How to Find the Length of Arc and the Area of Sector
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What is the Area of the Sector of a Circle?
The area of a sector in the region that a circle's sector encloses. Minor and major sectors are the two different categories of sectors. A major sector is larger than a semi-circle, whereas a minor sector is smaller than a semi-circle.
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Sector Area Formula
We use the area of a sector formula to get the overall area that the sector encompasses. The following formulae can be used to determine a sector's area:
Area of a Sector of a Circle \(= \ (\frac{θ}{360}) \times πr^2\), where \(r\) is the circle's radius and \(θ\) is the sector angle, in degrees, that the arc at the center subtends.
Area of a Sector of a Circle \(= \ \frac{1}{2} \times r^2θ\), where \(r\) is the circle's radius and \(θ\) sector angle, expressed in radians that the arc at the circle's center subtends.
Arc Length
Any section of a circle's circumference is considered an arc. The length of an arc is the distance between its two endpoints. Knowing a little bit about circle geometry is necessary to determine an arc length. Since the arc is a component of the circumference, you can determine the arc length if you know what percentage of \(360\) degrees the arc's central angle is.
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Arc Length Formula
Arc length \(= \ \frac{Central \ Angle}{360°} \times 2πr\)
Example
Find the length of the red arc. (\(π \ = \ 3.14\))
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Solution
Arc length \(= \ \frac{Central \ Angle}{360°} \times 2πr\)
As shown in the above picture, \(r \ = \ 9\) and Central Angle \(= \ 150°\), So:
Arc length \(= \ \frac{150°}{360°} \times 2π \times 9\) \(= \ \frac{5}{12} \times 2(3.14) \times 9 \ = \ 23.55\)
Therefore, the arc length is \(23.55\).
Arc Length and Sector Area
Think of this lesson as more than a rule to memorize. Arc Length and Sector Area is about angles, triangles, radians, and circular motion. A strong student does not rush to the first formula on the page; they pause, identify the structure of the problem, and then choose the tool that matches that structure. That pause is what prevents most mistakes.
Trig ratios connect angles to side lengths. In a right triangle, \(\sin\theta=\frac{opposite}{hypotenuse}\), \(\cos\theta=\frac{adjacent}{hypotenuse}\), and \(\tan\theta=\frac{opposite}{adjacent}\).
Here is the teacher way to approach the topic. First, read the problem slowly and underline the information that is actually given. Next, name the target: are you finding a value, simplifying an expression, comparing two quantities, solving for a variable, or interpreting a graph? Once the target is clear, the calculation becomes much less mysterious because every step has a job.
- Sketch or label the shape.
- Decide whether the question asks for length, area, volume, or surface area.
- Substitute values into the matching formula.
- Keep units squared for area and cubed for volume.
A helpful habit is to say what each number represents before using it. For example, if a number is a denominator, a radius, a slope, a common difference, or a coefficient, it should not be treated like an ordinary loose number. Its role tells you where it belongs in the formula. This is especially important on ACT-style questions because many wrong answer choices come from using the right numbers in the wrong places.
Another good habit is to keep the work organized vertically. Write one clean line for substitution, one line for simplifying, and one line for the final answer. If the problem has units, keep the units attached. If the problem has signs, exponents, or parentheses, copy them carefully from one line to the next. Most errors in this topic are not caused by a hard idea; they are caused by dropping a negative sign, combining unlike terms, using the wrong denominator, or skipping a check.
When you finish, ask a quick reasonableness question. Should the answer be positive or negative? Should it be larger or smaller than the original number? Does it fit the graph, table, shape, or equation? Can you plug it back into the original problem? This final check turns the lesson from a procedure into understanding.
On a test, the goal is not to write the longest solution. The goal is to write enough clear work that you can see the structure, avoid traps, and recover quickly if one line goes wrong. Practice the examples below with that mindset: identify the type of problem, choose the matching rule, show the substitution, simplify carefully, and check the answer before moving on.
Free printable Worksheets
Exercises for Finding the Arc Length and the Sector Area
1) Find the arc length of a circle with radius \(6\) and central angle \(60°\).
2) Find the sector area of a circle with radius \(4\) and central angle \(90°\).
3) Find the arc length of a circle with radius \(9\) and central angle \(120°\).
4) Find the sector area of a circle with radius \(10\) and central angle \(72°\).
5) Find the arc length when \(r=5\) and \(\theta=\frac{π}{3}\) radians.
6) Find the sector area when \(r=8\) and \(\theta=\frac{π}{4}\) radians.
7) A circle has diameter \(14\) and central angle \(150°\). Find the arc length.
8) Find the sector area of a circle with radius \(12\) and central angle \(45°\).
9) An arc has length \(5π\) in a circle of radius \(10\). Find the central angle in radians.
10) A sector has area \(24π\) in a circle of radius \(12\). Find the central angle in degrees.
11) Find the arc length when \(r=3\) and \(\theta=\frac{7π}{6}\) radians.
12) Find the sector area when \(r=6\) and \(\theta=\frac{5π}{3}\) radians.
13) A circle has circumference \(18π\). Find the length of an \(80°\) arc.
14) A sector is \(\frac{3}{8}\) of a circle with radius \(10\). Find its area.
15) An arc length is \(\frac{14π}{3}\), and the central angle is \(120°\). Find the radius.
16) A sector has area \(\frac{50π}{3}\) and central angle \(150°\). Find the radius.
17) A circle has radius \(18\), and an arc length is \(6π\). Find the central angle in degrees.
18) A circle has radius \(4\), and a sector area is \(10π\). Find the central angle in radians.
19) A clock minute hand is \(6\) inches long. How far does its tip travel in \(25\) minutes?
20) A sector has radius \(9\) and arc length \(6π\). Find the sector area.
