -\ 9= -\ 18 ⇒ 3\ x=-\ 18\ +\ 9=-\ 9⇒ x=-\ 3$
Find the product of solutions: $-\ 3\ ×\ 9=-\ 27$

The correct answer is $-\ 61$
Use PEMDAS (order of operation):
$[3\ ×\ (–\ 12)\ -\ 44]\ –\ (–\ 12)\ +\ [3\ ×\ 7]\ ÷\ 3=[-\ 36\ -\ 44]\ +\ 12\ +\ 21\ ÷\ 3=-\ 80\ +\ 12\ +\ 7=-\ 61$

The correct answer is $42$
$\frac{240}{8 }< \ x\ < \frac{360}{8}, 30 < \ x\ < 45$, From the choices provided, only $42$ is correct.

The correct answer is $120$ m$^3$
Volume of a box $=$ length $×$ width $×$ height $= 3 \ ×\ 5 \ ×\ 8 = 120$

The correct answer is $200$
$40 \ ×\ 5 = 200$

The correct answer is $37.5\%$ 
The population is increased by $10\%$ and $25\%$.
$15\%$ increase changes the population to $110\%$ of original population.
For the second increase, multiply the result by $125\%$.
$(1.10) \ ×\ (1.25) = 1.375 = 137.5\%$
$37.5$ percent of the population is increased after two years.

The correct answer is $-\ \frac{1}{4}$ 
The equation of a line in slope intercept form is: $y=m\ x\ +\ b$
Solve for $y$.
$4\ x\ -\ y=7→-\ y=-\ 4\ +\ 7$
Divide both sides by $(-\ 1)$.
Then: $-\ y=-\ 4\ x\ +\ 7→y=4\ x\ -\ 7$
The slope of this line is $4$.
The product of the slopes of two perpendicular lines is $- \ 1$. 
Therefore, the slope of a line that is perpendicular to this line is:
$m_1 \ ×\ m_2 = -\ 1 ⇒ 4 \ ×\ m_2 = -\ 1 ⇒ m_2 =- \frac{ 1}{4}=-\ \frac{1}{4}$

The correct answer is $20$
Use formula of rectangle prism volume.
V $=$ (length) (width) (height) $⇒ 5000 = (25)\ (10)$ (height) $⇒$ height $=5000 \ ÷\ 250 = 20$

The correct answer is $\frac{1}{3} ,44\% , 0.54 , \frac{4}{5}$
Change the numbers to decimal and then compare.
$\frac{1}{3} = 0.333…$
$0.54$ 
$44\% = 0.44$
$\frac{4}{5} = 0.80$
Therefore
$\frac{1}{3} \ < \ 44\% \ < \ 0.54 \ < \ \frac{4}{5}$

The correct answer is $12,324$
In the stadium the ratio of home fans to visiting fans in a crowd is $5:7$.
Therefore, total number of fans must be divisible by $12: 5 \ +\ 7 = 12$.
Let’s review the choices:
A. $12,324:\ 12,324\ ÷\ 12=1,027$
B. $42,326:\ 42,326\ ÷\ 12=3,527.166$
C. $44,566:\ 44,566\ ÷\ 12=3,713.833$
D. $66,812:\ 66,812\ ÷\ 12=5,567.666$
Only choice A when divided by $12$ results a whole number.

The correct answer is $\frac{1}{4}$
Probability$=\frac{number \ of\ desired\ \ outcomes}{number \ of\ \ total \ outcomes} = \frac{18}{12\ +\ 18\ +\ 18\ +\ 24} =\frac{18}{72} = \frac{1}{4}$

The correct answer is $24$ 
Plug in the value of $x$ and $y$.
$4\ (\ x\  −\  3\ y\ )\  +\  (3 \ −\  x\ ) ^2$ when $x = 2$ and $y = −\ 2$  
$x=2$ and $y=-\ 2$
$4\ (x\ -\ 3\ y)\ +\ (3\ -\ x)^2=4\ (2\ -\ 2(-\ 2))\ +\ (2\ -\ 2)^2=4\ (2\ +\ 4)\ +\ (0)^2 = 24 \ +\ 0=24$

