1) \(1\frac{1}{4} + 2\frac{2}{4} = \color{red}{3\frac{3}{4}}\)
GCF(12,16) = 4
Solution:
Separate the whole-number and fraction parts: \((1 + 2) + (\frac{1}{4} + \frac{2}{4})\).
Use the common denominator \(16\): \(\frac{1}{4}=\frac{4}{16}\) and \(\frac{2}{4}=\frac{8}{16}\).
Compute the whole-number part: \(1+2=3\).
Compute the fraction part: \(\frac{4}{16} + \frac{8}{16}=\frac{12}{16}\), which simplifies to \(\frac{3}{4}\).
Combine the parts: \(3\frac{3}{4}\).
2) \(3\frac{1}{5} + 1\frac{2}{5} = \color{red}{4\frac{3}{5}}\)
GCF(15,25) = 5
Solution:
Separate the whole-number and fraction parts: \((3 + 1) + (\frac{1}{5} + \frac{2}{5})\).
Use the common denominator \(25\): \(\frac{1}{5}=\frac{5}{25}\) and \(\frac{2}{5}=\frac{10}{25}\).
Compute the whole-number part: \(3+1=4\).
Compute the fraction part: \(\frac{5}{25} + \frac{10}{25}=\frac{15}{25}\), which simplifies to \(\frac{3}{5}\).
Combine the parts: \(4\frac{3}{5}\).
3) \(2\frac{1}{3} + 4\frac{1}{6} = \color{red}{6\frac{1}{2}}\)
GCF(9,18) = 9
Solution:
Separate the whole-number and fraction parts: \((2 + 4) + (\frac{1}{3} + \frac{1}{6})\).
Use the common denominator \(18\): \(\frac{1}{3}=\frac{6}{18}\) and \(\frac{1}{6}=\frac{3}{18}\).
Compute the whole-number part: \(2+4=6\).
Compute the fraction part: \(\frac{6}{18} + \frac{3}{18}=\frac{9}{18}\), which simplifies to \(\frac{1}{2}\).
Combine the parts: \(6\frac{1}{2}\).
4) \(5\frac{2}{7} + 1\frac{3}{14} = \color{red}{6\frac{1}{2}}\)
GCF(49,98) = 49
Solution:
Separate the whole-number and fraction parts: \((5 + 1) + (\frac{2}{7} + \frac{3}{14})\).
Use the common denominator \(98\): \(\frac{2}{7}=\frac{28}{98}\) and \(\frac{3}{14}=\frac{21}{98}\).
Compute the whole-number part: \(5+1=6\).
Compute the fraction part: \(\frac{28}{98} + \frac{21}{98}=\frac{49}{98}\), which simplifies to \(\frac{1}{2}\).
Combine the parts: \(6\frac{1}{2}\).
5) \(4\frac{3}{8} + 2\frac{5}{8} = \color{red}{7}\)
GCF(64,64) = 64
Solution:
Separate the whole-number and fraction parts: \((4 + 2) + (\frac{3}{8} + \frac{5}{8})\).
Use the common denominator \(64\): \(\frac{3}{8}=\frac{24}{64}\) and \(\frac{5}{8}=\frac{40}{64}\).
Compute the whole-number part: \(4+2=6\).
Compute the fraction part: \(\frac{24}{64} + \frac{40}{64}=\frac{64}{64}\), which simplifies to \(\frac{1}{1}\). The fraction \(\frac{64}{64}\) equals \(1\), so regroup the extra whole number.
Combine the parts: \(7\).
6) \(6\frac{5}{12} + 3\frac{7}{18} = \color{red}{9\frac{29}{36}}\)
GCF(174,216) = 6
Solution:
Separate the whole-number and fraction parts: \((6 + 3) + (\frac{5}{12} + \frac{7}{18})\).
Use the common denominator \(216\): \(\frac{5}{12}=\frac{90}{216}\) and \(\frac{7}{18}=\frac{84}{216}\).
Compute the whole-number part: \(6+3=9\).
Compute the fraction part: \(\frac{90}{216} + \frac{84}{216}=\frac{174}{216}\), which simplifies to \(\frac{29}{36}\).
Combine the parts: \(9\frac{29}{36}\).
7) \(7\frac{3}{10} + 2\frac{4}{15} = \color{red}{9\frac{17}{30}}\)
GCF(85,150) = 5
Solution:
Separate the whole-number and fraction parts: \((7 + 2) + (\frac{3}{10} + \frac{4}{15})\).
Use the common denominator \(150\): \(\frac{3}{10}=\frac{45}{150}\) and \(\frac{4}{15}=\frac{40}{150}\).
Compute the whole-number part: \(7+2=9\).
Compute the fraction part: \(\frac{45}{150} + \frac{40}{150}=\frac{85}{150}\), which simplifies to \(\frac{17}{30}\).
Combine the parts: \(9\frac{17}{30}\).
8) \(5\frac{5}{6} + 4\frac{3}{4} = \color{red}{10\frac{7}{12}}\)
GCF(38,24) = 2
Solution:
Separate the whole-number and fraction parts: \((5 + 4) + (\frac{5}{6} + \frac{3}{4})\).