1)Find the arc length of a circle with radius \(6\) and central angle \(60°\).
Use \(s=\frac{\theta}{360°}\cdot2πr\).
\(s=\frac{60}{360}\cdot2π(6)=2π\).
\(\color{red}{2π}\)
2)Find the sector area of a circle with radius \(4\) and central angle \(90°\).
Use \(A=\frac{\theta}{360°}\cdotπr^2\).
\(A=\frac{90}{360}\cdotπ(4)^2=4π\).
\(\color{red}{4π}\)
3)Find the arc length of a circle with radius \(9\) and central angle \(120°\).
Use \(s=\frac{120}{360}\cdot2π(9)\).
\(s=\frac{1}{3}\cdot18π=6π\).
\(\color{red}{6π}\)
4)Find the sector area of a circle with radius \(10\) and central angle \(72°\).
Use \(A=\frac{72}{360}\cdotπ(10)^2\).
\(A=\frac{1}{5}\cdot100π=20π\).
\(\color{red}{20π}\)
5)Find the arc length when \(r=5\) and \(\theta=\frac{π}{3}\) radians.
For radians, use \(s=r\theta\).
\(s=5\cdot\frac{π}{3}=\frac{5π}{3}\).
\(\color{red}{\frac{5π}{3}}\)
6)Find the sector area when \(r=8\) and \(\theta=\frac{π}{4}\) radians.
For radians, use \(A=\frac{1}{2}r^2\theta\).
\(A=\frac{1}{2}(8)^2\cdot\frac{π}{4}=8π\).
\(\color{red}{8π}\)
7)A circle has diameter \(14\) and central angle \(150°\). Find the arc length.
The radius is \(7\). Use \(s=\frac{150}{360}\cdot2π(7)\).
\(s=\frac{5}{12}\cdot14π=\frac{35π}{6}\).
\(\color{red}{\frac{35π}{6}}\)
8)Find the sector area of a circle with radius \(12\) and central angle \(45°\).
Use \(A=\frac{45}{360}\cdotπ(12)^2\).
\(A=\frac{1}{8}\cdot144π=18π\).
\(\color{red}{18π}\)
9)An arc has length \(5π\) in a circle of radius \(10\). Find the central angle in radians.
Use \(s=r\theta\).
\(5π=10\theta\), so \(\theta=\frac{π}{2}\).
\(\color{red}{\frac{π}{2}}\)
10)A sector has area \(24π\) in a circle of radius \(12\). Find the central angle in degrees.
Use \(A=\frac{\theta}{360°}\cdotπr^2\).
\(24π=\frac{\theta}{360}\cdot144π\), so \(\theta=60°\).
\(\color{red}{60°}\)
11)Find the arc length when \(r=3\) and \(\theta=\frac{7π}{6}\) radians.
Use \(s=r\theta\).
\(s=3\cdot\frac{7π}{6}=\frac{7π}{2}\).
\(\color{red}{\frac{7π}{2}}\)
12)Find the sector area when \(r=6\) and \(\theta=\frac{5π}{3}\) radians.
Use \(A=\frac{1}{2}r^2\theta\).
\(A=\frac{1}{2}(36)\cdot\frac{5π}{3}=30π\).
\(\color{red}{30π}\)
13)A circle has circumference \(18π\). Find the length of an \(80°\) arc.
Arc length is the same fraction of circumference as the central angle is of \(360°\).
\(s=\frac{80}{360}\cdot18π=4π\).
\(\color{red}{4π}\)
14)A sector is \(\frac{3}{8}\) of a circle with radius \(10\). Find its area.
The whole circle area is \(πr^2=100π\).
The sector area is \(\frac{3}{8}\cdot100π=\frac{75π}{2}\).
\(\color{red}{\frac{75π}{2}}\)
15)An arc length is \(\frac{14π}{3}\), and the central angle is \(120°\). Find the radius.
Convert \(120°\) to radians: \(120°=\frac{2π}{3}\).
Use \(s=r\theta\): \(\frac{14π}{3}=r\cdot\frac{2π}{3}\), so \(r=7\).
\(\color{red}{7}\)
16)A sector has area \(\frac{50π}{3}\) and central angle \(150°\). Find the radius.
Use \(A=\frac{150}{360}πr^2=\frac{5}{12}πr^2\).
\(\frac{50π}{3}=\frac{5}{12}πr^2\), so \(r^2=40\) and \(r=2\sqrt{10}\).
\(\color{red}{2\sqrt{10}}\)
17)A circle has radius \(18\), and an arc length is \(6π\). Find the central angle in degrees.
Use \(s=r\theta\): \(6π=18\theta\), so \(\theta=\frac{π}{3}\) radians.
Convert to degrees: \(\frac{π}{3}=60°\).
\(\color{red}{60°}\)
18)A circle has radius \(4\), and a sector area is \(10π\). Find the central angle in radians.
Use \(A=\frac{1}{2}r^2\theta\).
\(10π=\frac{1}{2}(16)\theta=8\theta\), so \(\theta=\frac{5π}{4}\).
\(\color{red}{\frac{5π}{4}}\)
19)A clock minute hand is \(6\) inches long. How far does its tip travel in \(25\) minutes?
\(25\) minutes is \(\frac{25}{60}=\frac{5}{12}\) of a full circle.
The distance is \(\frac{5}{12}\cdot2π(6)=5π\) inches.
\(\color{red}{5π\text{ in.}}\)
20)A sector has radius \(9\) and arc length \(6π\). Find the sector area.
Use \(A=\frac{1}{2}rs\) when radius and arc length are known.
\(A=\frac{1}{2}(9)(6π)=27π\).
\(\color{red}{27π}\)
Arc Length and Sector Area Practice Quiz