1) \(LCM(6, \ 8) = \color{red}{24}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(6 = 2 \times 3\)
\(8 = 2 \times 2 \times 2\)
So \(GCF(6, \ 8) = 2\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(6, \ 8)=\dfrac{6 \times 8}{2}\)
Step 3: Divide first, then multiply: \(6 \div 2 = 3\), and \(3 \times 8 = \color{red}{24}\).
Greatest Common Factor of 6 and 8
2) \(LCM(9, \ 12) = \color{red}{36}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(9 = 3 \times 3\)
\(12 = 2 \times 2 \times 3\)
So \(GCF(9, \ 12) = 3\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(9, \ 12)=\dfrac{9 \times 12}{3}\)
Step 3: Divide first, then multiply: \(9 \div 3 = 3\), and \(3 \times 12 = \color{red}{36}\).
Greatest Common Factor of 9 and 12
3) \(LCM(10, \ 15) = \color{red}{30}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(10 = 2 \times 5\)
\(15 = 3 \times 5\)
So \(GCF(10, \ 15) = 5\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(10, \ 15)=\dfrac{10 \times 15}{5}\)
Step 3: Divide first, then multiply: \(10 \div 5 = 2\), and \(2 \times 15 = \color{red}{30}\).
Greatest Common Factor of 10 and 15
4) \(LCM(14, \ 21) = \color{red}{42}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(14 = 2 \times 7\)
\(21 = 3 \times 7\)
So \(GCF(14, \ 21) = 7\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(14, \ 21)=\dfrac{14 \times 21}{7}\)
Step 3: Divide first, then multiply: \(14 \div 7 = 2\), and \(2 \times 21 = \color{red}{42}\).
Greatest Common Factor of 14 and 21
5) \(LCM(16, \ 20) = \color{red}{80}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(16 = 2 \times 2 \times 2 \times 2\)
\(20 = 2 \times 2 \times 5\)
So \(GCF(16, \ 20) = 4\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(16, \ 20)=\dfrac{16 \times 20}{4}\)
Step 3: Divide first, then multiply: \(16 \div 4 = 4\), and \(4 \times 20 = \color{red}{80}\).
Greatest Common Factor of 16 and 20
6) \(LCM(18, \ 24) = \color{red}{72}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(18 = 2 \times 3 \times 3\)
\(24 = 2 \times 2 \times 2 \times 3\)
So \(GCF(18, \ 24) = 6\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(18, \ 24)=\dfrac{18 \times 24}{6}\)
Step 3: Divide first, then multiply: \(18 \div 6 = 3\), and \(3 \times 24 = \color{red}{72}\).
Greatest Common Factor of 18 and 24
7) \(LCM(25, \ 30) = \color{red}{150}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(25 = 5 \times 5\)
\(30 = 2 \times 3 \times 5\)
So \(GCF(25, \ 30) = 5\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(25, \ 30)=\dfrac{25 \times 30}{5}\)
Step 3: Divide first, then multiply: \(25 \div 5 = 5\), and \(5 \times 30 = \color{red}{150}\).
Greatest Common Factor of 25 and 30
8) \(LCM(28, \ 42) = \color{red}{84}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(28 = 2 \times 2 \times 7\)
\(42 = 2 \times 3 \times 7\)
So \(GCF(28, \ 42) = 14\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(28, \ 42)=\dfrac{28 \times 42}{14}\)
Step 3: Divide first, then multiply: \(28 \div 14 = 2\), and \(2 \times 42 = \color{red}{84}\).
Greatest Common Factor of 28 and 42
9) \(LCM(32, \ 48) = \color{red}{96}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(32 = 2 \times 2 \times 2 \times 2 \times 2\)
\(48 = 2 \times 2 \times 2 \times 2 \times 3\)
So \(GCF(32, \ 48) = 16\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(32, \ 48)=\dfrac{32 \times 48}{16}\)
Step 3: Divide first, then multiply: \(32 \div 16 = 2\), and \(2 \times 48 = \color{red}{96}\).
Greatest Common Factor of 32 and 48
10) \(LCM(36, \ 45) = \color{red}{180}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(36 = 2 \times 2 \times 3 \times 3\)
\(45 = 3 \times 3 \times 5\)
So \(GCF(36, \ 45) = 9\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(36, \ 45)=\dfrac{36 \times 45}{9}\)
Step 3: Divide first, then multiply: \(36 \div 9 = 4\), and \(4 \times 45 = \color{red}{180}\).
Greatest Common Factor of 36 and 45
11) \(LCM(40, \ 56) = \color{red}{280}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(40 = 2 \times 2 \times 2 \times 5\)
\(56 = 2 \times 2 \times 2 \times 7\)
So \(GCF(40, \ 56) = 8\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(40, \ 56)=\dfrac{40 \times 56}{8}\)
Step 3: Divide first, then multiply: \(40 \div 8 = 5\), and \(5 \times 56 = \color{red}{280}\).