The correct answer is $60,000$ 
Three times of $24,000$ is $72,000$. One sixth of them cancelled their tickets.
One sixth of $72,000$ equals $12,000\ (\frac{1}{6} \ ×\ 72000 = 12000)$. 
$60,000 \ (72000 \ –\ 12000 = 60000)$ fans are attending this week

The correct answer is $10$ meters
The width of the rectangle is twice its length.
Let $x$ be the length. Then, width $=3\ x$
Perimeter of the rectangle is $2$ (width $+$ length) $= 3\ (2\ x\ +\ x)=90 ⇒ 9\ x=90 ⇒ x=10$
Length of the rectangle is $10$ meters.

The correct answer is $\frac{1}{4}$
The probability of choosing a Hearts is $\frac{16}{64}=\frac{1}{4}$

The correct answer is $20$ 
The ratio of boy to girls is $3:7$. 
Therefore, there are $3$ boys out of $10$ students.
To find the answer, first divide the total number of students by $10$, then multiply the result by $3$. 
$50 \div 10=5 \Rightarrow 5\times3=15$
There are $15$ boys and $35\  (50\  –\  15)$ girls.
So, $20$ more boys should be enrolled to make the ratio $1:1$

The correct answer is $18$
The diagonal of the square is $8$.
Let $x$ be the side. 
Use Pythagorean Theorem: $a^2\ +\ b^2=c^2$
$x^2\ +\ x^2=6^2⇒ 2\ x^2\ = 6^2 ⇒ 2\ x^2= 36 ⇒x^2 = 18 ⇒x= \sqrt{18}$
The area of the square is: $\sqrt{18}\ ×\ \sqrt{18}=18$

The correct answer is $\frac{216}{729}$
The square of a number is $\frac{36}{81}$, then the number is the square root of $\frac{36}{81}$
$\sqrt{\frac{36}{81}}= \frac{6}{9}$ 
The cube of the number is: $(\frac{6}{9})^3 = \frac{216}{729}$

The correct answer is $80$
Jason needs an $80\%$ average to pass for five exams.
Therefore, the sum of $5$ exams must be at lease $5 \ ×\ 80 = 400$
The sum of $4$ exams is: $68\ +\ 75\ +\ 89\ +\ 88=320$
The minimum score Jason can earn on his fifth and final test to pass is: $400\ –\ 320=80$

The correct answer is $30$
Write the numbers in order: $5\ , \ 19\ , \ 27\ , \ 30\ ,\ 35\ ,\ 48\ , \ 67$
Median is the number in the middle. So, the median is $30$.

The correct answer is $\frac{ 1}{20}$
$3,000$ out of $60,000$ equals to $\frac{3000}{60000} = \frac{3}{60} =\frac{ 1}{20}$

The correct answer is $170$
Use the information provided in the question to draw the shape.
Use Pythagorean Theorem: $a^2 \ +\ b^2 = c^2$
$80^2 \ +\ 150^2 = c^2 ⇒ 6400 \ +\ 22500 = c^2 ⇒ 28900 = c^2 ⇒ c = 170$

The correct answer is $87.5$
The difference of $94$ and $69$ is $25$. Therefore, $25$ should be subtracted from the sum.
$4400 \ –\ 25 = 4375$, mean $= \frac{sum \ of\ terms }{number \ of\ terms} ⇒$ mean $= \frac{4375 }{50} = 87.5$

The correct answer is $90$
To find the number of possible outfit combinations, multiply number of options for each factor: $3 \ ×\ 6\ ×\ 5 = 90$

The correct answer is $320\ x^{11}\ y^6$ 
Simplify. 
$5\ x^2\ \ y^3\ (4 \ x^3\ y\ )^3= 5\ x^2\ y^3\ (64\ x^9\ y^3\ ) = 320\ x^{11}\ y^6$

The correct answer is $40$ 
Plug in $124$ for $F$ and then solve for $C$.
$C=\frac{4}{12}\ (F \ –\ 32) ⇒ C=\frac{4}{12}\ (122 \ –\ 32) ⇒ C=\frac{4}{12}\ (90)=30$

The correct answer is $70\%$ 
The failing rate is $18$ out of $60 = \frac{18}{60}$
Change the fraction to percent:
$\frac{18}{60} \ ×\ 100\%=30\%$
$30$ percent of students failed. Therefore, $70$ percent of students passed the exam.