Use the common denominator \(24\): \(\frac{5}{6}=\frac{20}{24}\) and \(\frac{3}{4}=\frac{18}{24}\).
Compute the whole-number part: \(5+4=9\).
Compute the fraction part: \(\frac{20}{24} + \frac{18}{24}=\frac{38}{24}\), which simplifies to \(\frac{19}{12}\). The fraction \(\frac{38}{24}\) equals \(1\frac{7}{12}\), so regroup the extra whole number.
Combine the parts: \(10\frac{7}{12}\).
9) \(8\frac{7}{9} + 6\frac{5}{12} = \color{red}{15\frac{7}{36}}\)
GCF(129,108) = 3
Solution:
Separate the whole-number and fraction parts: \((8 + 6) + (\frac{7}{9} + \frac{5}{12})\).
Use the common denominator \(108\): \(\frac{7}{9}=\frac{84}{108}\) and \(\frac{5}{12}=\frac{45}{108}\).
Compute the whole-number part: \(8+6=14\).
Compute the fraction part: \(\frac{84}{108} + \frac{45}{108}=\frac{129}{108}\), which simplifies to \(\frac{43}{36}\). The fraction \(\frac{129}{108}\) equals \(1\frac{7}{36}\), so regroup the extra whole number.
Combine the parts: \(15\frac{7}{36}\).
10) \(9\frac{11}{15} + 3\frac{7}{10} = \color{red}{13\frac{13}{30}}\)
GCF(215,150) = 5
Solution:
Separate the whole-number and fraction parts: \((9 + 3) + (\frac{11}{15} + \frac{7}{10})\).
Use the common denominator \(150\): \(\frac{11}{15}=\frac{110}{150}\) and \(\frac{7}{10}=\frac{105}{150}\).
Compute the whole-number part: \(9+3=12\).
Compute the fraction part: \(\frac{110}{150} + \frac{105}{150}=\frac{215}{150}\), which simplifies to \(\frac{43}{30}\). The fraction \(\frac{215}{150}\) equals \(1\frac{13}{30}\), so regroup the extra whole number.
Combine the parts: \(13\frac{13}{30}\).
11) \(12\frac{5}{16} + 4\frac{7}{24} = \color{red}{16\frac{29}{48}}\)
GCF(232,384) = 8
Solution:
Separate the whole-number and fraction parts: \((12 + 4) + (\frac{5}{16} + \frac{7}{24})\).
Use the common denominator \(384\): \(\frac{5}{16}=\frac{120}{384}\) and \(\frac{7}{24}=\frac{112}{384}\).
Compute the whole-number part: \(12+4=16\).
Compute the fraction part: \(\frac{120}{384} + \frac{112}{384}=\frac{232}{384}\), which simplifies to \(\frac{29}{48}\).
Combine the parts: \(16\frac{29}{48}\).
12) \(10\frac{13}{18} + 8\frac{5}{6} = \color{red}{19\frac{5}{9}}\)
GCF(168,108) = 12
Solution:
Separate the whole-number and fraction parts: \((10 + 8) + (\frac{13}{18} + \frac{5}{6})\).
Use the common denominator \(108\): \(\frac{13}{18}=\frac{78}{108}\) and \(\frac{5}{6}=\frac{90}{108}\).
Compute the whole-number part: \(10+8=18\).
Compute the fraction part: \(\frac{78}{108} + \frac{90}{108}=\frac{168}{108}\), which simplifies to \(\frac{14}{9}\). The fraction \(\frac{168}{108}\) equals \(1\frac{5}{9}\), so regroup the extra whole number.
Combine the parts: \(19\frac{5}{9}\).
13) \(14\frac{9}{20} + 6\frac{11}{30} = \color{red}{20\frac{49}{60}}\)
GCF(490,600) = 10
Solution:
Separate the whole-number and fraction parts: \((14 + 6) + (\frac{9}{20} + \frac{11}{30})\).
Use the common denominator \(600\): \(\frac{9}{20}=\frac{270}{600}\) and \(\frac{11}{30}=\frac{220}{600}\).
Compute the whole-number part: \(14+6=20\).
Compute the fraction part: \(\frac{270}{600} + \frac{220}{600}=\frac{490}{600}\), which simplifies to \(\frac{49}{60}\).
Combine the parts: \(20\frac{49}{60}\).
14) \(15\frac{17}{24} + 9\frac{13}{36} = \color{red}{25\frac{5}{72}}\)
GCF(924,864) = 12
Solution:
Separate the whole-number and fraction parts: \((15 + 9) + (\frac{17}{24} + \frac{13}{36})\).
Use the common denominator \(864\): \(\frac{17}{24}=\frac{612}{864}\) and \(\frac{13}{36}=\frac{312}{864}\).
Compute the whole-number part: \(15+9=24\).
Compute the fraction part: \(\frac{612}{864} + \frac{312}{864}=\frac{924}{864}\), which simplifies to \(\frac{77}{72}\). The fraction \(\frac{924}{864}\) equals \(1\frac{5}{72}\), so regroup the extra whole number.