Greatest Common Factor of 40 and 56
12) \(LCM(54, \ 72) = \color{red}{216}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(54 = 2 \times 3 \times 3 \times 3\)
\(72 = 2 \times 2 \times 2 \times 3 \times 3\)
So \(GCF(54, \ 72) = 18\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(54, \ 72)=\dfrac{54 \times 72}{18}\)
Step 3: Divide first, then multiply: \(54 \div 18 = 3\), and \(3 \times 72 = \color{red}{216}\).
Greatest Common Factor of 54 and 72
13) \(LCM(63, \ 84) = \color{red}{252}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(63 = 3 \times 3 \times 7\)
\(84 = 2 \times 2 \times 3 \times 7\)
So \(GCF(63, \ 84) = 21\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(63, \ 84)=\dfrac{63 \times 84}{21}\)
Step 3: Divide first, then multiply: \(63 \div 21 = 3\), and \(3 \times 84 = \color{red}{252}\).
Greatest Common Factor of 63 and 84
14) \(LCM(75, \ 90) = \color{red}{450}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(75 = 3 \times 5 \times 5\)
\(90 = 2 \times 3 \times 3 \times 5\)
So \(GCF(75, \ 90) = 15\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(75, \ 90)=\dfrac{75 \times 90}{15}\)
Step 3: Divide first, then multiply: \(75 \div 15 = 5\), and \(5 \times 90 = \color{red}{450}\).
Greatest Common Factor of 75 and 90
15) \(LCM(96, \ 120) = \color{red}{480}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(96 = 2 \times 2 \times 2 \times 2 \times 2 \times 3\)
\(120 = 2 \times 2 \times 2 \times 3 \times 5\)
So \(GCF(96, \ 120) = 24\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(96, \ 120)=\dfrac{96 \times 120}{24}\)
Step 3: Divide first, then multiply: \(96 \div 24 = 4\), and \(4 \times 120 = \color{red}{480}\).
Greatest Common Factor of 96 and 120
16) \(LCM(105, \ 140) = \color{red}{420}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(105 = 3 \times 5 \times 7\)
\(140 = 2 \times 2 \times 5 \times 7\)
So \(GCF(105, \ 140) = 35\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(105, \ 140)=\dfrac{105 \times 140}{35}\)
Step 3: Divide first, then multiply: \(105 \div 35 = 3\), and \(3 \times 140 = \color{red}{420}\).
Greatest Common Factor of 105 and 140
17) \(LCM(121, \ 132) = \color{red}{1452}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(121 = 11 \times 11\)
\(132 = 2 \times 2 \times 3 \times 11\)
So \(GCF(121, \ 132) = 11\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(121, \ 132)=\dfrac{121 \times 132}{11}\)
Step 3: Divide first, then multiply: \(121 \div 11 = 11\), and \(11 \times 132 = \color{red}{1452}\).
Greatest Common Factor of 121 and 132
18) \(LCM(144, \ 180) = \color{red}{720}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(144 = 2 \times 2 \times 2 \times 2 \times 3 \times 3\)
\(180 = 2 \times 2 \times 3 \times 3 \times 5\)
So \(GCF(144, \ 180) = 36\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(144, \ 180)=\dfrac{144 \times 180}{36}\)
Step 3: Divide first, then multiply: \(144 \div 36 = 4\), and \(4 \times 180 = \color{red}{720}\).
Greatest Common Factor of 144 and 180
19) \(LCM(168, \ 252) = \color{red}{504}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(168 = 2 \times 2 \times 2 \times 3 \times 7\)
\(252 = 2 \times 2 \times 3 \times 3 \times 7\)
So \(GCF(168, \ 252) = 84\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(168, \ 252)=\dfrac{168 \times 252}{84}\)
Step 3: Divide first, then multiply: \(168 \div 84 = 2\), and \(2 \times 252 = \color{red}{504}\).
Greatest Common Factor of 168 and 252
20) \(LCM(210, \ 330) = \color{red}{2310}\)
Solution:Step 1: Find the GCF so the repeated factors are counted only once.
\(210 = 2 \times 3 \times 5 \times 7\)
\(330 = 2 \times 3 \times 5 \times 11\)
So \(GCF(210, \ 330) = 30\).
Step 2: Use \(LCM(a,b)=\dfrac{a \times b}{GCF(a,b)}\).
\(LCM(210, \ 330)=\dfrac{210 \times 330}{30}\)
Step 3: Divide first, then multiply: \(210 \div 30 = 7\), and \(7 \times 330 = \color{red}{2310}\).
Greatest Common Factor of 210 and 330