The correct answer is $10$ 
Let $x$ be the number.
Write the equation and solve for $x$. 
$50\%$ of $x=5⇒ 0.50 \ x\ =5 ⇒ x=5 \ ÷\ 0.50=10$

The correct answer is $\frac{1}{4}$
To get a sum of $6$ for two dice, we can get $5$ different options:
$(5, 1), (4, 2), (3, 3), (2, 4), (1, 5)$
To get a sum of $9$ for two dice, we can get $4$ different options:
$(6, 3), (5, 4), (4, 5), (3, 6)$
Therefore, there are $9$ options to get the sum of $6$ or $9$. 
Since, we have $6 \ ×\ 6 = 36$ total options, the probability of getting a sum of $6$ and $9$ is $9$ out of $36$ or $\frac{1}{4}$.

The correct answer is $33$
average $= \frac{\ sum\ \ of\ \ terms}{\ number\ \ of\ \ terms} ⇒$ (average of $7$ numbers) $21 = \frac{\ sum\ \ of\ \ numbers}{7} ⇒$
sum of $7$ numbers is $21 \ ×\ 7 = 147$
(average of $4$ numbers) $12 = \frac{\ sum\ \ of\ \ numbers }{4} ⇒$sum of $4$ numbers is $12 \ ×\ 4 = 48$
sum of $7$ numbers $–$ sum of $4$ numbers $=$ sum of $3$ numbers $147 \ – \ 48 = 99$
average of $3$ numbers $=\frac {99 }{3}=33$

The correct answer is $(-\ 2,3)$ 
$x\ +\ 2\ y\ =4$. Plug in the values of x and y from choices provided. Then:
1.$(−\ 2,3)$        $x\ +\ 2\ y=4→−2\ +\ 2\ (3)=4→−2\ +\ 6=4$         This is true!
2.$(1,2)$            $x\ +\ 2\ y=4→1\ +\ 2\ (2)=4→1\ +\ 4=4$               This is NOT true!
3.$(−\ 1,3)$        $x\ +\ 2\ y=4→−1\ +\ 2\ (3)=4→−1\ +\ 6=4$         This is NOT true!
4.$(−\ 3,4)$        $x\ +\ 2\ y =4→−3 \ +\ 2\ (4)=4→−3\ +\ 8=4$         This is NOT true!

The correct answer is $$810$ 
Let $x$ be all expenses, then $\frac{22}{100}\ x\ =$660 →x=\frac{100\ ×\ $660}{22}=$3,000$
He spent for his rent: $\frac{27}{100}\ ×\ $3,000=$810$

The correct answer is $\frac{1}{3}$
Solving Systems of Equations by Elimination
Multiply the first equation by $(3)$, then add it to the second equation.
$\cfrac{\begin{align} 3 \ (3\ x\ +\ 5\ y=21)\\ - \ 9 \ x\ -\ 3\ y=-\ 15 \end{align}} {\begin{align} 9 \ x\ +\ 15\ y= 63\\ - \ 9\ x\ -\ 3\ y=-\ 15 \end{align}} \\ \ \ \ \ \ \ \  \ \ \  \ \ \ \ \ 12\ y\ = 48 \ \ \  \Rightarrow y= 4$
Plug in the value of $x$ into one of the equations and solve for $x$.
$3\ x\ +\ 5\ (4)= 21 \Rightarrow 3\ x\ +\ 20= 21 \Rightarrow 3\ x\ = 1 \Rightarrow x =\frac{1}{3}$