Combine the parts: \(25\frac{5}{72}\).
15) \(21\frac{19}{28} + 7\frac{15}{42} = \color{red}{29\frac{1}{28}}\)
GCF(1218,1176) = 42
Solution:
Separate the whole-number and fraction parts: \((21 + 7) + (\frac{19}{28} + \frac{15}{42})\).
Use the common denominator \(1176\): \(\frac{19}{28}=\frac{798}{1176}\) and \(\frac{15}{42}=\frac{420}{1176}\).
Compute the whole-number part: \(21+7=28\).
Compute the fraction part: \(\frac{798}{1176} + \frac{420}{1176}=\frac{1218}{1176}\), which simplifies to \(\frac{29}{28}\). The fraction \(\frac{1218}{1176}\) equals \(1\frac{1}{28}\), so regroup the extra whole number.
Combine the parts: \(29\frac{1}{28}\).
16) \(18\frac{23}{30} + 12\frac{7}{20} = \color{red}{31\frac{7}{60}}\)
GCF(670,600) = 10
Solution:
Separate the whole-number and fraction parts: \((18 + 12) + (\frac{23}{30} + \frac{7}{20})\).
Use the common denominator \(600\): \(\frac{23}{30}=\frac{460}{600}\) and \(\frac{7}{20}=\frac{210}{600}\).
Compute the whole-number part: \(18+12=30\).
Compute the fraction part: \(\frac{460}{600} + \frac{210}{600}=\frac{670}{600}\), which simplifies to \(\frac{67}{60}\). The fraction \(\frac{670}{600}\) equals \(1\frac{7}{60}\), so regroup the extra whole number.
Combine the parts: \(31\frac{7}{60}\).
17) \(25\frac{29}{40} + 16\frac{17}{32} = \color{red}{42\frac{41}{160}}\)
GCF(1608,1280) = 8
Solution:
Separate the whole-number and fraction parts: \((25 + 16) + (\frac{29}{40} + \frac{17}{32})\).
Use the common denominator \(1280\): \(\frac{29}{40}=\frac{928}{1280}\) and \(\frac{17}{32}=\frac{680}{1280}\).
Compute the whole-number part: \(25+16=41\).
Compute the fraction part: \(\frac{928}{1280} + \frac{680}{1280}=\frac{1608}{1280}\), which simplifies to \(\frac{201}{160}\). The fraction \(\frac{1608}{1280}\) equals \(1\frac{41}{160}\), so regroup the extra whole number.
Combine the parts: \(42\frac{41}{160}\).
18) \(31\frac{37}{45} + 22\frac{19}{60} = \color{red}{54\frac{5}{36}}\)
GCF(3075,2700) = 75
Solution:
Separate the whole-number and fraction parts: \((31 + 22) + (\frac{37}{45} + \frac{19}{60})\).
Use the common denominator \(2700\): \(\frac{37}{45}=\frac{2220}{2700}\) and \(\frac{19}{60}=\frac{855}{2700}\).
Compute the whole-number part: \(31+22=53\).
Compute the fraction part: \(\frac{2220}{2700} + \frac{855}{2700}=\frac{3075}{2700}\), which simplifies to \(\frac{41}{36}\). The fraction \(\frac{3075}{2700}\) equals \(1\frac{5}{36}\), so regroup the extra whole number.
Combine the parts: \(54\frac{5}{36}\).
19) \(44\frac{41}{56} + 18\frac{33}{70} = \color{red}{63\frac{57}{280}}\)
GCF(4718,3920) = 14
Solution:
Separate the whole-number and fraction parts: \((44 + 18) + (\frac{41}{56} + \frac{33}{70})\).
Use the common denominator \(3920\): \(\frac{41}{56}=\frac{2870}{3920}\) and \(\frac{33}{70}=\frac{1848}{3920}\).
Compute the whole-number part: \(44+18=62\).
Compute the fraction part: \(\frac{2870}{3920} + \frac{1848}{3920}=\frac{4718}{3920}\), which simplifies to \(\frac{337}{280}\). The fraction \(\frac{4718}{3920}\) equals \(1\frac{57}{280}\), so regroup the extra whole number.
Combine the parts: \(63\frac{57}{280}\).
20) \(63\frac{47}{72} + 29\frac{55}{96} = \color{red}{93\frac{65}{288}}\)
GCF(8472,6912) = 24
Solution:
Separate the whole-number and fraction parts: \((63 + 29) + (\frac{47}{72} + \frac{55}{96})\).
Use the common denominator \(6912\): \(\frac{47}{72}=\frac{4512}{6912}\) and \(\frac{55}{96}=\frac{3960}{6912}\).
Compute the whole-number part: \(63+29=92\).
Compute the fraction part: \(\frac{4512}{6912} + \frac{3960}{6912}=\frac{8472}{6912}\), which simplifies to \(\frac{353}{288}\). The fraction \(\frac{8472}{6912}\) equals \(1\frac{65}{288}\), so regroup the extra whole number.
Combine the parts: \(93\frac{65}{288}\).