The correct answer is $57$
First, find the number.
Let $x$ be the number.
Write the equation and solve for $x$. 
$120 \%$ of a number is $72$, then: $1.2\ ×\ x=72⇒ x=72 \ ÷\ 1.2=60$
$95 \%$ of $60$ is: $0.95 \ × \ 60 =57$

The correct answer is $150$ cm$^2$
The perimeter of the trapezoid is $36$ cm.
Therefore, the missing side (height) is $= 64\ –\ 24 \ –\ 12\ –\ 18=10$
Area of a trapezoid: A$= \frac{ 1}{2}\ h\ (b_1\ +\ b_2)= \frac{ 1}{2}\ (10)\ (12\ +\ 18)=150$

The correct answer is $2$
Solve for $y$.
$4\ x\ -\ 2\ y\ =8 ⇒ -\ 2\ y\ =8\ -\ 4\ x ⇒ y=2\ x\ -\ 4$
The slope of the line is $2$.

The correct answer is $6$ hours
The distance between Jason and Joe is $9$ miles. Jason running at $5.5$ miles per hour and Joe is running at the speed of $7$ miles per hour.
Therefore, every hour the distance is $1.5$ miles less. $9\ ÷\ 1.5=6$

The correct answer is $150\ x\ +\ 14,000 \ ≤\ 30,000$
Let $x$ be the number of new shoes the team can purchase.
Therefore, the team can purchase $150 \ x$.
The team had $$30,000$ and spent $$14,000$.
Now the team can spend on new shoes $$16,000$ at most. 
Now, write the inequality:
$150\ x\ +\ 14,000 \ ≤\ 30,000$

The correct answer is $$726$ 
Use simple interest formula: $I=prt$
($I =$ interest, $p =$ principal,$r =$ rate,$t =$ time)
$I=(13200)\ (0.055)\ (2)=726$

The correct answer is $28$
Let $x$ be the width of the rectangle. Use Pythagorean Theorem: 
$a^2 \ +\ b^2 = c^2$
$x ^2 \ +\ 6^2 = 10^2 ⇒ x ^2 \ +\ 36 = 100 ⇒ x ^2 = 100 \ –\ 36 = 64 ⇒ x = 8$
Perimeter of the rectangle $= 2$ (length $+$ width) $= 2\ (8 \ +\ 6) = 2\ (14) = 28$

The correct answer is $\frac{1}{5}$
Isolate and solve for $x$.
$\frac{2}{3} \ x\ +\ \frac{1}{5}= \frac{1}{3} ⇒\frac{2}{3}\  x=\frac{1}{3} \ -\ \frac{1}{5} =\frac{2}{15} ⇒\frac{2}{3} \ x\ = \frac{2}{15}$ 
Multiply both sides by the reciprocal of the coefficient of $x$.
$(\frac{3}{2})\ \frac{2}{3} \ x\ =\frac{2}{15} \ (\frac{3}{2}) ⇒ x= \frac{6}{30} =\frac{1}{5}$

The correct answer is $66 \  π$ in$^2$
Surface Area of a cylinder $= 2π\ r\ (r \ +\ h)$,
The radius of the cylinder is $3\ (6 \ ÷\ 2)$ inches and its height is $8$ inches. Therefore, 
Surface Area of a cylinder $= 2π\ (3)\ (3 \ +\ 8) = 66 \  π$

The correct answer is $28$
First, find the sum of five numbers. 
average $= \frac{\ sum\ \ of\ \ terms}{\ number\ \ of\ \ terms} ⇒ 24 = \frac{\ sum\ \ of\ 5\ \ numbers}{5} ⇒$ sum of $5$ numbers $= 24 \ ×\ 5 = 120$
The sum of $5$ numbers is $120$. If a sixth number that is greater than $42$ is added to these numbers, then the sum of $6$ numbers must be greater than $162$. 
$120 \ +\ 42 = 162$
If the number was $42$, then the average of the numbers is: 
average $=\frac {\ sum \ \ of\ \ terms }{\ number\ \ of\ \ terms}=\frac{162}{6}=27$ 
Since the number is bigger than $42$.
Then, the average of six numbers must be greater than $27$.
Choice D is greater than $27$.